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Limiting Reactant A.K.A. Stoichiometry.  One reactant remains while the other is consumed in a reaction  Mole ratio will help determine the limiting.

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Presentation on theme: "Limiting Reactant A.K.A. Stoichiometry.  One reactant remains while the other is consumed in a reaction  Mole ratio will help determine the limiting."— Presentation transcript:

1 Limiting Reactant A.K.A. Stoichiometry

2  One reactant remains while the other is consumed in a reaction  Mole ratio will help determine the limiting reaction  Need to create a conversion pathway How do we determine which reactant limits the product?

3  Which reactant remains when 6.70 mole Na reacts with 3.2o moles of Cl 2  2 Na + Cl 2  2 NaCl Which reactant is the limiting reactant? Step 1 Moles of reactant Moles of product

4 Moles of NaMole RatioMoles of NaCl 6.70 moles of Na2 mol NaCl= 6.70 mol NaCl 2 mol Na 2 Na + Cl 2  2 NaCl Moles of Cl 2 Mole RatioMoles of Product 3.20 moles of Cl 2 2 mol NaCl= 6.40 mol NaCl 1 mol Cl 2 Step 1 Cl 2 is the Limiting Reactant!

5  Which reactant is the limiting reactant when 3.5 g Cu reacts with 6.0 g AgNO 3?  Cu + AgNO 3  Cu(NO 3 ) 2 + Ag; balanced?  Cu + 2 AgNO 3  Cu(NO 3 ) 2 + 2 Ag Limiting Reactant and Mass-Mass Conversions

6  We have 3.5 g Cu and 6.0 g AgNO 3 Create a Conversion Pathway Cu + 2 AgNO 3  Cu(NO 3 ) 2 + 2 Ag Step 1 Mass of Reactant Moles of Reactant Step 2 Moles of Product Step 3 Mass of Product

7 Mass of CuMolar Mass of Cu Mole RatioMolar Mass of Ag Mass of Ag 3.5 g Cu1 mol Cu2 mol Ag108 g Ag= 12 g Ag 63.5 g Cu1 mol Cu1 mol Ag Cu + 2 AgNO 3  Cu(NO 3 ) 2 + 2 Ag Mass of AgNO 3 Molar Mass of AgNO 3 Mole RatioMolar Mass of Ag Mass of Ag 6.0 g AgNO 3 1 mol AgNO 3 2 mol Ag108 g Ag= 3.8 g Ag 169.9 g AgNO 3 2 mol AgNO 3 1 mol Ag Silver nitrate is the limiting reactant!

8  Limiting Reactant Applet  With a partner, follow directions on worksheet and answer problems Your Turn…

9  Read pp. 257-258  Answer problems 33, 35, 37, 39, 45 Homework


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