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5.1 GRAPHING QUADRATIC FUNCTIONS I can graph quadratic functions in standard form. I can graph quadratic functions in vertex form. I can graph quadratic functions in intercept form. You NEED graph paper today!
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QUADRATIC FUNCTION? We’ve been working with functions in the form y = mx + b. This was called a linear function because the graph was a straight line. A quadratic function is the form: y = ax 2 + bx + c where a ≠ 0 The graph of a quadratic function is: A parabola What’s different between a linear function and a quadratic function?
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QUADRATIC FUNCTION IN STANDARD FORM Y = AX 2 + BX + C Vertex Can either be the minimum of the parabola or the maximum of the parabola. If a is positive… The parabola goes up (like a cup) If a is negative… The parabola goes down (like a frown)
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QUADRATIC FUNCTION Y = AX 2 + BX + C Axis of symmetry Parabolas are always symmetric. Makes a vertical ‘imaginary’ line at the x coordinate of the vertex that cuts the parabola into equal halves.
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EXAMPLE 1: GRAPHING A QUADRATIC FUNCTION IN STANDARD FORM Standard Form: y = ax 2 + bx + c y = 2(2) 2 – 8(2) + 6 y = 2(4) – 16 + 6 y = 8 -10 y = -2 (2, -2)
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Axis of Symmetry: x = 2 You also need two more points to be able to make the graph. Choose x = 3 and x = 4 because they are right after the Axis of Symmetry y = 2(3) 2 – 8(3) + 6 y = 2(9) – 24 + 6 y = 18 – 24 + 6 y = 0 (3, 0) y = 2(4) 2 – 8(4) + 6 y = 2(16) – 32 + 6 y = 32 – 32 + 6 y = 6 (4, 6)
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Vertex: (2, -2) Axis of Symmetry: x = 2 Points: (3,0) (4,6)
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INDIVIDUAL PRACTICE ON GRAPHING QUADRATICS IN STANDARD FORM Pg 253 20-25 List the vertex Axis of symmetry At least 2 extra points You have 15 minutes to work on this section of problems. I will do the next part of notes in 15 minutes.
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QUADRATIC FUNCTION IN VERTEX FORM y = a(x – h) 2 + k Vertex: (h,k) Axis of Symmetry: x = h You still also need to find two more points to plot.
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EXAMPLE 2: GRAPHING A QUADRATIC FUNCTION IN VERTEX FORM y = -3(x + 1) 2 + 2 Vertex: (-1,2) Axis of Symmetry: x = -1 Points: (0,-1) (1,-10) x = 0 y = -3(0+1) 2 + 2 y = -3(1) 2 + 2 y = -3(1) + 2 y = -3 + 2 y = -1 x = 1 y = -3(1+1) 2 + 2 y = -3(2) 2 + 2 y = -3(4) + 2 y = -12 + 2 y = -10 Vertex Form: y = a(x – h) 2 + k
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Vertex: (-1,2) Axis of Symmetry: x = -1 Points: (0,-1) (1,-10)
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INDIVIDUAL PRACTICE ON GRAPHING QUADRATICS IN VERTEX FORM Pg. 253 26-31 List the vertex Axis of symmetry At least 2 extra points You have 15 minutes to work on this section of problems. I will do the next part of notes in 15 minutes.
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QUADRATIC FUNCTIONS IN INTERCEPT FORM y = a(x – p)(x – q) The x-intercepts are p and q. The axis of symmetry is halfway between p and q. The vertex is found by plugging the axis of symmetry back in to the function and solve for y.
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EXAMPLE 3: GRAPHING QUADRATICS IN INTERCEPT FORM y = -(x + 2)(x - 4) X-intercepts: -2 and 4 Axis of symmetry: x = 1 Vertex: (1,9) x = 1 y = -(1+2)(1-4) y = -(3)(-3) y = -(-9) y = 9 Intercept Form: y = a(x – p)(x – q)
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X-intercepts: -2 and 4 Axis of symmetry: x = 1 Vertex: (1,9)
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INDIVIDUAL PRACTICE ON GRAPHING QUADRATICS IN INTERCEPT FORM Pg. 254 32-37 List the vertex Axis of symmetry Intercepts
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