1. FINAL EXAM MISCELLANEOUS REVIEW

2. PERIMETER, AREA, SURFACE AREA, AND VOLUME

3. QUESTION #1 FIND THE PERIMETER FIGURE BELOW.

4. ANSWER #1 FIND THE PERIMETER FIGURE BELOW. P = 8x + 12

5. QUESTION #2 FIND THE PERIMETER FIGURE BELOW.

6. ANSWER #2 FIND THE PERIMETER FIGURE BELOW. P = 11x + 4

7. QUESTION #3 FIND THE AREA OF THE FIGURE BELOW.

8. ANSWER #3 FIND THE AREA OF THE FIGURE BELOW. A = 1.1 in 2

9. QUESTION #4 FIND THE AREA OF THE ORANGE SECTION IN THE FIGURE BELOW.

10. QUESTION #4 FIND THE AREA OF THE ORANGE SECTION IN THE FIGURE BELOW. A = 201.0 in 2

11. QUESTION #5 THE LENGTH OF A RECTANGLE IS 3 MORE THAN THE WIDTH. IF THE DIMENSIONS OF THIS RECTANGLE ARE INCREASED BY 300%. A) WHAT IS THE AREA OF THE ORIGINAL FIGURE? B) WHAT IS THE NEW TOTAL AREA? C) WHAT IS THE AREA OF THE EXPANDED REGION?

12. ANSWER #5 THE LENGTH OF A RECTANGLE IS 3 MORE THAN THE WIDTH. IF THE DIMENSIONS OF THIS RECTANGLE ARE INCREASED BY 300%. A) WHAT IS THE AREA OF THE ORIGINAL FIGURE? B) WHAT IS THE NEW TOTAL AREA? C) WHAT IS THE AREA OF THE EXPANDED REGION? A = x 2 + 3x A = 9x 2 + 27x A = 8x 2 + 24x

13. QUESTION #6 FIND THE VOLUME OF A RECTANGULAR PRISM IF THE LENGTH OF THE BASE IS (3X+2), THE WIDTH OF THE BASE IS (X-1), AND THE HEIGHT OF THE PRISM IS (X+4).

14. ANSWER #6 FIND THE VOLUME OF A RECTANGULAR PRISM IF THE LENGTH OF THE BASE IS (3X+2), THE WIDTH OF THE BASE IS (X-1), AND THE HEIGHT OF THE PRISM IS (X+4). V = 3x 3 + 11x 2 – 6x - 8

15. QUESTION #7 USE THE SOLID FROM THE PREVIOUS PROBLEM AND DOUBLE THE DIMENSIONS! FIND THE VOLUME.

16. QUESTION #7 USE THE SOLID FROM THE PREVIOUS PROBLEM AND DOUBLE THE DIMENSIONS! FIND THE VOLUME. V = (6x+4)(2x-2)(2x+8) V = 24x 3 +88x 2 -48x-64 (Volume triples when dimensions double)

17. PROBABILITY

18. FIND THE PROBABILITY OF EACH OUTCOME. P(LESS THAN 3) A DIE IS ROLLED. QUESTION #8

19. FIND THE PROBABILITY OF EACH OUTCOME. P(LESS THAN 3) = 2/6 = 1/3 A DIE IS ROLLED. ANSWER #8

20. FIND THE PROBABILITY OF EACH OUTCOME. P(INTEGER) A DIE IS ROLLED. QUESTION #9

21. FIND THE PROBABILITY OF EACH OUTCOME. P(INTEGER) = 6/6 = 1 A DIE IS ROLLED. ANSWER #9

22. A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. P(NOT DIME) A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS. QUESTION #10

23. A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. P(NOT DIME) = 110/140 A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS. ANSWER #10

24. A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. P(NICKEL OR QUARTER) A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS. QUESTION #11

25. A COIN IS RANDOMLY SELECTED FROM THE JAR. FIND EACH PROBABILITY. P(NICKEL OR QUARTER) 27/140 + 18/140 = 40/140 = 2/7 A JAR CONTAINS 65 PENNIES, 27 NICKELS, 30 DIMES, AND 18 QUARTERS. QUESTION #11

26. FIND EACH PROBABILITY. P(LESS THAN 14) THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS. QUESTION #12

27. FIND EACH PROBABILITY. P(LESS THAN 14) = 13/28 THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS. ANSWER #12

28. FIND EACH PROBABILITY. P(NOT 2 OR 17) THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS. QUESTION #13

29. FIND EACH PROBABILITY. P(NOT 2 OR 17) = 1/28 + 1/28 = 2/28 = 1/14 THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS. ANSWER #13

30. FIND EACH PROBABILITY. P(13) THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS. QUESTION #14

31. FIND EACH PROBABILITY. P(13) = 1/28 THE STUDENTS IN A CLASS ARE RANDOMLY DRAWING CARDS NUMBERED 1 THROUGH 28 FROM A HAT TO DETERMINE THE ORDER IN WHICH THEY WILL GIVE THEIR PRESENTATIONS. QUESTION #14

32. WHAT IS THE PROBABILITY THAT THE SPINNER WITH LAND ON WHITE SECTION AND DIE WILL LAND ON 6? BRENDAN SPINS A SPINNER EQUALLY COLORED IN RED, BLUE, GREEN, AND WHITE AND ROLLS A FAIR DIE. QUESTION #15

33. WHAT IS THE PROBABILITY THAT THE SPINNER WITH LAND ON WHITE SECTION AND DIE WILL LAND ON 6? P(W, 6) = 1/4*1/6=1/24 BRENDAN SPINS A SPINNER EQUALLY COLORED IN RED, BLUE, GREEN, AND WHITE AND ROLLS A FAIR DIE. QUESTION #15

34. FIND THE PROBABILITY OF PICKING A BLACK THEN ANOTHER BLACK, WITHOUT REPLACEMENT. IN A BAG, THERE ARE 3 BLUE, 2 GREEN, AND 5 BLACK MARBLES. QUESTION #16

35. FIND THE PROBABILITY OF PICKING A BLACK THEN ANOTHER BLACK, WITHOUT REPLACEMENT. P(B, B)=5/10*4/9=2/9 IN A BAG, THERE ARE 3 BLUE, 2 GREEN, AND 5 BLACK MARBLES. ANSWER #16

36. HOW MANY DIFFERENT OUTFITS CAN SHE MAKE? ANNALISE WENT SHOPPING AND BOUGHT 4 T-SHIRTS, 3 SKIRTS, AND 2 SHOES. QUESTION #17

37. HOW MANY DIFFERENT OUTFITS CAN SHE MAKE? 4*3*2=24 ANNALISE WENT SHOPPING AND BOUGHT 4 T-SHIRTS, 3 SKIRTS, AND 2 SHOES. QUESTION #17

38. IF 133 STUDENTS ARE IN THE LITERATURE CLUB MEMBERS AND ALL STUDENTS READ AT LEAST ONE BOOK, HOW MANY STUDENTS READ ADVENTURE AND MYSTERY? THE VENN DIAGRAM BELOW SHOWS THE TYPES OF NOVELS THE LITERATURE CLUB MEMBERS READ DURING THEIR SUMMER BREAK. QUESTION #18

39. IF 133 STUDENTS ARE IN THE LITERATURE CLUB MEMBERS AND ALL STUDENTS READ AT LEAST ONE BOOK, HOW MANY STUDENTS READ ADVENTURE AND MYSTERY? 133-(36+14+7+43+3+28)=2 THE VENN DIAGRAM BELOW SHOWS THE TYPES OF NOVELS THE LITERATURE CLUB MEMBERS READ DURING THEIR SUMMER BREAK. QUESTION #18

40. PYTHAGOREAN THEOREM

41. QUESTION #19 FIND THE MISSING LENGTH.

42. ANSWER #19 FIND THE MISSING LENGTH. b = 112.5 units

43. QUESTION #20 FIND THE MISSING LENGTH.

44. QUESTION #20 FIND THE MISSING LENGTH. b = 7.2 units

45. QUESTION #21 DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE.

46. QUESTION #21 DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE. 9 2 +40 2 =41 2 is true, so it is a right triangle

47. QUESTION #22 DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE.

48. ANSWER #22 DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE. 4 2 +√26 2 =12 2 is NOT true, so it is NOT a right triangle

49. QUESTION #23 DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE.

50. QUESTION #23 DETERMINE WHETHER EACH SET OF MEASURES CAN BE THE LENGTHS OF THE SIDES OF A RIGHT TRIANGLE. (√65) 2 +(6√2) 2 =(√97) 2 is NOT true, so it is NOT a right triangle

51. QUESTION #24 FIND THE DISTANCE BETWEEN A AND B. ROUND TO THE NEAREST HUNDREDTH.

52. QUESTION #24 FIND THE DISTANCE BETWEEN A AND B. ROUND TO THE NEAREST HUNDREDTH. 10 2 +7 2 =c 2, so AB=11.7 units

53. QUESTION #25 EACH SIDE OF A CUBE IS 7 INCHES LONG. FIND THE LENGTH OF THE DIAGONAL OF THE SOLID.

54. ANSWER #25 EACH SIDE OF A CUBE IS 7 INCHES LONG. FIND THE LENGTH OF THE DIAGONAL OF THE SOLID. c d 7 7 2 +7 2 =c 2, so c=√98 7 2 +(√98) 2 =d 2, so d=12.1 units

55. THE END GOOD LUCK