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Short Version : 12. Static Equilibrium
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12.1. Conditions for Equilibrium (Mechanical) equilibrium = zero net external force & torque. Static equilibrium = equilibrium + at rest. Pivot point = origin of r i. is the same for all choices of pivot points Prob 55: For all pivot points
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Example 12.1. Drawbridge The raised span has a mass of 11,000 kg uniformly distributed over a length of 14 m. Find the tension in the supporting cable. Force F h at hinge not known. Choose pivot point at hinge. Another choice of pivot: Ex 15 y x 30 Tension T Gravity mg Hinge force F h 15 22 11
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GOT IT? 12.1. Which pair, acting as the only forces on the object, results in static equilibrium? Explain why the others don’t. (C) (A): F 0. (B): 0.
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12.2. Center of Gravity Total torque on mass M in uniform gravitational field : Center of gravity = point at which gravity seems to act for uniform gravitational field CG does not exist if net is not F net.
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Conceptual Example 12.1. Finding the Center of Gravity 1 st pivot 2 nd pivot Explain how you can find an object’s center of gravity by suspending it from a string.
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12.3. Examples of Static Equilibrium All forces co-planar: 2 eqs in x-y plane 1 eq along z-axis Tips: choose pivot point wisely.
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Example 12.2. Ladder Safety A ladder of mass m & length L leans against a frictionless wall. The coefficient of static friction between ladder & floor is . Find the minimum angle at which the ladder can lean without slipping. F net x : F net y : Choose pivot point at bottom of ladder. z : 0 90 y x mgmg n1n1 f S = n 1 i n2n2
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Example 12.3. Arm Holding Pumpkin Find the magnitudes of the biceps tension & the contact force at the elbow joint. F net x : F net y : Pivot point at elbow. z : ~ 10 M g y x MgMg mgmg T FcFc 80
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12.4. Stability Stable equilibrium: Original configuration regained after small disturbance. Unstable equilibrium: Original configuration lost after small disturbance. Stable equilibrium unstable equilibrium
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Stable Unstable Neutrally stable Metastable Equilibrium: F net = 0. V at global min V at local max V = const V at local min
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Stable equilibrium : PE at global min Metastable equilibrium : PE at local min
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Example 12.4. Semiconductor Engineering A new semiconductor device has electron in a potential U(x) = a x 2 – b x 4, where x is in nm, U in aJ (10 18 J), a = 8 aJ / nm 2, b = 1 aJ / nm 4. Find the equilibrium positions for the electron and describe their stability. Equilibrium criterion : or x = 0 is (meta) stable x = (a/2b) are unstable equilibria Metastable
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Saddle Point Equilibrium condition Saddle point stable unstable stable unstable
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