1. Forces and Newton’s Laws of Motion
Chapter 4
Forces and Newton’s Laws of Motion
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PHY Ch 04b - Revised: 6/9/2010

2. Forces and Newton’s Laws of Motion
Newton’s Three Laws of Motion
The Gravitational Force
Contact Forces (normal, friction, tension)
Application of Newton’s Second Law
Apparent Weight
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PHY Ch 04b - Revised: 6/9/2010

3. Net Force
The net force is the vector sum of all the forces acting on a body.
The net force is the resultant of this vector addition.
Bold letters represent vectors. The units of Force are Newtons, or the abbreviation N, which represent the SI units: kg-m/s2
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PHY Ch 04b - Revised: 6/9/2010

4. Free Body Diagrams
The free body diagram (FBD) is a simplified representation of an object, and the forces acting on it. It is called free because the diagram will show the object without its surroundings; i.e. the body is “free” of its environment.
We will consider only the forces acting on our object of interest. The object is depicted as not connected to any other object – it is “free”. Label the forces appropriately. Do not include the forces that this body exerts on any other body.
The best way to explain the free body diagram is to describe the steps required to construct one. Follow the procedure given below.
(1) Isolate the body of interest. Draw a dotted circle around the object that separates our object from its surroundings.
(2) Draw all external force vectors acting on that body.
(3) You may indicate the body’s assumed direction of motion. This does not represent a separate force acting on the body.
(4) Choose a convenient coordinate system.
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PHY Ch 04b - Revised: 6/9/2010

5. Free Body Diagram N1 F T w1 yx y
The force directions are as indicated in the diagram. The magnitudes should be in proportion if possible.
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PHY Ch 04b - Revised: 6/9/2010

6. Newton’s First Law of Motion: Inertia and Equilibrium
Newton’s 1st Law (The Law of Inertia):
If no force acts on an object, then the speed and direction of itsmotion do not change.
Inertia is a measure of an object’s resistance to changes in its motion.
It is represented by the inertial mass.
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PHY Ch 04b - Revised: 6/9/2010

7. Newton’s First Law of Motion
If the object is at rest, it remains at rest (velocity = 0).
If the object is in motion, it continues to move in a straight line with the same velocity.
No force is required to keep a body in straight line motion when effects such as friction are negligible.
An object is in translational equilibrium if the net force on it is zero and vice versa.
Translational Equilibrium
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PHY Ch 04b - Revised: 6/9/2010

8. Newton’s Second Law of Motion Net Force, Mass, and Acceleration
Newton’s 2nd Law:
The acceleration of a body is directly proportional to the net force acting on the body and inversely proportional to the body’s mass.
Mathematically:
This is the workhorse of mechanics
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

9. Newton’s Second Law of Motion
An object’s mass is a measure of its inertia. The more mass, the more force is required to obtain a given acceleration.
The net force is just the vector sum of all of the forces acting on the body, often written as F.
If a = 0, then F = 0. This body can have:
Velocity = 0 which is called static equilibrium, or
Velocity  0, but constant, which is called dynamic equilibrium.
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

10. Newton’s Third Law of Motion Interaction Pairs
Newton’s 3rd Law:
When 2 bodies interact, the forces on the bodies, due to each other, are always equal in magnitude and opposite in direction.
In other words, forces come in pairs.
Mathematically:
designates the force on object 2 due to object 1.
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PHY Ch 04b - Revised: 6/9/2010

11. Types of Forces Contact forces: Normal Force & Friction Tension
Gravitational Force
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12. Contact Forces
Contact forces: these are forces that arise due to of an interaction between the atoms in the surfaces of the bodies in contact.
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13. Normal Forces
Normal force: this force acts in the direction perpendicular to the contact surface.
Normal force of the ground on the box N w
Normal force of the ramp on the box N w
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PHY Ch 04b - Revised: 6/9/2010

14. Normal Forces y N Example: Consider a box on a table. FBD for box x w
Apply Newton’s 2nd law
This just says the magnitude of the normal force equals the magnitude of the weight; they are not Newton’s third law interaction partners.
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PHY Ch 04b - Revised: 6/9/2010

15. Frictional Forces
Friction: a contact force parallel to the contact surfaces.
Static friction acts to prevent objects from sliding.
Kinetic friction acts to make sliding objects slow down. Sometimes called Dynamic friction.
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16. Frictional Forces
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17. Tension
This is the force transmitted through a “rope” from one end to the other.
An ideal cord has zero mass, does not stretch, and the tension is the same throughout the cord.
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PHY Ch 04b - Revised: 6/9/2010

18. T FBD for the mass M w Apply Newton’s 2nd Law to the mass M.
Example (text problem 4.77): A pulley is hung from the ceiling by a rope. A block of mass M is suspended by another rope that passes over the pulley and is attached to the wall. The rope fastened to the wall makes a right angle with the wall. Neglect the masses of the rope and the pulley.
Find the tension in the rope from which the pulley hangs and the angle . w T x y
FBD for the mass M
Apply Newton’s 2nd Law to the mass M.
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PHY Ch 04b - Revised: 6/9/2010

19. This statement is true only when  = 45 and
Example continued:
Apply Newton’s 2nd Law:
FBD for the pulley: x y T F 
This statement is true only when  = 45 and
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PHY Ch 04b - Revised: 6/9/2010

20. Gravitational Forces
Gravity is the force between two masses. Gravity is a long-range force. No contact is needed between the bodies. The force of gravity is always attractive!
r is the distance between the two masses M1 and M2 and G = 6.671011 Nm2/kg2. M2 r M1
F21
F12
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PHY Ch 04b - Revised: 6/9/2010

21. Gravitational Forces Let M1 = ME = mass of the Earth.
Here F = the force the Earth exerts on mass M2. This is the force known as weight, w.
Near the surface of the Earth
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

22. Gravitational Forces Note that
is the gravitational force per unit mass. This is called the gravitational field strength. It is also referred to as the acceleration due to gravity.
What is the direction of g?
What is the direction of w?
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PHY Ch 04b - Revised: 6/9/2010

23. Gravitational Forces On Earth: In low Earth orbit:
Example: What is the weight of a 100 kg astronaut on the surface of the Earth (force of the Earth on the astronaut)? How about in low Earth orbit? This is an orbit about 300 km above the surface of the Earth.
On Earth:
In low Earth orbit:
The weight is reduced by about 10%. The astronaut is NOT weightless!
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

24. Applying Newton’s Second Law
The one equation everyone remembers!
Sumof the forces acting on the objects in the system
“m” is the System
Mass
“a” is the System
Response
This equation is just the tip of the “iceberg” of the mechanics problem. The student will need to anlyze the forces in the problem and sum the force vector components to build the left hand side of the equation.
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

25. Applying Newton’s Second Law
Example: A force of 10.0 N is applied to the right on block 1. Assume a frictionless surface. The masses are m1 = 3.00 kg and m2 = 1.00 kg.
Find the tension in the cord connecting the two blocks as shown. F
block 2
block 1
Assume that the rope stays taut so that both blocks have the same acceleration.
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PHY Ch 04b - Revised: 6/9/2010

26. Apply Newton’s 2nd Law to each block:
FBD for block 2:
FBD for block 1: T F w1 N1 x y x T w2 N2 y
Apply Newton’s 2nd Law to each block:
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PHY Ch 04b - Revised: 6/9/2010

27. These two equations contain the unknowns: a and T.
Example continued:
(1)
These two equations contain the unknowns: a and T.
(2)
To solve for T, a must be eliminated. Solve for a in (2) and substitute in (1).
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

28. Pick Your System Carefullyx T w2 N2 y T F w1 N1 x y
Include both objects in the system. Now when you sum the x-components of the forces the tensions cancel. In addition, since there is no friction, y-components do not contribute to the motion.
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

29. Apparent Weight Stand on a bathroom scale. N FBD for the person:x y
FBD for the person:
Apply Newton’s 2nd Law:
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PHY Ch 04b - Revised: 6/9/2010

30. Apparent Weight is what the scale reads.
The normal force is the force the scale exerts on you. By Newton’s 3rd Law this is also the force (magnitude only) you exert on the scale. A scale will read the normal force.
is what the scale reads.
When ay = 0, N = mg. The scale reads your true weight.
When ay  0, N > mg or N < mg.
In free fall ay = -g and N = 0. The person is weightless.
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

31. Apparent Weight FBD for woman: N w
Example (text problem 4.128):
A woman of mass 51 kg is standing in an elevator. The elevator pushes up on her feet with 408 newtons of force.
What is the acceleration of the elevator?
FBD for woman: w N x y
Apply Newton’s 2nd Law:
(1)
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

32. Apparent Weight Given: N = 408 newtons, m = 51 kg, g = 9.8 m/s2
Example continued:
Given: N = 408 newtons, m = 51 kg, g = 9.8 m/s2
Unknown: ay
Solving (1) for ay:
The elevator could be (1) traveling upward with decreasing speed, or (2) traveling downward with increasing speed.
The change in velocity is DOWNWARD.
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PHY Ch 04b - Revised: 6/9/2010

33. Free Body Diagram
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34. This is not a methodolgy to solve for the acceleration
This is not a methodolgy to solve for the acceleration. It is just graphically demonstrating that the net force is ma
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35. Same problem but the applied force is angled up
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36. The normal force, N, is smaller in this case because the upward angled applied force reduces the effective weight of the sled.
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37. Equilibrium Problem
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38. Equilibrium Problem
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39. Equilibrium Problem
This is an example of three-vector equilibrium problem. It lends itself to a simple solution because the vector sum of the three vectors closes on itself (equilibrium) and forms a triangle
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40. Milk Carton Max static friction force Non-slip limit on applied force
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41. MFMcGraw
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42. Hanging Problems
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43. Hanging Picture
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44. Hanging Picture - Free Body Diagrammg T1
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45. Hanging Picture
Since this turned out to be a right triangle the simple trig functions are that is needed to find a solution.
If the triangle was not a right triangle then the Law of Sines would have been needed.
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PHY Ch 04b - Revised: 6/9/2010

46. MFMcGraw
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47. MFMcGraw
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48. Atwood Machine and Variations
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49. Atwood’s Machine
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50. A 2-Pulley Atwood Machine
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51. MFMcGraw
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52. Three Body Problem
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53. Incline Plane Problems
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54. Single Incline Plane Problem
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55. Double Incline Plane Problem
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56. Force Summary Friction Tension Pulleys Normal Forces Opposes motion
Proportional to normal force
Non-conservative
Static & dynamic
Normal Forces
Perpendicular to surface at point of contact.
Magnitude needed to maintain equilibrium
Tension
No mass
No stretching
Pulleys
Massless
No friction (bearing)
Tension in rope continuously changes direction
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010

57. Summary Newton’s Three Laws of Motion Drawing free body diagrams
Contact forces versus long-range forces
Different forces (gravity, friction, normal, tension, air resistance)
Application of Newton’s Second Law
MFMcGraw
PHY Ch 04b - Revised: 6/9/2010