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Published byBrook Owen Modified over 9 years ago
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Block Convolution: overlap-save method Input Signal x[n]: arbitrary length Impulse response of the filter h[n]: lenght P Block Size: N we take N samples of x[n] There’s ALIASING! right samples: L = N - (P - 1) CIRCULAR CONVOLUTION LINEAR CONVOLUTION + ALIASING
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Signal x[n] The input signal x[n] is splitted into blocks of length = L...
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Signal x[n] Lenght FFT = N The entry signal x[n] is splitted in blocks of lenght = N... P - 1 zero padding The Impulse response lenght = P, so we aggregate P - 1 zeros to the signal beggining Then when we compute the circular convolution, only L = N - (P - 1) samples match the linear convolution. Lenght L
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Signal x[n] Signal h[n] Lenght PN - P zero paddingLenght FFT = N To complete the lenght of the N FFT, we aggregate N-P zeros to the impulse response h[n] (lenght P)...
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Signal x[n] Signal h[n] x1[n]*h[n]x1[n]*h[n] We compute the first segment of the output performing a circular convolution of x 1 [n] and h[n] Length FFT = N Circular convolution DOESN’T match the linear convolution we discard P - 1 samples It HAS “aliasing” of P - 1 samples
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Signal x[n] Signal h[n] x1[n]*h[n]x1[n]*h[n] We compute the first segment of the output performing a circular convolution of x 1 [n] and h[n] Lenght FFT = N x 1 [n] * h[n] = IFFT{X 1 [k]xH[k]} It HAS “aliasing” of P - 1 samples
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Sucesión x[n] Sucesión h[n] x1[n]*h[n]x1[n]*h[n] We “copy” the result of the circular convolution of x 1 [n] and h[n] To the system output, discarding the wrong samples
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Signal x[n] Signal h[n] x1[n]*h[n]x1[n]*h[n] We “copy” the result of the circular convolution of x 1 [n] and h[n] to the system output, discarding the wrong samples
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] Signal x 2 [n] We process the second block x 2 [n] of the input x[n]... (overlapping P - 1 samples with the previous block)
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(solapando P - 1 muestras con el bloque previo) Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] We process the second block x 2 [n] of the input x[n]... with the impulse response h[n]
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(overlapping P - 1 samples with the previous block) Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] We process the second block x 2 [n] of the input x[n]... and we obtain the second segment x 2 [n] * h[n] x2[n]*h[n]x2[n]*h[n] with the impulse response h[n] Again, we have to discard P - 1 samples of the segment, that are wrong (due to aliasing)
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] We “copy” the result of the second circular convolution of x 1 [n] and h[n] (discarding the wrong samples)
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] We “copy” the result of the second circular convolution of x 1 [n] and h[n] (discarding the wrong samples)
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] we process the third block x 2 [n] of the input x[n]... x2[n]*h[n]x2[n]*h[n] (overlapping P - 1 samples with the previous block)
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] we process the third block x 2 [n] of the input x[n]... x2[n]*h[n]x2[n]*h[n] (overlapping P - 1 samples with the previous block) with the impulse response h[n]
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we obtain the third segment of the output x 3 [n] * h[n] Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] discarding the P - 1 first samples
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we copy it to the output... Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n]
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we copy it to the output... Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n]
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] we process the fourth block of the input x[n]
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] we process the fourth block of the input x[n] with the impluse response h[n]
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] we obtain the fourth segment of the output x 4 [n] * h[n] x4[n]*h[n]x4[n]*h[n]
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] We discard the first P - 1 samples... x4[n]*h[n]x4[n]*h[n]
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] x4[n]*h[n]x4[n]*h[n] …we copy it to the output
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] x4[n]*h[n]x4[n]*h[n] …we copy it to the output
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] x4[n]*h[n]x4[n]*h[n] We add the 4 output segments... + + + +...eliminating the correspoding samples!!
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] x4[n]*h[n]x4[n]*h[n] BLOCK convolution
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Signal h[n] x1[n]*h[n]x1[n]*h[n] Signal x[n] x2[n]*h[n]x2[n]*h[n] x3[n]*h[n]x3[n]*h[n] x4[n]*h[n]x4[n]*h[n] BLOCK convolution LINEAR convolution =
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