2. Chapter 10 Sinusoidal Steady-State Analysis Engineering Circuit Analysis Sixth Edition W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin Copyright © 2002 McGraw-Hill, Inc. All Rights Reserved. User Note: Run View Show under the Slide Show menu to enable slide selection. Fig. 10.1 The sinusoidal function v(t) = V m sin  t is... Fig. 10.2 The sine wave V m sin (  t  leads … Fig. 10.3 A graphical representation of two sinusoids v 1 and v 2. Fig. 10.8 (and 10.9) Real and imaginary forcing functions. Fig. 10.10 The complex forcing function V m e j(  t +  ) produces... Fig. 10.12 (10.13 & 10.14) Resistors, inductors, and capacitors … Fig. 10.19 Circuit from Example 10.6. Fig. 10.21 Circuit from Example 10.7. Fig. 10.37 Phasor diagrams.

3. Fig. 10.1 The sinusoidal function v(t) = V m sin  t is plotted (a) versus  t and (b) versus t. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. The sinusoidal function v(t) = V m sin  t is plotted (a) versus  t and (b) versus t.

4. Fig. 10.2The sine wave V m sin (  t  leads V m sin  t by  rad. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. The sine wave V m sin (  t  leads V m sin  t by  rad.

5. Fig. 10.3A graphical representation of two sinusoids v 1 and v 2. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. A graphical representation of the two sinusoids v 1 and v 2. The magnitude of each sine function is represented by the length of the corresponding arrow, and the phase angle by the orientation with respect to the positive x axis. In this diagram, v 1 leads v 2 by 100 o + 30 o = 130 o, although it could also be argued that v 2 leads v 1 by 230 o. It is customary, however, to express the phase difference by an angle less than or equal to 180 o in magnitude.

6. Fig. 10.8 and 10.9 Real and imaginary forcing functions. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. The sinusoidal forcing function V m cos (  t +  ) produces the steady-state response I m cos (  t +  ). The imaginary sinusoidal forcing function j V m sin (  t +  ) produces the imaginary sinusoidal response j I m sin (  t +  ).

7. Fig. 10.10 The complex forcing function V m e j(  t +  ) produces the complex response I m e j(  t +  ). W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. The complex forcing function V m e j(  t +  ) produces the complex response I m e j(  t +  ).

8. Figs. 10.12, 10.13, 10.14 Resistors, inductors, and capacitors in the phasor domain. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. (b) (a) (c) In the phasor domain, (a) a resistor R is represented by an impedance of the same value; (b) a capacitor C is represented by an impedance 1/j  C; (c) an inductor L is represented by an impedance j  L.

9. Fig. 10.19 Circuit from Example 10.6. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. Find the current i(t) in the circuit shown in (a).

10. Fig. 10.21 Circuit from Example 10.7. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. Find the time-domain node voltages v 1 (t) and v 2 (t) in the circuit shown below.

11. Fig. 10.37 Phasor diagrams. W.H. Hayt, Jr., J.E. Kemmerly, S.M. Durbin, Engineering Circuit Analysis, Sixth Edition. Copyright ©2002 McGraw-Hill. All rights reserved. (a) A phasor diagram showing the sum of V 1 = 6 + j8 V and V 2 = 3 – j4 V, V 1 + V 2 = 9 + j4 V = 9.85  24.0 o V. (b) The phasor diagram shows V 1 and I 1, where I 1 = YV 1 and Y = 1 + j S = 1.4  45 o S. The current and voltage amplitude scales are different.