1. Grade 7 pp 269 QUESTION 2 a) Put numbers in order from least to greatest: 14,14,14,15,15,15,15,15,16,18, 18,19,19,19, 20,20,21,21,22,95 Mode: (most common number) 15 min Range: (largest minus smallest number) 95 – 14= 81 min Median : (Middle number of set) 18+18 = 36 36/2= 18 min

2. Grade 7 pp 269 QUESTION 2 Mean : (Add the numbers and then divide that by how many numbers are in the set) 14+14+14+15+15+15+15+15+16+18+18+19+19+19+ 20+20+21+21+22+95=427 427/20= 21.35 min b) The outlier is 95 minutes. It is much longer than any other time. The bus may have broken down or they may have been a detour, traffic delay or so on.

3. Grade 7 pp 269 QUESTION 2 C) Remove the outlier from the numbers: 14,14,14,15,15,15,15,15,16,18, 18,19,19,19, 20,20,21,21,22,95 Now: Mode: (most common number) 15 min (no change) Range: (largest minus smallest number) 22 – 14= 8 min ( much smaller range) Median : (Middle number of set) 18 min (no change in this case)

4. Grade 7 pp 269 QUESTION 2 Mean : (Add the numbers and then divide that by how many numbers are in the set) 14+14+14+15+15+15+15+15+16+18+18+19+19+19+ 20+20+21+21+22+95=427 ( You took 95 away so 427-95= 332) There is one less number in the set so 19 numbers. 332/19= 17.47min ( The mean is much smaller because the outlier was a large number)

5. Grade 7 pp 269 QUESTION 3 a) Put numbers in order from least to greatest: 4,28,32,32,32,34,36,36,36,36,38,40,42,44,46 Mode(most common number) : 36 Range: (largest minus smallest number) 46 –4= 42 Median : (Middle number of set) 36

6. Grade 7 pp 269 QUESTION 3 Mean: (Add the numbers and then divide that by how many numbers are in the set) 4+28+32+32+32+34+36+36+36+36+38+40+42+44+46= 516 516/15= 34.4 b) The outlier is 4. It is much smaller than any other size sold.

7. Grade 7 pp 269 QUESTION 3 c) Remove the outlier from the group: 4,28,32,32,32,34,36,36,36,36,38,40,42,44,46 Now: Mode: (most common number) 36 ( No change ) Range: (largest minus smallest number) 46 –28= 18 ( A much smaller range) Median : (Middle number of set) 36 + 36 = 72 72/2= 36 ( No change in this case)

8. Grade 7 pp 269 QUESTION 3 Mean: (Add the numbers and then divide that by how many numbers are in the set) 4+28+32+32+32+34+36+36+36+36+38+40+42+44+46=516 The outlier is removed so: 516 – 4= 512 There is now one less number in the set so there are 14 numbers. 512/14= 36.6 ( The mean is larger than it was because the outlier is a small number)