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Published byEzra Howard Modified over 9 years ago
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Central Angle : an angle with its vertex at the center of the circle Inscribed Angle : an angle whose vertex on a circle and whose side contain chord of the circle Inscribed and Central Angle Created by ﺠﻴﻄ for Mathlabsky.wordpress.com
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a b c AOB = Central Angle A C B O ACB = Inscribed Angle a + b = c Proof : x Theorem Inscribed and Central Angle
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A B C O p p q q 2p 2q Let ACO = p, and BCO = q OC = OA (radius) ACO = CAO OC = OB (radius) BCO = CBO a b c D AOD = 2p & BOD = 2q & ACB = p + q AOB = 2p + 2q AOB = 2 ACB AOB = 2 ACB
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A B C D O AOB = 2 ACB AOB = 2 ADB ACB = ADB “If two inscribed angles intercept the same arc, than the angle are congruent” ACB = ADB
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A B C O AOC = 180 0 AOC = 2 ABC ABC = 90 0 “An angle inscribed in a semicercle is a right angle” ABC = 90 0
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A B C D O Let m 1=2x m 2 = x and m 3 = (360 – 2x) “If a quadrilateral is inscribed in a circle, then its opposite angles are supplementary” 1 2 3 4 m 3 = (360 – 2x) m 4 = ½(360 – 2x) m 4 = 180 – x m 2 + m 4 = x + (180 – x) BAD + BCD = 180 BAD + BCD = 180
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A B D E C ABD = ACD BAC = BDC AEB = CED ABE CDE 1 1 2 2 3 3 1 1 22 3 3 C D EE A B
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A B O C D E ● Let AOB = x and COD = y ACB = ½ x DBC = ½ y ½ x ½ y B C E A AEB = ½ x + ½ y AEB = ½ AOB + ½ COD AEB = ½ AOB + ½ COD y X
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A B C D E O x y Let AOB = x and COD = y ADB = ½ x DBC = ½ y E B D A ½ y ½ x AEB = ½ x - ½ y AEB = ½ AOB - ½ COD
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