Download presentation
Presentation is loading. Please wait.
Published byChris Henley Modified over 9 years ago
1
Laser Physics EAL 501 Lecture 6 Power & Frequency
2
We said that there are two types of cavities 1- Ring cavities
5
Standing wave cavities 1- Longitudenal modes due to standing waves Do ring lasers have longitudenal modes?
7
2-Transversal modes [Gaussian beams] The electric field distribution in the x-y plane Satisfy the wave eq. The Fresnel-Kirchoff’s theory states that “if we know the field distribution at a plan 1 (x 1,y 1,z 1 ) then the distribution at any plane (x,y,z) is given by We can write Where The solution is
8
Higher order modes are given by
9
Gaussian Beams The solution of wave equation can be plane waves But it is not real q(z) is the complex beam parameter of the beam
11
Amplitude factor Transverse phase factor Longitudenal phase factor Rayleigh range Beam waist Radius of curvature
14
Gain Saturation We drive the rate equations
15
The steady state solution of the rate equation in the case I=0 gives us the threshold condition The steady state solution of the rate equation in the case after the threshold can be shown to be
16
Steady state under threshold solution is In case of 3 level laser In case of 4 level laser
17
Solution above threshold in the case of two levels without pumping
18
Solution above threshold in the case of 3levels with pumping Since g(ν)=σ(v)(N 2 -N 1 ) then we can write Problem : find small signal gain and saturation intensity for 4 level laser
19
Hole burning 1.Spatial hole burning 2.Spectral hole burning 1- Spatial hole burning in the case of standing wave cavity there are points of zero intensity and points of max. intensity which depletes the gain much more rapidly 2- Spectral hole burning in the case of inhomogeneous broadening the atoms that feed the laser modes will be depleted much more rapidly
20
Output power Usually only one mirror produces output and if the mirror reflection is high Where s is the scattering losses The condition of steady state lasing
21
It is easy to find the value of transmission t to get the maximum output So the optimum output intensity is
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.