1. Limiting Reactant

2. + ? 2B + S ?

23. +

24. + 2B + S B 2 S

25. + 2B + 1S 1B 2 S Bread (B) and Salami (S) react in a 2 to 1 (2:1) ratio to produce sandwich (B 2 S)‏

26. + 6B + 2S ?

45. + + (leftover)‏

46. 6B + 2S + 2B 2 S

47. 6B + 2S + 2B 2 S The amount of salami limits the amount of sandwiches that can be produced

48. what reaction could this be?

83. 2H 2 + 1 O 2 2H 2 O

84. ? what happens if there is an excess amount of hydrogen?

114. ?

115. ?

116. ? 5H 2 + 1 O 2 2H 2 O+ 3H 2

117. ? excess H 2 + 1 O 2 2H 2 O

118. Limiting Reactant  The limiting reactant is the reactant you run out of first.  The excess reactant is the one you have left over.  The limiting reactant determines how much product you can make

119. Calculating Limiting Reactant  Do two stoichiometry problems.  The one that makes the least product is the limiting reagent.  For example  Copper reacts with sulfur to form copper ( I ) sulfide. If 10.6 g of copper reacts with 3.83 g S how much product will be formed?

120.  If 10.6 g of copper reacts with 3.83 g S. How many grams of product will be formed?  2Cu + S → Cu 2 S 10.6 g Cu 63.55g Cu 1 mol Cu 2 mol Cu 1 mol Cu 2 S 1 mol Cu 2 S 159.16 g Cu 2 S = 13.3 g Cu 2 S 3.83 g S 32.06g S 1 mol S 1 S 1 Cu 2 S 1 mol Cu 2 S 159.16 g Cu 2 S = 19.0 g Cu 2 S = 13.3 g Cu 2 S Cu is Limiting Reagent

121. Your turn Mg + 2HCl → MgCl 2 + H 2  If 10.1 g of magnesium and 2.87 g of HCl gas are reacted  a) what is the limiting reactant?  b) how many grams of hydrogen gas will be produced?

122. Your Turn II 2Al + 3CuSO 4 → Al 2 (SO 4 ) 3 + 3Cu  If 10.3 g of aluminum are reacted with 51.7 g of CuSO 4  a) what is the limiting reactant?  b) how much copper will be produced?