1. StatementReason E G H F Given Alt. Int. <s Thm. Reflex. Prop of p.244ex4 SAS. Steps 1,3,4

2. StatementReason J K L M p.246ex4 Given Reflex. Prop of ≅ <JKL ≅ <MLK SAS Steps 1,2,3

3. StatementReason p.244 ex 4 A B C D Given Alt. Int. <s Thm. Given SAS Steps 3,2,4 Reflexive Prop of ≅

4. StatementReason Given: <ZVY ≅ <WYV, <ZVW ≅ <WYZ,VW ≅ YZ Prove: V Y X W Z p.247: 21 Given Def. of ≅ m<WVY = m<ZYV Def. of ≅ Given SAS, Steps 6,5,7 <ZVY ≅ <WYV, <ZVW ≅ <WYZ m <ZVY = m <WYV, m <ZVW = m <WYZ m <ZVY + m <ZVW = m <WYV + m <WYZ <WVY ≅ <ZYV Reflex. Prop of ≅ <Add. Prop of = <Add. Post

5. Determine if you can use ASA to prove the triangles congruent. Explain. No, no included side

6. p. 246:13 Given: B is the midpoint of A B C D B is the mdpt of DC Given Def. Mdpt. SAS Steps 2,4,5 Reflex. Prop of ≅ <ABD and <ABC are right <s <ABD ≅ <ABC StatementReason

7. StatementReason Determine if you can use ASA to prove ΔUVX ≅ ΔWVX. Explain. p.253ex2 X U V W <WVX is a right angle <UXV ≅ <WXV given Reflex. Prop Def. of Linear Pair <WVX ≅ <UVX

8. 100 0 Given: What is the measure of y? y l m

9. Determine if you can use ASA to prove ΔNKL ≅ ΔLMN. Explain. p.253ex2 K L M N By Alt. Int. <s Thm, <KLN ≅ <MNL Reflex. Prop No other congruence relationships can be determined, so ASA cannot be applied.

10. Determine is you can use the HL Congruence Theorem to prove the triangles congruent. If not, tell what else you need to know. p.255ex4 Yes No, need the hyp ≅ Yes It is given that segment AC ≅ segment DB. Seg. CB ≅ Seg. CB, by the Reflexive Prop. Since <ABC and <DCB are rt <s, ΔABC and ΔDCB are rt triangles. ΔABC ≅ ΔDCB by HL.

11. StatementReason Given: <G ≅ <K, <J ≅ <M, HJ ≅ LM Prove: ΔGHJ ≅ ΔKLM H K L M G J p.254ex3 Given ASA Steps 1,3,2 Third <s Thm ΔGHJ ≅ ΔKLM <H ≅ <L <G ≅ <K, <J ≅ <M

12. StatementReason p.254ex3 Y WZ V X Use AAS to prove the triangles congruent. Given: <X ≅ <V, <YZW ≅ <YWZ, Prove: ΔXYZ ≅ ΔVYW <X ≅ <V <YZW ≅ <YWZ AAS Given ≅ Supps Thm Def. of Supp <s <XZY is supp to <YZW <YWX is supp to <VWY <YZX ≅ <YWV ≅ XYZ ≅ ΔVYW

13. StatementReason A B D E F C Given: Prove: p. 257: 13 Given Rt. < ≅ Thm Given AAS

14. StatementReason p.257:15 Given: E is a midpoint of Segments AD and BC Prove: Triangles ABE and DCE are congruent A B C D E <A and <D are rt anglesGiven E is mdpt of Segs AD, BC Given HL Rt. <s Thm Def. of mdpt Def. Rt Δs

15. StatementReason Given: Prove: p.258: 22 A B E C D Given AAS Vert. <s Thm Alt. Int. <s Thm

16. StatementReason p. 258: 23 Given: Prove: K J L M AAS Given Rt.<s Thm Def. of Perpendicular

17. StatementReason p.259q4 Given: Prove: A C D E B F G ASA Given ≅ Supp Thm Def. of Supp <s <BAC is supp of <FAB; <DEC is supp of <GED

18. StatementReason Given: Prove: E F G D Use CPCTC Given Alt. Int. <s Thm Reflex. Prop of ≅ SAS CPCTC Converse of Alt. Int. <s Thm

19. StatementReason Given: Prove: p.261ex3b Use CPCTC N O P M Given AAS CPCTC Alt. Int. <s Thm. Reflex. Prop ≅ Conv. Alt. Int. <s Thm

20. StatementReason Given: Prove: Use CPCTC A B C D Given SSS CPCTC Def. of < Bisector Reflex. Prop of ≅

21. StatementReason Given:M is the midpoint of Prove: Given SAS CPCTC Vert <s Thm Def. of mdpt M P Q R S Use CPCTC p.263: 8

22. StatementReason p.263: 9 Given: Prove: Use CPCTC W X Y Z Given SSS CPCTC Reflex. Prop ≅

23. StatementReason p.263: 10 Given: Prove: G is the midpoint of Given Def. of mdpt Def. of ≅ Through any 2 points there is exactly 1 line Reflex. Prop of ≅ Given SSS CPCTC ≅ Supp. Thm FG = HG Draw Use CPCTC 12 E F G H

24. StatementReason p.263: 11 Given: Prove:M is the midpoint of Given Def. of < bisector Given Reflex. Prop of ≅ SAS CPCTC Def. of mdpt M is the midpoint of L M K J Use CPCTC

25. StatementReason Given: ΔQRS is adjacent to ΔQTS. Prove: ΔQRS is adjacent to ΔQTS. Given Def. of < bisect Reflex. Prop of ≅ AAS CPCTC Def. of bisect p.263:14

26. StatementReason Given:with E the midpoint of Prove: p.263: 15 Given Def. of mdpt Vert <s Thm SAS CPCTC Conv. of Alt. Int. <s Thm E is the mdpt. of Use CPCTC

27. Given: PS = RQ, m<1 = m<4 Prove: m<3 = m<2 Given Def. of Perpendicular Def. of rt triangle Given Def. of ≅ Reflex. Prop of ≅ SAS CPCTC Def of ≅ PS = RQ m<1 = m<4 m<3 = m <2 p.264:19 1 2 P S R Q 3 4 Use CPCTC