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Published byCandace Upp Modified over 9 years ago
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Datorteknik DelayedLoad bild 1 Delayed Load
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Datorteknik DelayedLoad bild 2 All problems solved? NO, what will happen if...... lw $6 $0($1) add $4 $6 $1 add $7 $6 $2
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Datorteknik DelayedLoad bild 3 IM Reg DMReg Critical path “DM” to “EX” ? IM Reg DMReg IM Reg DMReg 0x30 lw $6 $0($1) 0x34 add $4 $6 $1 0x38 add $7 $6 $2
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Datorteknik DelayedLoad bild 4 Branch logic Sgn/Ze extend Zero ext. ALU A B 31 0 4 + + = = = = The Model We Use
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Datorteknik DelayedLoad bild 5 Fix or Not? The Critical path would be 2T (ALU+DM) Clockspeed only half WE CHOOSE NOT TO FIX
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Datorteknik DelayedLoad bild 6 Delayed Load One “delayed load” slot –lw $6 $0($1) –other useful operation, or nop –add $4 $6 $1 –add $7 $6 $4 Still better than NO forward –lw $6 $0($1) –other useful operation, or nop –add $4 $6 $1 –other useful operation, or nop –add $7 $6 $4
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Datorteknik DelayedLoad bild 7 Pipeline Efficiency Critical path cut to 1/4 Can we do the same with only three stages?
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Datorteknik DelayedLoad bild 8 IM Reg DMReg 4 Stage Pipe IM Reg DM Reg 3 Stage Pipe
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Datorteknik DelayedLoad bild 9 Branch logic Sgn/Ze extend Zero ext. ALU A B 31 0 4 + + = = = = 4 Stage Pipe
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Datorteknik DelayedLoad bild 10 Branch logic Sgn/Ze extend Zero ext. ALU A B 31 0 4 + + = = = =
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Datorteknik DelayedLoad bild 11 Critical Path? ALU + DM No, it’s too long, no can do!
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Datorteknik DelayedLoad bild 12 Branch logic Sgn/Ze extend Zero ext. ALU A B 31 0 4 + + = = = =
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Datorteknik DelayedLoad bild 13 What about the instruction set? lw $t2 4($t4)? NO, ALU is not in path lw $t2 $t4? OK, No need for ALU
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Datorteknik DelayedLoad bild 14 Avoid Delayed Load? Yes, by moving DM to EX, we can forward the result
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Datorteknik DelayedLoad bild 15 Different Pipelength/depth Is it possible to implement both version in one structure (MIPS pipe). NO! There might be collisions, both EX, and DM accesses memory at the same time.
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Datorteknik DelayedLoad bild 16 Pipeline Efficiency Did we change the critical path? NO!, ALU and DM are not in sequence
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