1. Limiting Reactant A.K.A. Stoichiometry

2.  One reactant remains while the other is consumed in a reaction  Mole ratio will help determine the limiting reaction  Need to create a conversion pathway How do we determine which reactant limits the product?

3. How Do Hot Fudge Sundaes and Limiting Reactants Relate?

4. How Many Sundaes Can You Make?

5. Two! The chocolate syrup limits the recipe!

6.  Which reactant remains when 6.70 mole Na reacts with 3.2o moles of Cl 2  2 Na + Cl 2  2 NaCl Which reactant is the limiting reactant? Step 1 Moles of reactant Moles of product

7. Moles of NaMole RatioMoles of NaCl 6.70 moles of Na2 mol NaCl= 6.70 mol NaCl 2 mol Na 2 Na + Cl 2  2 NaCl Moles of Cl 2 Mole RatioMoles of Product 3.20 moles of Cl 2 2 mol NaCl= 6.40 mol NaCl 1 mol Cl 2 Step 1 Cl 2 is the Limiting Reactant!

8. Limiting Reactant Worksheet It’s Your Turn…

9.  Which reactant is the limiting reactant when 3.5 g Cu reacts with 6.0 g AgNO 3?  Cu + AgNO 3  Cu(NO 3 ) 2 + Ag; balanced?  Cu + 2 AgNO 3  Cu(NO 3 ) 2 + 2 Ag Limiting Reactant and Mass-Mass Conversions

10.  We have 3.5 g Cu and 6.0 g AgNO 3 Create a Conversion Pathway Cu + 2 AgNO 3  Cu(NO 3 ) 2 + 2 Ag Step 1 Mass of Reactant Moles of Reactant Step 2 Moles of Product Step 3 Mass of Product

11. Mass of CuMolar Mass of Cu Mole RatioMolar Mass of Ag Mass of Ag 3.5 g Cu1 mol Cu2 mol Ag108 g Ag= 12 g Ag 63.5 g Cu1 mol Cu1 mol Ag Cu + 2 AgNO 3  Cu(NO 3 ) 2 + 2 Ag Mass of AgNO 3 Molar Mass of AgNO 3 Mole RatioMolar Mass of Ag Mass of Ag 6.0 g AgNO 3 1 mol AgNO 3 2 mol Ag108 g Ag= 3.8 g Ag 169.9 g AgNO 3 2 mol AgNO 3 1 mol Ag Silver nitrate is the limiting reactant!

12.  Read pp. 257-258  Answer problems pg. 263: 45 Homework