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The percent of calories from fat that a person in the United States consumes is normally distributed with a mean of about 36 and a standard deviation of 10. Suppose that one individual is randomly chosen. Let X = the percent of calories from fat = 36 percent = 10 percent X ~ N( 36, 10 )
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The percent of calories from fat that a person in the United States consumes is normally distributed with a mean of about 36 and a standard deviation of 10. Suppose that one individual is randomly chosen. Find the probability that the percent of calories a person consumes from fat is more than 40. Probability Statement: P(X > 40)=0.3446 Calculator steps: 2 nd, DIST,normalcdf(40,1E99,36,10),Enter
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The percent of calories from fat that a person in the United States consumes is normally distributed with a mean of about 36 calories and a standard deviation of 10 calories. Suppose that one individual is randomly chosen. Find the probability that the percent of calories a person consumes from fat is less than 50. Probability statement: P(X < 50)=0.9192 Calculator steps: 2 nd, DISTR,normalcdf(-1E99,50,36,10),Enter
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The percent of calories from fat that a person in the United States consumes is normally distributed with a mean of about 36 calories and a standard deviation of 10 calories. Suppose that one individual is randomly chosen. Find the probability that the percent of calories a person consumes from fat is between 30 and 40. Probability Statement: P(30 < X < 40) = 0.0.3812 Calculator steps: 2 nd, DISTR,normalcdf(30,40,36,10),Enter
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The percent of calories from fat that a person in the United States consumes is normally distributed with a mean of about 36 calories and a standard deviation of 10 calories. Suppose that one individual is randomly chosen. Find the lower quartile of percent of calories from fat. (Find the 25 th percentile.) Let k = the 25 th percentile. Probability statement: P(X < k) = 0.25 k = 29.26 calories Calculator steps to find k: 2 nd,DISTR,invNorm(0.25,36,10), Enter
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