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Geometry 3.5 Angles of a Polygon
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Polygons (“many angles”)
have vertices, sides, angles, and exterior angles are named by listing consecutive vertices in order A B C F Hexagon ABCDEF D E
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Polygons each segment intersects two other segments
formed by line segments, no curves the segments enclose space each segment intersects two other segments
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Polygons Not Polygons
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Diagonal of a Polygon A segment connecting two nonconsecutive vertices
Diagonals
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Convex Polygons No side ”collapses” in toward the center
Easy test : RUBBER BAND stretched around the figure would have the same shape…….
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Convex Polygons Nonconvex Polygons
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From now on……. When the textbook refers to polygons, it means convex polygons
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Polygons are classified by number of sides
Number of sides Name of Polygon 3 triangle 4 quadrilateral 5 pentagon 6 hexagon 8 octagon 10 decagon n n-gon
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Interior Angles of a Polygon
To find the sum of angle measures, divide the polygon into triangles Draw diagonals from just one vertex 4 sides, 2 triangles Angle sum = 2 (180) 5 sides, 3 triangles Angle sum = 3 (180) 6 sides, 4 triangles Angle sum = 4 (180) DO YOU SEE A PATTERN ?
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Interior Angles of a Polygon
4 sides, 2 triangles Angle sum = 2 (180) 5 sides, 3 triangles Angle sum = 3 (180) 6 sides, 4 triangles Angle sum = 4 (180) The pattern is: ANGLE SUM = (Number of sides – 2) (180)
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Theorem The sum of the measures of the interior angles of a convex polygon with n sides is (n-2)180. 5 sides. 3 triangles. Sum of angle measures is (5-2)(180) = 3(180) = 540 Example:
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Exterior Angles of a Polygon
3 2 2 1 4 3 5 1 4 5 Draw the exterior angles Put them together The sum = 360 Works with every polygon!
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Theorem The sum of the measures of the exterior angles of any convex polygon, one angle at each vertex, is 360.
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Regular Polygons If a polygon is both equilateral and equiangular it is called a regular polygon 120 120 120 120 120 120 120 120 120 120 120 120 Equilateral Equiangular Regular
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Example 1 A polygon has 8 sides (octagon.) Find:
The interior angle sum The exterior angle sum n=8, so (8-2)180 = 6(180) = 1080 360
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Example 2 Find the measure of each interior and exterior angle of a regular pentagon Interior: (5-2)180 = 3(180) = 540 540 = 108 each 5 Exterior: 360 = 72 each
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Example 3 How many sides does a regular polygon have if:
the measure of each exterior angle is 45 360 = = 45n n n = 8 8 sides: an octagon the measure of each interior angle is 150 (n-2)180 = 150 (n-2)180 = 150n n 180n – 360 = 150n - 360 = - 30n n = sides
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In summary… Sum of interior angles (n-2)180 Sum of ext. angles 360
One ext. angle 360/n One int. angle [(n – 2)180]/n OR supp. to 360/n # of sides given an ext. angle 360/measue of ext. angle # of sides given an int. angle find the ext angle(supp to int. angle) 360/measure of ext. angle
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Homework pg #1-17, skip 7, bring compass
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