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Particle Reactions and Decays - I [Secs 16.1, 16.2 Dunlap]
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CAN IT HAPPEN ? Check B, L i, Qc No Yes IS IT WEAK? T, S, C violation ? Yes WEAK W +, or W - involved. Flavor change occurs with one unit of charge change. QUARKS LINK UP? γ in products Yes No REACTION DECAY enough energy Q>0 Q<0 No STRONG No ? Yes ? E.M.
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Classification of Decays NoType of DecayParticlesGuage BosonsExample 1 Leptonic decay lepton leptons weak 2 Hadronic lepton decay lepton lepton+hadron weak 3 Hadronic decay hadron hadrons strong 4 Nonleptonic hadron decay hadron hadrons strong+ weak 5 Semileptonic hadron decay hadron hadron+leptons weak 6 Leptonic hadron decay hadron leptons weak 7 Electromagnetic hadron decay hadron hadron+photon EM TO LEPTONS TO HADRONS
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LEPTON DECAYS (i.e. decay into leptons) LEPTONIC DECAY HADRONIC – LEPTON DECAY
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HADRONIC DECAYS HADRONIC DECAY LEPTONIC HADRON DECAY SEMI-LEPTONIC HADRON DECAY NON-LEPTONIC HADRON DECAY ELECTROMAGNETIC HADRON DECAY
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In 1963 The UFI is back In 1963 theoretical physicist Nicolo Cabibbo gave an explanation in terms of quark state mixing and introduced an angle - The Cabibbo angle The quarks can exist either as eigenstates of the WEAK interaction or the STRONG interaction. Indeed it is best to think of the QUARKS as being fundamentally having FLAVOR STATES determined via the WEAK interaction. Then comes along the STRONG interaction which MIXES these flavors into.
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How the Quark Mixing works θcθc θcθc After switching on the STRONG interaction – these are the new quark states. The Cabibbo Angle turns out to be ~15 °
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Cabbibo allowed – Cabibbo Surpressed Cabibbo Allowed Cabibbo Surpressed ddsdds dusdus ddsdds dduddu
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W+W+ u d W+W+ u s K+K+ MEASURING THE CABIBBO ANGLE
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Example 1 BETA MINUS DECAY All the primary conservation laws (above the line) are ok, so the reaction should go. But is it S, W, or EM? There are two things that indicate the primary classification is WEAK. These are (i) the fact that this T of the final state is N.D (not defined) and (ii) the fact that leptons are present in the final state. Having established that it is a W (weak) decay we then make the inference: WEAK DECAY INVOLVEMENT OF “W” PARTICLE
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Example 1 BETA MINUS DECAY FEYNMAN DIAGRAM CLASSIFICATION = Semileptonic Hadron Decay
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Example 2 ASSOCIATED PRODUCTION All the primary conservation laws (above the line) are ok. Also the secondary conservation laws (obeyed by the strong interaction, ones below the line) are ok. This means the reaction must be mediated by the STRONG force. There will be NO Ws All quarks will “link up”.
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Example 2 ASSOCIATED PRODUCTION FEYNMAN DIAGRAM CLASSIFICATION = PURE HADRONIC
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Example 3 K- MESON DECAY All the primary conservation laws (above the line) are ok. But here the secondary conservation laws (obeyed by the strong interaction, ones below the line) are NOT OK. This is a clear indication that this cannot be a strong process. The presence of leptons also confirms that this must be a WEAK interaction process. the presence of W particles.
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Example 3 K- MESON DECAY FEYNMAN DIAGRAM DECAY CLASSIFICATION = LEPTONIC HADRON DECAY
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Example 4 LAMDA ZERO DECAY As with the K+ decay we see failure on isospin and strangeness. Again this is clear indication that the WEAK interaction is responsible. [We saw in the lecture on strangeness that a strong interaction could only occur if the strange quark that had been produced could find another strange quark for pairing up with – and annihilating with] W PARTICLE involved in FLAVOR changing
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Example 4 LAMDA ZERO DECAY FEYNMAN DIAGRAM DECAY CLASSIFICATION = Nonleptonic Hadron decay
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Example 5 DELTA ++ PRODUCTION So all is OK for an allowed reaction and one going by the STRONG interaction. This a fully hadronic process.
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Example 5 DELTA ++ PRODUCTION FEYNMAN DIAGRAM CLASSIFICATION = Hadronic Reaction
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Example 6 D ZERO DECAY All is ok above the line – so the process is possible. Below the line we see a violation of strangeness and charm. Thus it looks as if we have a charmed quark changing into a strange quark. Involvement of a W boson. This is a WEAK process.
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Example 6 D ZERO DECAY FEYNMAN DIAGRAM DECAY CLASSIFICATION = Nonleptonic Hadron decay
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Example 7 D ZERO DECAY We see again an allowed decay but one which involves flavor changing on a quark. Here, however the presence of leptons in the final state makes finding the Feynman diagram easy.
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Example 7 D ZERO DECAY FEYNMAN DIAGRAM DECAY CLASSIFICATION = Semileptonic Hadron decay
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Example 8
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