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Graphing r = θ on the Polar Coordinate Plane

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Presentation on theme: "Graphing r = θ on the Polar Coordinate Plane"— Presentation transcript:

1 Graphing r = θ on the Polar Coordinate Plane

2 Graphing r = θ on the Polar Coordinate Plane
To sketch the graph of r = θ, we should find some ordered pairs that satisfy the function. Since this function involves polar coordinates, we are looking for pairs of the form (r, θ).

3 Graphing r = θ on the Polar Coordinate Plane
To sketch the graph of r = θ, we should find some ordered pairs that satisfy the function. Since this function involves polar coordinates, we are looking for pairs of the form (r, θ). Let’s construct a table so that we can find ordered pairs on the graph of r = θ.

4 Graphing r = θ on the Polar Coordinate Plane
To construct a table of values for r = θ, let’s choose values for θ and find the corresponding values of r, and then form ordered pairs (r, θ).

5 Graphing r = θ on the Polar Coordinate Plane
To construct a table of values for r = θ, let’s choose values for θ and find the corresponding values of r, and then form ordered pairs (r, θ). We can then plot these ordered pairs on a polar coordinate plane to obtain a graph of the function.

6 Graphing r = θ on the Polar Coordinate Plane
Let’s start by choosing θ = 0.

7 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) Let’s start by choosing θ = 0.

8 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) Let’s start by choosing θ = 0. If θ = 0, then since r = θ we see that r also equals 0.

9 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) Let’s start by choosing θ = 0. If θ = 0, then since r = θ we see that r also equals 0.

10 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) Let’s start by choosing θ = 0. If θ = 0, then since r = θ we see that r also equals 0. This gives us the ordered pair (0, 0).

11 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) Let’s start by choosing θ = 0. If θ = 0, then since r = θ we see that r also equals 0. This gives us the ordered pair (0, 0).

12 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) Let’s start by choosing θ = 0. If θ = 0, then since r = θ we see that r also equals 0. This gives us the ordered pair (0, 0). Let’s plot this ordered pair on our polar coordinate plane.

13 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) Now let’s choose another value for θ.

14 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 Now let’s choose another value for θ. If θ = , π 4

15 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately 0.8. π 4 π 4

16 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 4 ≈ 0.8 Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately 0.8. π 4 π 4

17 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 4 ≈ 0.8 Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair π 4 π 4 π 4 ( ) 0.8,

18 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 4 ≈ 0.8 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair π 4 π 4 π 4 ( ) 0.8,

19 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 4 ≈ 0.8 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair Let’s plot this ordered pair on our polar coordinate plane, π 4 π 4 π 4 ( ) 0.8,

20 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 4 ≈ 0.8 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair Let’s plot this ordered pair on our polar coordinate plane, and connect the point we already graphed with this new point. π 4 π 4 π 4 ( ) 0.8,

21 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 4 ≈ 0.8 π 4 ( ) 0.8, Now let’s choose another value for θ.

22 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , π 2

23 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately 1.6. π 2 π 2

24 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately 1.6. π 2 π 2

25 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair π 2 π 2 π 2 ( ) 1.6,

26 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair π 2 π 2 π 2 ( ) 1.6,

27 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair Let’s plot this ordered pair on our polar coordinate plane, π 2 π 2 π 2 ( ) 1.6,

28 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair Let’s plot this ordered pair on our polar coordinate plane, and connect it with what we’ve graphed so far. π 2 π 2 π 2 ( ) 1.6,

29 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ.

30 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , 4

31 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately 2.4. 4 4

32 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately 2.4. 4 4

33 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair 4 4 4 ( ) 2.4,

34 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair 4 4 4 ( ) 2.4,

35 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair Let’s plot this ordered pair on our polar coordinate plane, 4 4 4 ( ) 2.4,

36 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, Now let’s choose another value for θ. If θ = , then since r = θ we see that r also equals , which is approximately This gives us the ordered pair Let’s plot this ordered pair on our polar coordinate plane, and connect it with what we’ve graphed so far. 4 4 4 ( ) 2.4,

37 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, We can continue to choose values for θ,

38 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, We can continue to choose values for θ, find the corresponding values for r,

39 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, We can continue to choose values for θ, find the corresponding values for r, plot the ordered pair (r, θ) on our polar coordinate plane,

40 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, We can continue to choose values for θ, find the corresponding values for r, plot the ordered pair (r, θ) on our polar coordinate plane, and connect our points to obtain a graph of r = θ.

41 Graphing r = θ on the Polar Coordinate Plane
r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

42 Graphing r = θ on the Polar Coordinate Plane
π r (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

43 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

44 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

45 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

46 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

47 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4,

48 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, (

49 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, (

50 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, (

51 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, (

52 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( ( ) 2 4.7,

53 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( ( ) 2 4.7,

54 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( 2 ( ) 4.7,

55 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 4 ≈ 5.5 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( 2 ( ) 4.7,

56 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 4 ≈ 5.5 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( 2 ( ) 4.7, ) 4 5.5, (

57 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 4 ≈ 5.5 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( ( ) ) 4 5.5, ( 2 4.7,

58 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 4 ≈ 5.5 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( ( ) ) 4 5.5, ( 2 4.7, Finally, we can continue drawing our graph along this same trajectory.

59 Graphing r = θ on the Polar Coordinate Plane
π r π ≈ 3.1 (r, θ ) (0, 0 ) (3.1, π) π 4 π 2 4 4 2 4 π 4 ≈ 0.8 π 2 ≈ 1.6 4 ≈ 2.4 4 ≈ 3.9 2 ≈ 4.7 4 ≈ 5.5 π 4 ( ) 0.8, π 2 ( ) 1.6, 4 ( ) 2.4, ) 4 3.9, ( ( ) ) 4 5.5, ( 2 4.7, Finally, we can continue drawing our graph along this same trajectory. The graph of r = θ is called the Archimedean Spiral.


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