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5.2 - EQUILIBRIUM CONSTANT: K EQ Unit 5: Equilibrium
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EQUILIBRIUM CONSTANT For a general reaction... aA + bB ↔ cC + dD where a,b,c,d are balancing coefficients and A,B,C,D are substances, an equilibrium constant (K eq ) expression can be written as: K eq = [C] c x [D] d OR [A] a x [B] b Keq = [Products] coefficient [Reactants] coefficient This mathematical relationship is true for all equilibrium systems.
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USING THE K EQ EXPRESSION For the equilibrium reaction... H 2 (g) + I 2 (g) ↔ 2 HI (g) find the equilibrium constant (k eq ) if [H 2 ] = 0.022 M, [I 2 ] = 0.022 M, and [HI] = 0.156 M.
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FACTS ABOUT K EQ VALUES Since Keq is a constant for a reaction, it does not change unless the temperature of the system changes. It does not matter on the initial concentrations used to reach equilibrium, just the concentrations at equilibrium.
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FACTS ABOUT K EQ VALUES For example, the following data was taken during an experiment with the equation H 2 + I 2 ↔ 2 HI at equilibrium: Note that for this reaction, Keq is always the same (ignoring experimental error). Trial[HI][ H 2 ][ I 2 ]K eq 10.1560.0220 50.3 20.7500.106 50.1 31.000.8200.024250.4 41.000.02420.82050.4 51.560.220 50.3
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FACTS ABOUT K EQ VALUES When calculating Keq for a given reaction, we DO NOT INCLUDE substances in the liquid or solid phase. This is because the concentrations of substances in these phases do not change, but are constant. So, only include gaseous and aqueous states when calculating Keq.
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FACTS ABOUT K EQ VALUES Write the equilibrium expression for CaO(s) + CO 2 (g) CaCO 3 (s)
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SITUATION 1: IF K EQ IS VERY LARGE: The concentration of the products are much greater than the concentration of the reactants. This means that the reaction essentially ‘goes to completion’. That is, all or most of the reactants are used up to form the products. We will call a number greater than 10 10 very large. For example he decomposition of ozone, O 3 : 2 O 3 (g)↔ 3 O 2 (g) K eq = 2.0 × 10 57
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SITUATION 2: IF K EQ IS VERY SMALL: The concentration of the products are much smaller than the concentration of the reactants. This means the reaction does not occur to a great extent. That is, most of the reactants remain unchanged because only a few products are formed. We will call a value less than 10 -10 very small. For example, The production of nitrogen monoxide: N 2 (g) + O 2 (g)↔2 NO(g) K eq = 1.0 × 10 -25
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SITUATION 3: IF K EQ IS NEITHER VERY LARGE OR VERY SMALL: This means that there significant amounts of both products and reactants formed at equilibrium. We call values between 10 -10 and 10 10 neither very large or very small. For example, the reaction of carbon monoxide and water: CO(g) + H 2 O(g)↔CO 2 (g) + H 2 (g) K eq = 5.09
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