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1 Covalent Bonding Sharing is caring
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2 Metallic Ionic Covalent Transfer Electrons Delocalized Electrons (sea of e - ) Share Electrons Molecule Unit Cell
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3 In covalent bonding, atoms still want to achieve a noble gas configuration (the octet rule). But rather than losing or gaining electrons, atoms share electrons.
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4 Covalent Bonds When one nonmetal shares one or more electrons with an atom of another nonmetal so both atoms end up with eight valence electrons
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5 But rather than losing or gaining electrons, atoms now share an electron pair. The shared electron pair is called a bonding pair
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6 Naming Covalent Compound
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7 Covalent bonding Makes molecules Specific atoms joined by sharing electrons Two kinds of molecules: Molecular compound Sharing by different elements Diatomic molecules Two of the same atom O 2 N 2
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8 Diatomic elements There are 7 elements that always form molecules: H 2, N 2, O 2, F 2, Cl 2, Br 2, I 2 The –gens (hydrogen, nitrogen, oxygen and halogens) NEVER FOUND AS SINGLE ATOMS if “alone” Their names are just the name of the element Oxygen by itself means O 2
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9 1 and 7 Covalent Bond Video
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10 Binary Molecular Compounds Steps to name compounds a. a.Name first element - use entire name b. b.Name second element- change ending to –ide c. c.Prefixes used to indicate number of each atom d. Only time that no prefix is used is if the first is a one Examples: CCl 4 – As 2 O 3 – tri di tetrachloride carbon arsenic oxide
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11 The Prefixes Mono-monocle Tri-tricycle Penta-pentagon Octa- octopus Tetra-Tetris Di-Dialogue
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12 1mono 2di 3tri 4tetra 5penta 6hexa 7hepta 8octa 9nona 10deca The first vowel is often dropped to avoid the combination of “ao” or “oo”. CO = carbon monoxide (monooxide) SO 2 = sulfur dioxide (doxide) P 4 O 10 = tetraphosphorus decoxide
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13 CF 4 N 2 O SF 6 carbon tetraflouride dinitrogen monoxide sulfur hexafluoride Molecular Nomenclature: Examples P2O3P2O3 diphosporus trioxide IF 7 iodine heptafluoride
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14 arsenic trichloride dinitrogen pentoxide tetraphosphorus decoxide AsCl 3 N 2 O 5 P 4 O 10 More Molecular Examples
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15 Octet Rule: All elements will have 8 electrons around it through a combination of shared and unshared electrons. THERE ARE A FEW EXCEPTIONS!!! »H »H only needs 2 electrons »Be »Be only needs 4 electrons »B »B only needs 6 electrons Covalent Bonds and Lewis Structures
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16 Most covalent bonds involve the sharing of: –2 electrons (single covalent bond), –4 electrons (double covalent bond, or –6 electrons (triple covalent bond). Covalent Bonds and Lewis Structures
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17 Covalent Bonds and Lewis Structures We are going to use the N.A.S method: N = needed A = available S = shared (or halogens) HONC 1234 # of bonds * * Element that form the most bonds goes in the middle
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18 Covalent Bonds and Lewis Structures O 2 : N = A = S = 2 (8) = 16 6 + 6= 12 16 – 12 = 4 (2 bonds)
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19 Covalent Bonds and Lewis Structures CO: N = A = S = 8 + 8 = 16 4 + 6= 10 16 – 10 = 6 (3 bonds)
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20 Lewis structures (electron dot structures) show the structure of molecules. (Bonds can be shown with dots for electrons, or with dashes: 1 dash = 2 electrons) H 2 HBr CCl 4 N 2
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21 Lewis structures (electron dot structures) show the structure of molecules. (Bonds can be shown with dots for electrons, or with dashes: 1 dash = 2 electrons) H 2 HBr CCl 4 N 2
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22 Lewis structures (electron dot structures) show the structure of molecules. (Bonds can be shown with dots for electrons, or with dashes: 1 dash = 2 electrons) H 2 HBr CCl 4 N 2
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23 Lewis structures (electron dot structures) show the structure of molecules. (Bonds can be shown with dots for electrons, or with dashes: 1 dash = 2 electrons) H 2 HBr CCl 4 N 2
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24 Lewis structures (electron dot structures) show the structure of molecules. (Bonds can be shown with dots for electrons, or with dashes: 1 dash = 2 electrons) H 2 HBr CCl 4 N 2
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25 Lewis structures (electron dot structures) show the structure of molecules. (Bonds can be shown with dots for electrons, or with dashes: 1 dash = 2 electrons) H 2 HBr CCl 4 N 2
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26 Covalent Bonds and Lewis Structures NO 3 - : N = A = S = 8 + 3 (8) = 32 5 + 3 (6) + 1= 24 32 – 24 = 8 (4 bonds)
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