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(Mon) A small boy standing at the top of a tall snowy hill is making a snowman. If the head of the snowman has a mass of 10 kg, and the body of the snowman.

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Presentation on theme: "(Mon) A small boy standing at the top of a tall snowy hill is making a snowman. If the head of the snowman has a mass of 10 kg, and the body of the snowman."— Presentation transcript:

1 (Mon) A small boy standing at the top of a tall snowy hill is making a snowman. If the head of the snowman has a mass of 10 kg, and the body of the snowman is 1.5 m tall, how much work did the boy have to do to lift the head from the ground onto the top of the snowman? (5 min / 5 pts)

2 1.5 m W = Fd F = mg = (10kg)(9.81 m/s²) W = (10 kg)(9.81 m/s²)(1.5 m) W = 147.15 J

3 (Tue) The 10 kg head of a snowman sitting on the top of a 100 m tall hill falls 1.5 m off the snowman and starts rolling down the hill. Assuming that the head didn’t pick up any additional snow, what is the speed of the head when it reaches the bottom of the hill? (5 min / 5 pts)

4 1.5 m MEi = MEf ½mv² + mgh + ½kx² = ½mv² + mgh + ½kx² 0 + (10kg)(9.81m/s²)(101.5m) = ½(10kg)(v²) + 0 + 0 v = 44.63 m/s 101.5 m v² = 2(9.81m/s²)(101.5m)

5 (Wed) The 10 kg head of a snowman sitting on the top of a 100 m tall hill falls 1.5 m off the snowman and starts rolling down the hill. While rolling down the hill, the head picks up an additional 90 kg of snow. What is the speed of the head when it reaches the bottom of the hill? (5 min / 5 pts)

6 1.5 m MEi = MEf ½mv² + mgh + ½kx² = ½mv² + mgh + ½kx² 0 + (10kg)(9.81m/s²)(101.5m) = ½(100kg)(v²) + 0 + 0 v =14.11 m/s 101.5 m v² = 2(9.81m/s²)(101.5m)(10/100)

7 (Thu) The 10 kg head of a snowman sitting on the top of a 100 m tall hill falls 1.5 m off the snowman and starts rolling down the hill. While rolling down the hill, the head picks up an additional 90 kg of snow. At the bottom of the hill, it hits a parked car and stops in 0.3 seconds. How much force did it apply to the parked car? (7 min / 7 pts)

8 1.5 m MEi = MEfKE + PEg + PEe = KE + PEg + PEe 0 + (10kg)(9.81m/s²)(101.5m) = ½(100kg)(v²) + 0 + 0 v = 14.11 m/s 101.5 m v² = 2(9.81m/s²)(101.5m)(10/100) FΔt = Δp Δp = mΔv F = mΔv/Δt F = (100kg)(14.11m/s)/(0.3s) F = 4703.3 N

9 End of Week Procedures: 1.Add up all the points you got this week 2.Put the total number of points at the top of your page (out of 22 points) 3.List any dates you were absent (and why) 4.Make sure your name and period is on the top of the paper 5.Turn in your papers


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