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Polar Molecular Compounds SWBAT: Identify Polar and Nonpolar Molecules
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Periodic Table Trends Atomic Radii Half the distance between the nuclei of two adjacent atoms Electronegativity Ability of an atom to attract electrons when bonded with another atom
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Atomic Radii Trend
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Electronegativity Trend Electronegativity is highest within the nonmetals with Fluorine having the highest. Why are noble gases excluded?
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Electronegativity Trend
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A.Three Types of Bonds: non-polar, polar, ionic Use Electronegativity (EN) values to determine type of bond EN value: H = 2.1 C = 2.5 N = 3.0 O = 3.5 F = 4.0 P = 2.1 S = 2.5 Cl = 3.0 Br = 2.8 I = 2.5 Every element has a specific EN value We will focus on the elements of organic chemistry C,H,N,O,P,S and Halogens Do not need to memorize
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Electronegativity Difference and type of bond
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Rating of Covalent Bonds: Example 1: What type of bond is H-Cl? EN: H = 2.1 Cl: 3.0 Subtract ENs from each other, larger – smaller 3.0 – 2.1 = 0.9 compare to rating Redraw compound with partial charges: δ+ & δ- δ+ δ- H – Cl Dipole Moment 0 -.4 = nonpolar.5 – 1.7 = polar 1.8 and greater = ionic *Polar Covalent 0 -.4 = nonpolar.5 – 1.7 = polar 1.8 and greater = ionic
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Rating of Covalent Bonds: Example 1: What type of bond is H-Br? EN: H = 2.1 Br: 2.8 Subtract ENs from each other, larger – smaller 2.8 – 2.1 = 0.7 compare to rating Redraw compound with partial charges: δ+ & δ- δ+ δ- H – Br Dipole Moment 0 -.4 = nonpolar.5 – 1.7 = polar 1.8 and greater = ionic *Polar Covalent 0 -.4 = nonpolar.5 – 1.7 = polar 1.8 and greater = ionic
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Rating of Covalent Bonds: Example 2: What type of bond is C-H? EN: H = 2.1 C: 2.5 Subtract ENs from each other, larger – smaller 2.5 – 2.1 = 0.4 compare to rating Less than 0.5 = no partial charges, no dipole arrow C – H 0 -.4 = nonpolar.5 – 1.7 = polar 1.8 and greater = ionic *Nonpolar Covalent 0 -.4 = nonpolar.5 – 1.7 = polar 1.8 and greater = ionic
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Tips Bonds between different elements always have some kind of dipole moment regardless of polarity rating Draw the dipole arrow of Br – Pd (use just their position in the PT) Br – Pd Bonds between same elements never have a dipole moment regardless of individual EN No dipole between F – F or H – H
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Practice Problems Using electronegativity difference, classify each bond as ionic, polar covalent, or nonpolar covalent. Show the partial charge for any polar covalent bonds. K – F EN values: K = 0.8 & F = 4.0 O – O EN values: O = 3.5 I – Cl EN values: I = 2.5, & Cl = 3.0
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Practice Problems Using electronegativity difference, classify each bond as ionic, polar covalent, or nonpolar covalent. Show the partial charge for any polar covalent bonds. K – F EN values: K = 0.8 & F = 4.0 4.0 - 0.8 = 3.2 - ionic bond O – O EN values: O = 3.5 3.5 - 3.5 = 0 - nonpolar covalent bond I – Cl EN values: I = 2.5 & Cl = 3.0 3.0 - 2.5 = 0.5 - polar covalent bond δ+ δ- I – Cl
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Practice Problems The bonds between the following pairs of elements are covalent. Arrange them according to polarity, listing the most polar first. a. H – Cl b. H – C c. H – F d. H – O e. H – H f. S – Cl
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Homework Problems 4.50 Describe the end in EN going down a group. 4.52 Approximately what EN difference would you expect for a polar covalent bond? 4.54 Predict whether each of the following bonds is ionic, polar covalent or nonpolar covalent: A. Si-O B. K-Cl C. S-F D. P-Br E. Li-O F. N-P 4.56 For each of the following bonds, indicate the positive end with δ+ and the negative end with δ-. Write an arrow to show the dipole for each. A. Si-Br B. Se-F C. Br-F D. N-H E. N-P
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