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BALMERSERIEN n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV.

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Presentation on theme: "BALMERSERIEN n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV."— Presentation transcript:

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2 BALMERSERIEN

3 n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV

4 HH n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV

5 HH n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV

6 HH n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV

7 HH n = 1 n = 2 n = 3 n = 4 n = 5 -13,6 eV -3,39 eV -1,51 eV -0,85 eV

8 LymanBalmerPaschenLymanBalmerPaschen

9 n = 1 n = 2 n = 3 n = 4 n = 5 2000 1000500 100 nm

10 100 n = 1 n = 2 n = 3 n = 4 n = 5 2000 1000500 nm 100 Lyman

11 100 n = 1 n = 2 n = 3 n = 4 n = 5 2000 1000500 nm 100 500 Lyman Balmer

12 100 n = 1 n = 2 n = 3 n = 4 n = 5 1000500 nm 100 5001000 2000 Lyman BalmerPaschen

13 100 n = 1 n = 2 n = 3 n = 4 n = 5 1000500 nm 100 500 Lyman BalmerPaschen 1000 2000

14 Bohrs atommodell H  - linjen

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