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1 Mendelian Inheritance Part 1 BIO 2215 Oklahoma City Community College Dennis Anderson
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2 Gregor Mendel Father of Genetics 1823-1884 Monk in Austria Experimented with garden peas
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3 Short Tall
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4 Mendel’s Hypotheses Each parent has two factors (alleles) Each parent gives one of those factors to the offspring Tall has TT Short has tt Tall is dominant Short is recessive
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5 TTtt T t Tt
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6 TT T T
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7 tt t t
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8 Law of Segregation Alleles separate during gamete production Gametes have one allele for each trait During fertilization gametes combine at random to form individuals of the next generation
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9 Discovery of Chromosomes in 1900 Confirmed Law of Segregation Chromosomes are in pairs Each chromosome has one of the allele pair
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10 Chromosomes line up in a double row. Meiosis Metaphase Assume a T allele on each red chromatid and a t allele on each blue chromatid TTtt
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11 Chromosomes separate Each each daughter cell gets doubled chromosomes TT tt
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12 Doubled Chromosomes Separate in Second Meiotic Division TT tt
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13 Each gamete will have a T allele or a t allele TTtt
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14 Allele Member of a paired gene –One allele comes from each parent Represented by a single letter
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15 Dominant & Recessive Alleles Dominant alleles are expressed Recessive alleles are not expressed in the presence of a dominant allele –Recessive alleles are only expressed if both recessive alleles are present
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16 Gene A unit of heredity that controls the development of one trait Made of DNA Most genes are composed of two alleles
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17 Homozygous Both alleles alike AA or aa
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18 Heterozygous Alleles are different Aa
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19 Genotype Genetic make up Represented by alleles TT & Tt are genotypes for tall pea plants
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20 Phenotype A trait Genotype determines the phenotype Tall is a phenotype
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21 Homologous Chromosomes Chromosomes of the same pair Each homologue will have one allele for a paired gene Homologous chromosomes pair up during meiosis Only one of each homologue will be in each gamete
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22 Sickle Cell Anemia RBCs sickle shaped Anemia Pain Stroke Leg ulcers Jaundice Gall stones Spleen, kidney & lungs
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23 Sickle Cell Anemia Recessive allele s, codes for hemoglobin S –Long rod-like molecules –Stretches RBC into sickle shape Homozygous recessive ss, have sickle cell anemia Heterozygous Ss, are carriers
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24 Albinism Lack of pigment –Skin –Hair –Eyes
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25 Amino AcidsMelanin Pigment Enzyme A a AA = Normal pigmentation Aa = Normal pigmentation aa = Albino
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26 PKU Disease Phenylalanine excess Mental retardation if untreated
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27 PhenylalanineTyrosine Enzyme P p PP = Normal Pp = Normal pp = PKU
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28 A man & woman are both carriers (heterozygous) for albinism. What is the chance their children will inherit albinism? Monohybrid Cross or One Trait
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29 AA = Normal pigmentation Aa = Normal pigmentation (carrier) aa = Albino Man = AaWoman = Aa A a a A
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30 A a a A AA Aa aa
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31 AA Aa aa Genotypes 1 AA, 2Aa, 1aa Phenotypes 3 Normal 1 Abino Probability 25% for albinism
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32 A man & woman are both carriers (heterozygous) for PKU disease. What is the chance their children will inherit PKU disease?
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33 p p P PP PpPp PpPp pp P PP = Normal Pp = Normal (carrier) pp = PKU disease
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34 PP Pp pp Genotypes 1 PP, 2Pp, 1pp Phenotypes 3 Normal 1 PKU disease Probability 25% for PKU disease
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35 A man with sickle cell anemia marries a woman who is a carrier. What is the chance their children will inherit sickle cell anemia?
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36 s s s Ss ss S SS = Normal Ss = Normal (carrier) ss = Sickle Cell
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37 Ss ss Genotypes 2 Ss, 2ss Phenotypes 2 Normal (carriers) 2 Sickle cell Probability 50% for Sickle cell
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38 Dwarfism = D Normal height = d DD = Dwarfism Dd = Dwarfism dd = Normal height Dwarfism Dwarf Band
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39 A man with heterozygous dwarfism marries a woman who has normal height. What is the chance their children will inherit dwarfism? Dwarfism is dominant.
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40 d d D Dd dd Dd dd d DD = Dwarf Dd = Dwarf dd = Normal
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41 Dd dd Dd dd Genotypes 2 Dd, 2dd Phenotypes 2 Normal 2 Dwarfs Probability 50% for Dwarfism
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42 Law of Independent Assortment The inheritance of one gene does not influence the inheritance of another gene if they are on separate chromosomes. The gene for albinism does not affect the gene for dwarfism
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43 Dihybrid Cross or Two Traits A heterozygous tall plant that is also heterozygous for yellow seeds is crossed with another plant with the same genotype Tall and yellow seeds are dominant to short and green seeds.
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44 Tall Yellow TtYy TY What gametes can each parent produce? Ty tY ty TtYy TY Ty tY ty Tall Yellow
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45 9 Tall-Yellow Match gametes on a Punnent Square TY Ty tY ty TYTytYty TtYy TTYYTTYyTtYY TTYyTTyyTtyy TtYYTtYyttYYttYy TtYyTtyyttYyttyy 3 Tall-Green 3 Short-Yellow 1 Short-Green
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46 A man with blue eyes and normal height marries a woman with heterozygous brown eyes and heterozygous dwarfism. What are the possible phenotypes of their children? Dwarfism & brown eyes are dominant.
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47 Normal height-Blue ddbb db What gametes can each parent produce? DdBb DB Db dB db Dwarf-Brown
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48 DB Db dB db Match gametes on Punnent Square db DdBb Ddbb ddBb ddbb Dwarf-Brown eyes Dwarf-blue eyes Normal height-Brown eyes Normal height-Blue eyes
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49 X-linked Traits Alleles on the X chromosome Women have two alleles Men have one allele
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50 Hemophilia Blood clotting impaired Recessive allele, h carried on X cms X-linked recessive trait More common in males
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51 X H X H = Normal Female X H X h = Normal Female (Carrier) X h X h = Hemophiliac Female X H y = Normal Male X h y = Hemophiliac Male Alleles must be written on X chromosome
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52 A man with hemophilia marries a normal woman who is not a carrier. What is the chance their children will inherit hemophilia? Hemophilia is X-linked recessive.
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53 y XHXH XhXh X H X h XHXH X H X H = Normal Female X H X h = Normal Female (Carrier) X h X h = Hemophiliac Female X H y = Normal Male X h y = Hemophiliac Male X H X h XHyXHy XHyXHy
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54 Genotypes 2 X H X h, 2 X H y Phenotypes 2 Carrier Females 2 Normal Males Probability O% for Hemophilia y XHXH XhXh X H X h XHXH XHyXHy XHyXHy
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55 A normal man marries a normal woman who is a carrier for hemophilia. What is the chance their children will inherit hemophilia?
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56 y XhXh XHXH XHXH X H X H = Normal Female X H X h = Normal Female (Carrier) X h X h = Hemophiliac Female X H y = Normal Male X h y = Hemophiliac Male X H X H X h XHyXHy XhyXhy
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57 Genotypes 1X H X H, 1 X H X h, 1X H y, 1 X h y Phenotypes 2 Normal Females 1 Normal Males 1 Male Hemophiliac Probability 50% for Male Hemophiliac 0% for Female Hemophiliac y XhXh XHXH X H XHXH X H X h XHyXHy XhyXhy
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58 Hypertrichosis X-linked dominant Similar gene in apes
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59 The End
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