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Non compartmental analysis
Update: 13/08/2010
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Statistical Moment Approach
Stochastic interpretation Individual particles are assumed to move independently among kinetic spaces according to fixed transfert probabilities The behaviour of drug particles is described by the statistical moments
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Statistical Moment Approach
! Synonymous Model-independent approach Non-compartmental analysis
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The Main Non-compartmental Parameters
Clearance = Dose / AUC Vss = MRT = Vss / Cl = AUMC / AUC F% = AUC EV / AUC IV DEV = DIV Dose x AUMC AUC2
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The Mean Residence Time
(MRT system)
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Non-compartmental analysis
Principle of the method: (1) Entry To measure the time each molecule stays in the system: t1, t2, t3...tn MRT = mean of the different times MRT = t1 + t2 + t3 +...tn n Exit
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Non-compartmental analysis
Principle of the method rate of absorption 2 balls / s 2 balls / s Clearance = flow = 2 balls/second MRT = t = (t1 + t2... t6)/n = ( …+6)/6 = 3 Vss = Clearance x MRT = 6 balls Tube volume x R2 x L = x R2 x 12R Ball volume (6 x 4R3)/3 Ratio Vballe/ Vtube = 0.67 = partition coefficient between balls and tube
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Mean Residence Time Principle of the method : (2)
The random variable (RV) is the presence time in the system This random variable is characterized by its mean (MRT) and its variance (VRT) The plasma concentration curve provides this information under minimal assumptions
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Non-compartmental analysis
Principle of the method: (3) Administration of No molecules at t=0 AUCtot will be proportional to No The molecules eliminated at t1 had a sojourn time of t1 in the system Number of molecules eliminated at t1 : C C1 C(t1) x t AUCtot t1 (t) x No
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Non-compartmental analysis
Principle of the method: (4) Cumulated sojourn times of molecule which has been eliminated during t at : C C1 C1 x t AUCTOT t1 : t1 x x No tn : tn x x No Cn Cn x t AUCTOT (t) t1 tn C1 x t x No Cn x t x No MRT= t1x tn x No AUCTOT AUCTOT MRT = ti x Ci x t / AUCTOT = t C(t) t / C(t) t
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Non-compartmental analysis
Requirements to compute MRT
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Central compartment (measure)
Mean Residence Time Principle of the method: (5) Entry (exogenous, endogenous) Central compartment (measure) recirculation exchanges Exit (single) : excretion, metabolism Only one exit from the measurement compartment First-order elimination : linearity
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Non-compartmental analysis
Principle of the method: (6) 1 2 2 exit sites MRT is not computable by statistical moments applied to plasma concentration
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Computation Method Non-compartmental analysis
Trapezes Fitting to a polyexponential equation Equation parameters : Yi, li Assuming a compartmental model Model parameters : kij
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Non-compartmental analysis
Computation method (1) The 3 statistical moments S0 = (ti - ti-1) (Ci + Ci-1) / 2 = AUC S1 = (ti - ti-1) (Ci x ti + Ci x ti -1) / 2 = AUMC S2 = (ti - ti-1) (Ci x ti + Ci x ti -1) / 2 = AUMMC AUC = S0 MRT = S1 / S0 VRT = S2 / S0 - (S1 - S0)2 2 2
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Non-compartmental analysis
Computation method (2) The 3 centered moments (normalized in relation to the origin) AUC = C(t) x dt MRT = t x C(t) x dt / C(t) x dt VRT = (t - MRT)2 x C(t) x dt / C(t) x dt
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Non-compartmental analysis
Computation method (3) S0 by the arithmetic trapezoidal rule C0 +C1 C0 AUC1 = x (t1 - t0) 2 C1 extrapolation area C2 C3 AUC1 AUC2 AUC3 t0 t1 t2 t3 AUCTOT = S1 = AUC1 + AUC2 ... AUCn + extrapolation area
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Non-compartmental analysis
Computation method (4) Computation of S1 = AUMC with the arithmetic trapezoidal rule t0 x C0 + t1 x C1 C0 AUMC1 = x (t1-t0) 2 C1 area to extrapolate C2 C3 AUMC1 AUMC2 AUMC3 t0 t1 t2 t3 AUMCTOT = S2 = AUMC1 + AUMC AUMC extrapolated
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Non-compartmental analysis
Computation method (5) How to extrapolate S0 : Cz / 2 S1 : tz x Cz / z + Cz / 2 S2 : t2z Cz / z + 2tz Cz / z + 2Cz/z Cz : the last measured concentration at tz Problem with z et z 2 2 3 2 3
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Non-compartmental analysis
Computation method (6) From the parameters of a given model S0 = Yi / i S1 = Yi /i S2 = 2Yi /i n i =1 n 2 i =1 n 3 i =1
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Non-compartmental analysis
Computation method (7) Bicompartmental model : C(t) = Y1 exp(-1t) + Y2 exp(-2t) MRTsystem = Y1/1 + Y2 / 2 2 2 Y1/1 + Y2 / 2
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Non-compartmental analysis
Principle of the method: MRT = t x C(t) x t C(t) x t MRT = t C(t) dt C(t) dt
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MRT system: interpretation
Monocompartmental model (IV) t1/2 : time to eliminate 50% of the molecules MRT : time to eliminate 63.2% of the molecules MRT = 1/ K10 t1/2 = MRT
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MRT system: interpretation
Multicompartmental model terminal half-life vs MRT MRT = 16 h Concentration MRT = 4 h t1/2 = 12 h temps (h)
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MRT system Comparison of published results Y1/1 + Y2 / 2 2 2
Author 1 : bicompartmental model: t1/2 = 6h Author 2 : tricompartmental model: t1/2 = 18h Solution : a posteriori computation of MRTsystem MRT bicompartmental MRT tricompartmental Y1/1 + Y2 / 2 2 2 Y1/1 + Y2 / 2 + Y3 / 3 2 2 2 ? = Y1/1 + Y2 / 2 Y1/1 + Y2 / 2 + Y3 / 3
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The Mean Absorption Time (MAT)
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The MAT Definition : mean time for the arrival of bioavailable drug 1
Ka MAT K10 F = 100% Administration 1 MAT = Ka
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The MAT How to evaluate the MAT 1- IV administration MRTIV = 1 / K10
Po IV Ka K10 1- IV administration MRTIV = 1 / K10 2- Oral administration MRToral longer than MRTIV MRToral = 1 / K / Ka MAT = MRToral - MRTIV = 1 / Ka
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MAT and bioavailability
The MAT MAT and bioavailability The MAT measures the MRT at the administration site and not the "rate" of drug arrival in the central compartment
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MAT and bioavailability
The MAT MAT and bioavailability Actually, the MAT is the MRT at the injection site MAT does not provide information about the absorption process unless F = 100%
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The MAT MAT and bioavailability F = Ka1 / (Ka1 +Ka2) MRT oral = + = +
! MAT is influenced by all processes of elimination (absorption, degradation,…) located at the administration site
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The MAT MAT and bioavailability 1 1.5 2 K10 1 K10 0.5 K10
MAT = 1/(1+1) = 0.5h MAT= 1/( )= 0.5h MAT=1/(0+2)=0.5h Conclusion : by measuring (AUMC/AUC), the same MAT will be obtained This does not mean that the absorption processes towards the central compartment are equivalent !
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The MAT MAT and bioavailability MATB < MATA but
1 0.5 A B 4 1 1 1 MATA = = 0.5 h MATB = = 0.28 h (1 + 1) ( ) MATB < MATA but Absorption clearance of B is lower than that of A ! !
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the MAT To accurately interpret the MAT in physiological terms it is necessary to: express the rate of absorption using the clearance concept Clabs = Vabs is unknown but this approach provides a meaning to the comparison of 2 MAT when the bioavailability is known Ka1 Vabs Clabs Ka1 x Vabs !
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MAT and bioavailability
The MAT MAT and bioavailability Given a MAT of 5 h with F = 100% Clabs = Ka1 x Vabs = 0.2 L/h Given a MAT of 5 h with F = 50% Clabs = Ka1 x Vabs = 0.1 L/h Ka1 = 0.2 h-1 Vabs = 1 L 0.1 h-1 Vabs = 1 L 0.1 h-1
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The Mean Dissolution Time (MDT)
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The MDT in vitro measurement: dissolution test
statistical moments approach modelling approach (Weibull)
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The MDT in vivo measurement (1) :
solution tablet digestive tract blood dissolution absorption elimination MRTtotal = MRTdissolution + MRTabsorption + MRT elimination What is the dissolution rate of the pellet in the digestive tract ?
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The MDT in vivo measurement (2) : IV IV administration MRTIV = 6 h
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The MDT in vivo measurement (3) : oral administration of the drug
of an oral solution elimination digestive tract blood oral administration of the drug Computation of MRTpo, solution from plasma concentrations MRToral, solution = MRTabsorption + MRTelimination = 8 h MAT = MRTpo - MRTIV MAT = 8h - 6h = 2h
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Tablet administration
The MDT in vivo measurement (4) : administration solution Tablet administration computation of MRToral,tablet from plasma concentrations MRToral,tablet=MRTdissolution + MAT + MRTelimination=18 h MRT dissolution= MRToral,tablet - (MAT + MRT IV) MRT dissolution= 18 - (2+6) = 10h
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Mean residence time in the central compartment (MRTc) and in the peripheral (tissue) compartment (MRTT)
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MRTcentral and MRTtissue
Definition : mean time for the analyte within the measured compartment (MRTC) or outside the compartment (MRTT) MRTC MRTT MRTsystem = MRTC + MRTT The MRT are additive
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MRTcentral and MRTtissue
Computations MRTC = AUC / Co = = MRTT = MRTsystem - MRTC MRTT = 1 Vc K10 Cl AUMC AUC AUC Co N.B. : necessary to know Co accurately
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MRTcentral and MRTtissue
Relationship with the extent of distribution MRTsystem Vss MRTcentral Vc This ratio measures the affinity for the peripheral compartment =
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The Mean Transit Time (MTT)
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The Mean Transit Times (MTT)
Definition : Average interval of time spent by a drug particle from its entry into the central compartment to its next exit
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The Mean Transit Time in the measurement (central) compartment (MTTcentral)
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The MTTcentral Calculation : MTTC = - C(o) dCp/dt for t = 0
MTTC = - C(o) C'(o) MTTC = Yi Yi i n n i =1 i =1 N.B. : necessary to know Co accurately
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The MTTcentral Computation : example for a bicompartmental model
C(t) = 5 exp(-0.7t) + 2 exp(-0.07t) MTTC = (5 + 2) / (5 x x 0.07) = h
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The MTTcentral and number of visits
Definition : The analyte "traveled" several times between the central and peripheral compartment R is the average number of times the drug molecule returns to the central compartment after passage through it MRTC R = MTTC
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The MTTcentral and number of visits
MRTC = R + 1 MTTC When there is no recycling (monocompartmental model) R = 0 and : MRTC = MRTC = MTTC MTTC
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The MTTcentral and number of visits
Bicompartmental model K12 MTTC = 1 / (K10 + K12) MTTC = 1 / (Cl + Cld) R = K12 / K10 R = Cld / Cl Vc K21 K10 MTTC describes the first pass of the analyte in the central compartment and does not take into account the recirculating process of the distributed fraction.
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The Mean Transit Time in the peripheral (tissue) compartment (MTTtissue)
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The MTTtissue (MTTT) Computation MTTT = MRTtissue / R MTTT =
MRTsystem - MRTcentral R (visit)
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The MTTtissue Computation : bicompartmental model Vss - Vc Vt
1 K21 Cld Cld K12 K21 K10 MTTT : - does not rely on clearance - measures drug affinity for peripheral tissues Jusko.J.Pharm.Sci : 157
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Application of the MRT concept
Interpretation of drug kinetics (1) Digoxin 21.4e-1.99t e-0.017t Gentamicin 5600e-0.218t e-0.012t Clearance (L/h) Cld (L/h) Vss (L) Vc (L) VT (L) 12.0 52.4 585 33.7 551.0 time : h concentration : mg l-1 Jusko.J.Pharm.Sci : 157
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Application of the MRT concept
Interpretation of drug kinetics (2) Gentamicin Digoxin K12 (h-1) K21 (h-1) K10 (h-1) R 1.56 0.095 0.338 4.37 Jusko.J.Pharm.Sci : 157
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Application of the MRT concept
Interpretation of the mean times Gentamicin Digoxin MTTcentral (transit time. central comp) MRTC (residence time. central comp.) MTTtissue (transit time peripheral comp.) MRTtissue (residence time peripheral comp.) MRTsystem (total) 4.65 5.88 64.5 17.1 23.0 0.532 2.81 10.5 46.0 48.8 Jusko.J.Pharm.Sci : 157
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Stochastic interpretation of a kinetic relationship
Cldistribution MRTC (all the visits) MTTC (for a single visit) MRTT (for all the visits) MTTT (for a single visit) R number de visits Clredistribution Clelimination MRTsystem = MRTC + MRTT
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Interpretation of a compartmental model
Determinist vs stochastic Digoxin 21.4 e-1.99t e-0.017t Cld = 52 L/h 0.3 h MTTT : 10.5h MRTT : 46h VT : 551 L MTTC : 0.5h MRTC : 2.81h Vc 34 L 4.4 41 h ClR = 52 L/h stochastic Cl = 12 L/h Determinist MRTsystem = 48.8 h 1.56 h-1 Vc : 33.7 L VT : 551L 0.095 h-1 0.338 h-1 t1/2 = 41 h
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Interpretation of a compartmental model
Determinist vs stochastic Gentamicin y =5600 e-0.281t e-0.012t Cld = 0.65 L/h t1/2 =3h MTTT : 64.5h MRTT : 17.1h VT : 40.8 L MTTC : 4.65h MRTC : 5.88h Vc : 14 L 0.265 t1/2 =57h ClR = 0.65 L/h stochastic Clélimination = 2.39 L/h Determinist MRTsystem = 23 h 0.045 h-1 Vc : 14 L VT : 40.8L 0.016 h-1 0.17 h-1 t1/2 = 57 h
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Interpretation determinist vs stochastic
Gentamicin vs digoxin Determinist Digoxin Gentamicin 0.56 h-1 0.045 h-1 Vc = 34 L VT = 551 L Vc = 14 L VT = 40.8 L 0.095 h-1 0.016 h-1 0.338 h-1 0.17 h t1/2 distribution : 0.3h t1/2 : 4 h t1/2 distribution : 3h t1/2 : 57 h MTTT: 10.5h MRTT:46h VT : 551 h Cld:0.65 L/h 0.26 0.65 L/h MTTT: 64.5h MRTT:17.1h VT : 40.8 h MTTC: 0.5h MRTC: 2.81h Vc = 34 L Cld:52 L/h 4.4 ClR:52 L/h MTTC: 4.65h MRTC: 5.88h Vc = 14 L Cl = 12 L/h Cl = 2.39 L/h MR system: 23 h MR system: 48.8 h
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MRTsystem Computation Statistical moments
Parameters from compartmental model
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Mean Residence Time t1/2 MRT 0.693 Varea Vss =
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