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4.7 Write and Apply Exponential & Power Functions
How do you write an exponential function given two points? How do you write a power function given two points? Which function uses logs to solve it?
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Just like 2 points determine a line, 2 points determine an exponential curve. An Exponential Function is in the form of y=abx
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Write an Exponential function, y=abx whose graph goes thru (1,6) & (3,24)
Substitute the coordinates into y=abx to get 2 equations. 1. 6=ab1 2. 24=ab3 Then solve the system:
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Write an Exponential function, y=abx whose graph goes thru (1,6) & (3,24) (continued)
1. 6=ab1 → a=6/b 2. 24=(6/b) b3 24=6b2 4=b2 2=b a= 6/b = 6/2 = 3 So the function is Y=3·2x
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Substitute the coordinates of the two given points into y = ab .
Write an exponential function y =ab whose graph passes through (1, 12) and (3, 108). x SOLUTION STEP 1 Substitute the coordinates of the two given points into y = ab . x 12 = ab 1 Substitute 12 for y and 1 for x. 108 = ab 3 Substitute 108 for y and 3 for x. STEP 2
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Substitute for a in second equation. 12 b
108 = b3 12 b Substitute for a in second equation. 12 b Simplify. Divide each side by 12. Take the positive square root because b > 0. STEP 3 Determine that a = 12 b = 3 = 4 so, y = x
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Write an Exponential function, y=abx whose graph goes thru (-1,
b(.0625)=a 32=[b(.0625)]b2 32=.0625b3 512=b3 b=8 y=1/2 · 8x a=1/2
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Power Function A Power Function is in the form of y = axb Because there are only two constants (a and b), only two points are needed to determine a power curve through the points
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Modeling with POWER functions
a = 5/2b 9 = (5/2b)6b 9 = 5·3b 1.8 = 3b log31.8 = log33b .535 ≈ b a = 3.45 y = 3.45x.535 y = axb Only 2 points are needed (2,5) & (6,9) 5 = a 2b 9 = a 6b
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Substitute the coordinates of the two given points into y = ax .
Write a power function y = ax whose graph passes through (3, 2) and (6, 9) . b SOLUTION STEP 1 Substitute the coordinates of the two given points into y = ax . b b 2 = a 3 Substitute 2 for y and 3 for x. 9 = a 6 b Substitute 9 for y and 6 for x.
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Substitute for a in second equation. 2 3 9 = 6 2 3 9 = 2 2 b Simplify.
STEP 2 Solve for a in the first equation to obtain a = , and substitute this expression for a in the second equation. 2 3 b Substitute for a in second equation. 2 3 b 9 = 2 3 b 9 = 2 2 b Simplify. 4.5 = 2 b Divide each side by 2. Log = b 2 Take log of each side. 2 Log 4.5 Log2 = b Change-of-base formula Use a calculator. b STEP 3 Determine that a = So, y = 0.184x 2.17 3 2
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Substitute the coordinates of the two given points into y = ax .
Write a power function y = ax whose graph passes through the given points. b 6. (3, 4), (6, 15) SOLUTION STEP 1 Substitute the coordinates of the two given points into y = ax . b b 4 = a 3 Substitute 4 for y and 3 for x. 15 = a 6 b Substitute 15 for y and 6 for x.
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Substitute for a in second equation. 4 3 b
STEP 2 Solve for a in the first equation to obtain a = , and substitute this expression for a in the second equation. 4 3 b 4 3 b 15 = Substitute for a in second equation. 4 3 b 15 = 4 2 b Simplify. = 2 b 15 4 Divide each side by 4. 3.7 = 2 Log = b 2 Take log of each side. 2
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Change-of-base formula
Log 3.7 Log2 = b Change-of-base formula 0.5682 0.3010 = 1.9 Simplify. b Use a calculator. STEP 3 Determine that a = So, y = 0.492x 1.9 3 4 1.91
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Biology page 284 The table at the right shows the typical wingspans x (in feet) and the typical weights y (in pounds) for several types of birds. Biology • Draw a scatter plot of the data pairs (ln x, ln y). Is a power model a good fit for the original data pairs (x, y)? • Find a power model for the original data.
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How do you write an exponential function given two points?
y = abx How do you write a power function given two points? y = axb Which function uses logs to solve it? Power function y = axb
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Homework Page 285 3-7, 15-19
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