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6.2 - 1 10 TH EDITION LIAL HORNSBY SCHNEIDER COLLEGE ALGEBRA
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6.2 - 2 6.2 Ellipses Equations and Graphs of Ellipses Translated Ellipses Ecentricity Applications of Ellipses
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6.2 - 3 Ellipse An ellipse is the set of all points in a plane the sum of whose distances from two fixed points is constant. Each fixed point is called a focus (plural, foci) of the ellipse.
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6.2 - 4 Equations and Graphs of Ellipses An ellipse has two axes of symmetry, the major axis (the longer one) and the minor axis (the shorter one). The foci are always located on the major axis.
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6.2 - 5 Equations and Graphs of Ellipses The midpoint of the major axis is the center of the ellipse, and the endpoints of the major axis are the vertices of the ellipse. The graph of an ellipse is not the graph of a function.
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6.2 - 6 Equations and Graphs of Ellipses This ellipse has its center at the origin, foci F(c, 0) and F(– c, 0), and vertices V(a, 0) and V(– a, 0). The distance from V to F is a – c and the distance from V to F a + c.
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6.2 - 7 Equations and Graphs of Ellipses The sum of these distances is 2a. Since V is on the ellipse, this sum is the constant referred to in the definition of an ellipse. Thus, for any point P(x, y) on the ellipse,
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6.2 - 8 Equations and Graphs of Ellipses By the distance formula, and
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6.2 - 9 Equations and Graphs of Ellipses Thus, Isolate Be careful when squaring. Square both sides
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6.2 - 10 Equations and Graphs of Ellipses Isolate Be careful when squaring. Square x – c: square x + c
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6.2 - 11 Equations and Graphs of Ellipses Square both sides. Divide each term by 4. Divide by 4. Distributive property
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6.2 - 12 Equations and Graphs of Ellipses Rearrange terms. Subtract 2ca 2 x. Factor. Divide by ()()
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6.2 - 13 Equations and Graphs of Ellipses Divide by 2. Combine terms. Square both sides. Subtract c 2. Since B(0, b) is on the ellipse in the figure shown here, we have
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6.2 - 14 Equations and Graphs of Ellipses Replacing a 2 – c 2 with b 2 in equation ( ) gives the standard form of the equation of an ellipse centered at the origin with foci on the x-axis. If the vertices and foci were on the y-axis, an almost identical derivation could be used to get the standard form
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6.2 - 15 Standard Forms of Equations for Ellipses The ellipse with center at the origin and equation (a > b) has vertices ( a, 0), endpoints of the minor axis (0, b), and foci ( c, 0), where c 2 = a 2 – b 2.
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6.2 - 16 Standard Forms of Equations for Ellipses The ellipse with center at the origin and equation (a > b) has vertices (0, a), endpoints of the minor axis ( b, 0), and foci (0, c), where c 2 = a 2 – b 2.
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6.2 - 17 Example 1 GRAPHING ELLIPSES CENTERED AT THE ORIGIN Graph each ellipse, and find the coordinates of the foci. Give the domain and range. Solution a. Divide each side of the equation by 36 to get Standard form of an ellipse. Divide each term by 36. Thus, the x-intercepts are 3, and the y-intercepts are 2. The graph of the ellipse is shown in the next slide.
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6.2 - 18 Example 1 GRAPHING ELLIPSES CENTERED AT THE ORIGIN Since 9 > 4, we find the foci of the ellipse by letting a 2 = 9 and b 2 = 4 in c 2 = a 2 – b 2. (By definition, c > 0.) The major axis is along the x-axis, so the foci have coordinates and The domain of this relation is [– 3, 3], and the range is (– 2, 2].
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6.2 - 19 Example 1 GRAPHING ELLIPSES CENTERED AT THE ORIGIN Graph each ellipse, and find the coordinates of the foci. Give the domain and range. Solution b. Standard form of an ellipse. Divide each term by 64. Thus, the x-intercepts are 4, and the y-intercepts are 8. The graph of the ellipse is shown in the next slide. Write the equation in standard form.
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6.2 - 20 Example 1 GRAPHING ELLIPSES CENTERED AT THE ORIGIN Here 64 > 16, so a 2 = 64 and b 2 = 16. Thus The major axis is on the y-axis, so the coordinates of the foci are and. The domain of the relation is the range is [– 4, 4]; the range [– 8, 8].
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6.2 - 21 Example 1 The graph of an ellipse is not the graph of a function. To graph the ellipse in Example 1(a) with a graphing calculator, solve for y in 4x 2 + 9y 2 = 36 to get equations of the two functions
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6.2 - 22 Example 2 WRITING THE EQUATION OF AN ELLIPSE Write the equation of the ellipse having center at the origin, foci at (0, 3) and (0, – 3), and major axis of length 8 units. Solution Since the major axis is 8 units long, 2a = 8 and a = 4. To find b 2, use the relationship a 2 – b 2 = c 2, with a = 4 and c = 3. Substitute for a and c. Solve for b 2.
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6.2 - 23 Example 2 WRITING THE EQUATION OF AN ELLIPSE Since the foci are on the y-axis, we use the larger intercept, a, to find the denominator for y 2, giving the equation in standard form as
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6.2 - 24 Example 2 WRITING THE EQUATION OF AN ELLIPSE The domain of this relation is and the range is
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6.2 - 25 Example 3 GRAPHING A HALF-ELLIPSE Graph and give the domain and range. Solution Square both sides to get the equation of an ellipse with x-intercepts 5 and y-intercepts 4.
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6.2 - 26 Example 3 GRAPHING A HALF-ELLIPSE Since the only possible values of y are those making giving the half-ellipse shown here. The half- ellipse is the graph of a function. The domain is the interval [– 5, 5] and the range is [0, 4].
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6.2 - 27 Ellipse Centered at (h, k) An ellipse centered at (h, k) with horizontal major axis of length 2a has equation There is a similar result for ellipses having a vertical major axis.
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6.2 - 28 Example 4 GRAPHING AN ELLIPSE Graph and give the domain and range. Solution The graph of this equation is an ellipse centered at (2, – 1). Ellipses always have a > b. For this ellipse, a = 4 and b = 3. Since a = 4 is associated with y 2, the vertices of the ellipse are on the vertical line through (2, – 1).
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6.2 - 29 Example 4 GRAPHING AN ELLIPSE Graph and give the domain and range. Solution Find the vertices by locating two points on the vertical line through (2, – 1), one 4 units up from (2, – 1), and one 4 units down. The vertices (2, 3) and (2, – 5).
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6.2 - 30 Example 4 GRAPHING AN ELLIPSE Graph and give the domain and range. Solution Two other points on the ellipse are on the horizontal line through (2, – 1), one 3 units to the right and one 3 units to the left.
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6.2 - 31 Example 4 GRAPHING AN ELLIPSE Graph and give the domain and range. Solution The domain is [– 1, 5], and the range is [– 5, 3].
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6.2 - 32 Note As suggested by the graphs in this section, an ellipse is symmetric with respect to its major axis, its minor axis, and its center. If a = b in the equation of an ellipse, then the graph is a circle.
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6.2 - 33 Eccentricity The ellipse is the third conic section (or conic) we have studied. (The circle and the parabola were the first two.) The fourth conic section, the hyperbola, will be introduced in the next section. All conics can be characterized by one general definition.
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6.2 - 34 Conic A conic is the set of all points P(x, y) in a plane such that the ratio of the distance from P to a fixed point and the distance from P to a fixed line is constant.
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6.2 - 35 Eccentricity For a parabola, the fixed line is the directrix, and the fixed point is a focus. In the figure shown here, the focus is F(c,0) and the directrix is the line x = – c. The constant ratio is called the eccentricity of the conic, written e. (This is not the same e as the base of natural logarithms.)
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6.2 - 36 Eccentricity If the conic is a parabola, then by definition, the distances d(P, F) and d(P, D) are equal. Thus, every parabola has eccentricity 1.
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6.2 - 37 Eccentricity For an ellipse, eccentricity is a measure of its “roundness.” By the definition of an ellipse, a 2 > b 2 and and Thus, for the ellipse, Divide by a.
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6.2 - 38 Eccentricity If a is constant, letting c approach 0 would force the ratio to approach 0, which also forces b to approach a (so that would approach 0). Since b determines the endpoints of the minor axis, this means that the lengths of the major and minor axes are almost the same, producing an ellipse very close in shape to a circle when e is very close to 0. In a similar manner, if e approaches 1, then b will approach 0.
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6.2 - 39 Eccentricity The path of Earth around the sun is an ellipse that is very nearly circular. For this ellipse, e .017. On the other hand, the path of Halley’s comet is a very flat ellipse, with e .97. The locations of the foci are shown in each case.
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6.2 - 40 Eccentricity The equation of a circle can be written Divide by r 2. In a circle, the foci coincide with the center, so a = b, and and thus e = 0.
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6.2 - 41 Example 5 APPLYING THE EQUATION OF AN ELLIPSE TO THE ORBIT OF A PLANET Find the eccentricity of the ellipse. Solution a. Since 16 > 9, a 2 = 16, which gives a = 4. Also, Finally,
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6.2 - 42 Example 5 APPLYING THE EQUATION OF AN ELLIPSE TO THE ORBIT OF A PLANET Find the eccentricity of the ellipse. Solution b. Divide by 50 to obtain Here, a 2 = 10, with Now, find c.
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6.2 - 43 Example 6 APPLYING THE EQUATION OF AN ELLIPSE TO THE ORBIT OF A PLANET The orbit of the planet Mars is an ellipse with the sun at one focus. The eccentricity of the ellipse is.0935, and the closest distance that Mars comes to the sun is 128.5 million mi. Find the maximum distance of Mars from the sun. The orbit of Mars has the origin at the center of the ellipse and the sun at one focus. Mars is closest to the sun when Mars is at the right endpoint of the major axis and farthest from the sun when Mars is at the left endpoint. Therefore, the smallest distance is a – c, and the greatest distance is a + c. Solution
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6.2 - 44 Example 6 APPLYING THE EQUATION OF AN ELLIPSE O THE ORBIT OF A PLANET Since a – c = 128.5, c = a – 128.5. Using Multiply by a. Subtract.0935a; add 128.5 Divide by.9065 Then and The maximum distance of Mars from the sun is about 155.1 million mi.
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6.2 - 45 Applications of Ellipses When a ray of light or sound emanating from one focus of an ellipse bounces off the ellipse, it passes through the other focus.
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6.2 - 46 Applications of Ellipses This reflecting property is responsible for whispering galleries. John Quincy Adams was able to listen in on his opponents’ conversations because his desk was positioned at one of the foci beneath the ellipsoidal ceiling and his opponents were located across the room at the other focus.
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6.2 - 47 Applications of Ellipses A lithotripter is a machine used to crush kidney stones using shock waves. The patient is placed in an elliptical tub with the kidney stone at one focus of the ellipse. A beam is projected from the other focus to the tub so that it reflects to hit the kidney stone.
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6.2 - 48 Example 7 MODELING THE REFLECTIVE PROPERTY OF ELLIPSES If a lithotripter is based on the ellipse determine how many units both the kidney stone and the source of the beam must be placed from the center of the ellipse. (– c, 0) (c, 0)
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6.2 - 49 (– c, 0) (c, 0) Example 7 MODELING THE REFLECTIVE PROPERTY OF ELLIPSES Solution The kidney stone and the source of the beam must be placed at the foci, (c, 0) and (– c, 0). Here a 2 = 36 and b 2 = 27, so
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