2. 1.All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! 2.All students will play EVERY ROUND and show work on a separate sheet of paper (to be turned in). 3.Students will keep score together – winner gets bonus credit. JEOPARDY! Algebra 2 – Unit 3 Review

3. A Picture Is Worth A Thousand Words Word World! 3’s Company 200 300 500 700 100 300 500 200 500 1000 100 200 400 The Basics We’re Done! Good Luck on the Test!!

4. Solve for x and y: x + 2y = 11 2x – y = 2 100

5. x = 3, y = 4 or (3, 4) 100 x + 2y = 11 (2x – y = 2)  24x – 2y = 4 5x = 15  x = 3

6. Solve for x and y: x = 2y – 3 y – 3x = –1 200

7. y – 3(2y – 3) = –1 -5y + 9 = -1 y = 2 x = 2(2) – 3 = 1 x = 1, y = 2 or (1, 2) 200 x = 2y – 3 y – 3x = –1

8. Solve for x and y: 4x – 3y = 5 8x – 6y = 12 400

9. Since 0 = 2 can NEVER be true … “NO SOLUTION” !!! 400 ( 4x – 3y = 5 )  –2–8x + 6y = –10 8x – 6y = 12 8x – 6y = 12 0 = 2

10. The sum of two numbers is 24. The first number is 4 less than the second number. Find the two numbers. 200

11. Let x = first number Let y = second number x + y = 24 x = y – 4 x = 10, y = 14 200

12. Brandon has a pocket full of nickels and dimes. If he has 20 coins worth $1.30 in his pocket, how many of each coin does he have? 300

13. Let N = # of nickels Let D = # of dimes ( N + D = 20 )  –5 (.05N +.10D = 1.30 )  100 N = 14, D = 6 300

14. Twyla is taking her friends to a concert. Tickets cost $8 for general admission and $10 for reserved seating. If Twyla buys 12 tickets for a total of $102, how many of each kind of ticket did she buy? 500

15. Let G = # of general tickets Let R = # of reserved tickets ( G + R = 12 )  –8 8G + 10R = 102 G = 9, R = 3 500

16. The perimeter of a rectangle is 44. If the length is 6 more than the width, then find the length and the width. 700

17. Let L = length, W = width 2 L + 2 W = 44 L = W + 6 Substitute to get … 2(W + 6) + 2w = 44 L = 14, W = 8 700

18. Graph the following and identify the solution: y = 2x – 8 2y + x = 4 100

19. (4, 0) 100 y = 2x – 8 2y + x = 4y = –½ x + 2

20. 300 Graph the following and identify the solution: y  3x – 3 y  –2x + 4

21. 300 y  3x – 3 y  –2x + 4

22. 500 Graph the following and identify the solution: y  –5 x  2 y  x + 4

23. 500 y  –5 x  2 y  x + 4

24. 200 Solve for x, y and z: 3x + 5y + z = 5 x – 2y = –9 2x = –10

25. 200 x = –5 y = 2 z = 10 3x + 5y + z = 5 x – 2y = –9 2x = –10

26. 500 Solve for x, y, and z: 2x – y = 2 2y – z = 8 3x + z = 9

27. 500 x = 3 y = 4 z = 0 2x – y = 2 2y – z = 84x – 2y = 4 3x + z = 93x + 2y = 17 7x = 21

28. 1000 Solve for x, y and z: x – y + z = –2 3x + 2y + z = 6 2x + 3y – 2z = 10

29. x = 1 y = 2 z = –1 1000 x – y + z = –2 3x + 2y + z = 6 2x + 3y – 2z = 10