2. Algebra I Concept Test # 7 – Graphing Lines Practice Test 1.Given: f (x) = − x + 8 a) Find f (10) Substitute 3 5 f (10) = − (10) + 8 3 5 f (10) = − + 8 30 5 Multiply Divide f (10) = − 6 + 8 Add f (10) = 2 b) Find f (0) f (0) = − (0) + 8 3 5 Multiply Substitute f (0) = 0 + 8 Add f (0) = 8 © 2007-09 by S-Squared, Inc. All Rights Reserved.

3. 2. Julie is 5 inches taller than Maria. Donovan is 3 inches shorter than Maria. The sum of their height is 188 inches. a)Write a variable equation for the given information. Donovan is 3 inches shorter than Maria The sum of their height is 188 inches Algebra I Concept Test # 7 – Graphing Lines Practice Test Assign variables: m + m + 5 + m – 3 = 188 Let, m = Maria’s height, m – 3 = Donovan’s height 3m + 2 = 188 m + 5 = Julie’s height, Julie is 5 inches taller than Maria Simplify

4. Maria’s height is m 2. Julie is 5 inches taller than Maria. Donovan is 3 inches shorter than Maria. The sum of their height is 188 inches. Algebra I Concept Test # 7 – Graphing Lines Practice Test 3m = 186 − 2 m = 62 3 3 b) How tall is each person in feet and inches? 3m + 2 = 188 Maria is 5 feet 2 inches tall Julie’s height is m + 5 Julie is 5 feet 7 inches tall Donovan’s height is m – 3 Donovan is 4 feet 11 inches tall Subtract Divide Note: This is Maria’s height in inches. To convert to feet and inches, divide by 12.

5. y = − 5 − 5 − 2 − 2 xy − 4 0 4 4 y = – 5 (−3) (−3) y = − 8 − 8 y = – 5 (0) (0) 3 4 (0) (0) 3 4 (4) (4) Algebra I Concept Test # 7 – Graphing Lines Practice Test 3.Given: a)Simplify the given equation and find three ordered pairs that are solutions. y = (3x – 20) 1 4 1 4 y = x – 5 3 4 y = – 5 3 4 (−4) y = – 5 (3) (3) − 8 − 8 − 5 − 2 0 (− 4, − 8), (0, − 5), (4, − 2)

6. Algebra I Concept Test # 7 – Graphing Lines Practice Test 3.Given: b)On the grid, draw the coordinate plane indicating the x-axis, y-axis, and the number intervals. y = (3x – 20) 1 4 x – axis (1) y – axis (2) −5 −4 −3 −2 −1 0 1 2 3 4 5 10 8 6 4 2 −2 −4 −6 −8 −10 c)Plot the points and graph the line. (− 4, − 8) (0, − 5) (4, − 2)

7. 4. Given the equation, 4y = − 3x + 4 a)Rewrite the equation in slope-intercept form. − 3 4 − 3 4 y = 1 OR (0, 1) − 3 4 − 3 4 4 4 4 −3−3 4 Algebra I Concept Test # 7 – Graphing Lines Practice Test Divide m = y = x + 1 b)Identify the slope. c)Identify the y-intercept. d)Graph: Note: Plot the y-intercept first, and then apply the slope. Slope – intercept form: y = mx + b

8. 1 2 Note: To find the x-intercept, let y = 0. Note: To find the y-intercept, let x = 0. a)Find the x- and y-intercepts. b)Graph: c)Identify the slope. 5.Given the equation: x – 2y = 4, x – intercept = (4, 0) y – intercept = (0, – 2) x – intercept = (4, 0) y – intercept = (0, – 2) x – 2y = 4 2 4 x - intercept y - intercept x – 2(0) = 4 x – 0 = 4 x = 4 0 – 2y = 4 – 2y = 4 y = – 2 2 4 Algebra I Concept Test # 7 – Graphing Lines Practice Test m = =

9. 6. a)On the coordinate plane provided, graph x = − 1 b)On the same coordinate plane, graph y = 4 c)Find the slope of x = − 1 d)Find the slope of y = 4 e)Identify the point of intersection Undefined 0 0 (– 1, 4) Algebra I Concept Test # 7 – Graphing Lines Practice Test

10. 7. Using the following graph, a)Find the y-coordinate when x = 0 y = − 3 x = 3 Algebra I Concept Test # 7 – Graphing Lines Practice Test Notice: You are looking for the unknown coordinate of an ordered pair when a coordinate is given. b)Find the x-coordinate when y = − 5 y = − 5 x = 0

11. 8.Given the following graph: a) Identify the slope Algebra I Concept Test # 7 – Graphing Lines Practice Test 3 2 − 2 3 2 m = b)Find the slope of a line perpendicular to the given line. c)Find the slope of a line parallel to the given line.

12. 9.Which of the following has a steeper slope: Algebra I Concept Test # 7 – Graphing Lines Practice Test y = x + 1 or 1 3 y = x – 1 2 3 Note: The line with the steeper slope is the line that has the greater numerical slope value. Notice, 2 3 1 3 > y = x – 1,has the steeper slope. 2 3