2. Bekah Sean Griffen Kohta 5 th period

3. 60 Degrease Bekah Tan x= Opposite/adjacent Tan 60= x feet / 14 feet 14(tan 60)= X 24.249 feet+ 14 feet 5.125 feet+ 24.249 feet = 29.374 feet Long leg= square root of 3 x short leg X = square root of 3 x 14 feet X= 14 x square root of 3/ 3 X= 24.25 feet 60 degrees 14 feet 5 feet

4. 45 Degrees Kohta 60 inches (eye height) 28 feet base Tan x = opposite adjacent Tan (45)= x feet 28 feet 28 (tan 45)= x 28 feet = x 28 feet + 60 inches 28 feet + 5 feet = 33 feet 45-45-90 Side=Side 28=28 Side+Height=Pole Height 28+5=33feet 5 Feet 28 feet

5. 30 Degrees Sean Tan x = opposite / adjacent Tan30 = x / 38ft 38(Tan30) = x X ≈21.94 + 5.75 X≈27.69 ft Tan x = opposite / adjacent Tan30 = x / 38ft 38(Tan30) = x X ≈21.94 + 5.75 X≈27.69 ft 38 ft 5.75 Long leg =√3 ×short leg 38 = √3 × s. leg s. Leg = 38√3 / 3 s. Leg ≈ 21.94 + 5.75 X ≈ 27.69 ft. 30 degrees X

6. 24 Degrees Griffin 24 Degrees 67 Feet 5.75 Feet Tan x ≈ opposite Adjacent Tan (24) ≈ X Feet 67 Feet 67 [Tan (24)] ≈ X Feet X ≈ 29.83 Feet 29.83 Feet + 5.75 Feet ≈ 35.58 Feet

7. So………What Did We Learn Again? We noted that as the measure of the angle increased, the closer we got to the object. This made the angle sharper, and obviously decreased the distance from us to the light pole. The height of the light pole stayed the same We also noted that our light pole was crooked, so the measurements were most likely inaccurate. Also, one can not get an accurate measurement by simply taking steps.