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Over Lesson 2–1 A.A B.B C.C D.D 5-Minute Check 5 A.–4 B.4 C.12 D.20 Evaluate |–8| + |b| + a if a = 0 and b = 12. Five locations in California with elevations.

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Presentation on theme: "Over Lesson 2–1 A.A B.B C.C D.D 5-Minute Check 5 A.–4 B.4 C.12 D.20 Evaluate |–8| + |b| + a if a = 0 and b = 12. Five locations in California with elevations."— Presentation transcript:

1 Over Lesson 2–1 A.A B.B C.C D.D 5-Minute Check 5 A.–4 B.4 C.12 D.20 Evaluate |–8| + |b| + a if a = 0 and b = 12. Five locations in California with elevations below sea level are shown in the table. What is the order of these elevations from least to greatest? A.–3, –5, –13, –43, –69 B.–13, –43, –69, –5, –3 C.–69, –13, –3, –5, 43 D.–69, –43, –13, –5, –3

2 Splash Screen

3 Then/Now You added integers using algebra tiles. (Explore 2–2) Add two integers. Add more than two integers.

4 Vocabulary opposites additive inverse

5 Example 1 Add Integers Using a Number Line Find –2 + (–4). Use a number line. Step 1Start at zero. Step 2Move 2 units left. Step 3From there, move 4 more units to the left. Answer: So, –2 + (–4) = –6.

6 A.A B.B C.C D.D Example 1 A.7 B.–7 C.3 D.–3 Find –2 + (–5).

7 Concept

8 Example 2 Add Integers with the Same Sign Find –5 + (–4). –5 + (–4) = –9Add |–5| and |–4|. Both numbers are negative, so the sum is negative. Answer: –9

9 A.A B.B C.C D.D Example 2 A.–11 B.–5 C.5 D.11 Find –3 + (–8).

10 Example 3 Add Integers Using Number Line A. Find 7 + (–11). Step 1:Start at zero. Answer: 7 + (–11) = –4 Step 2:Move 7 units to the right. Step 3:From there, move 11 units to the left.

11 Example 3 Add Integers Using Number Line B. Find –2 + 9. Step 1: Start at zero. Answer: –2 + 9 = 7 Step 2: Move 2 units to the left. Step 3: From there, move 9 units to the right.

12 Concept

13 Example 4 Add Integers with Different Signs A. Find –9 + 10. –9 + 10 = 1To find –9 + 10, subtract |9| from |10|. The sum is positive because |10| > |9|. Answer: 1

14 Example 4 Add Integers with Different Signs B. Find 8 + (–15). 8 + (–15) = –7To find 8 + (–15), subtract |8| from |–15|. The sum is negative because |–15| > |8|. Answer: –7

15 A.A B.B C.C D.D Example 4 A.5 B.–5 C.17 D.–17 A. Find –6 + 11.

16 A.A B.B C.C D.D Example 4 A.11 B.–11 C.3 D.–3 B. Find 4 + (–7).

17 A.A B.B C.C D.D Example 3 A.3 B.–3 C.9 D.–9 B. Find 3 + (–6).

18 A.A B.B C.C D.D Example 3 A.13 B.–13 C.3 D.–3 A. Find –5 + 8.

19 Example 5 Solve Equations WEATHER On February 1, the temperature at dawn was –22°F. By noon, it had risen 19 degrees. What was the temperature at noon?

20 Example 5 Solve the equation. –22 + 19 = tTo find the sum, subtract |19| from |–22|. –3 = tThe sum is negative because |–22| > |19|. Answer: The temperature at noon was –3°F.

21 A.A B.B C.C D.D Example 5 A.3 feet above sea level B.3 feet below sea level C.61 feet above sea level D.61 feet below sea level HIKING Dave started his hike at 32 feet below sea level. During the hike he gained an altitude of 29 feet. At what altitude did Dave complete his hike?

22 Concept

23 Example 6 Add More Than Two Integers A. Find –8 + (–4) + 8. –8 + (–4) + 8=–8 + 8 + (–4)Commutative Property =0 + (–4)Additive Inverse Property =–4Identity Property of Addition Answer: –4

24 Example 6 Add More Than Two Integers B. Find 6 + (–3) + (–9) + 2. 6 + (–3) + (–9) + 2 = 6 + 2 + (–3) + (–9) Commutative Property = (6 + 2) + [–3 + (–9)]Associative Property = 8 + (–12) or –4Simplify. Answer: –4

25 A.A B.B C.C D.D Example 6 A.–9 B.–3 C.3 D.15 A. Find 3 + (–9) + (–3).

26 A.A B.B C.C D.D Example 6 A.–22 B.–8 C.0 D.10 B. Find –2 + 11 + (–4) + 5.

27 End of the Lesson


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