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Logical Effort A Method to Optimize Circuit Topology Swarthmore College E77 VLSI Design Adem Kader David Luong Mark Piper December 6, 2005
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Current Issues Facing Circuit Designers Wanting to optimize circuits for faster performance, inexperienced designers often encounter… –“Simulate-and-Tweak” loops –Incomplete intuition in design process –Uncertainty in decision-making
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Logical Effort as a Solution Quick method of circuit analysis –Circuit topology –Transistor sizing –Delay estimation Easy way to compare multi-stage designs “Back-of-the-envelope” calculation Provides intuition of circuit timing characteristics in complex circuitry
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How does it work? Assumes RC model of a transistor d = gh + p d = propagation delay gh = effort delay g = logical effort h = electrical effort = Cout/Cin p = parasitic delay
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Defining Logical Effort Ratio of the input capacitance of the gate to the input capacitance of an inverter that can deliver the same output current Measure of a gate to drive a particular fan-out relative to an inverter
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Visualizing Logical Effort
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Application of Logical Effort Estimating Delay Propagation d = g h + p INVERTER NAND
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Multi-Stage Design and Logical Effort Often circuits are more complicated than an inverter or a NAND gate Same framework applies with the modification…
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Logical Effort and Transistor Sizing Interested in choosing transistor sizing to minimize stage and overall delay f (min) = g(i) * h(i) = F 1/N Delay equation becomes… In the end…
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Application of Transistor Sizing How do we choose stage capacitances given we want to minimize propagation delay?
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Optimal Number of Gates Path Effort F Optimal NMinimum Delay, D Stage Effort, f 0-5.8311.0-6.80-5.8 5.82-22.326.8-11.42.4-4.7 22.3-82.2311.4-16.02.8-4.4 82.2-300416.0-20.73.0-4.2 300-1090520.7-25.33.1-4.1 1090-3920625.3-29.83.2-4.0 Rule of thumb is … Note that single gate does not always translate to minimized delay
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Example: The Implementation Problem Which do you choose?
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Using Logical Effort… Option 1: Path logic effort G = 1 * 6/3 * 1 = 2 Path Branch Effort B = 1 Path electrical effort H = C out /C in = 8C/C = 8 Path Stage effort = F = GBH = 2*1*8 = 16 D min = N*F1/N+P = 3*(16)1/3 + (1+4*1 + 1) = 3*3.25 + 6 = 13.5
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Using Logical Effort… Option 2: Path logic effort G = 1 * 4/3 * 5/3 = 20/9 Path Branch Effort B = 1 Path electrical effort H = C out /C in = 8C/C = 8 Path Stage effort = F = GBH = 20/9*1*8 = 160/9 D min = N*F1/N+P = 3*(160/9)1/3 + (1+2*1 + 2) = 3*3.25 + 5 = 12.8
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Using SPICE…
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Example: Choosing the Optimal N The Buffer Problem Must drive 64 parallel inverters Choose 1, 3, or 5 series inverter stages to drive the load?
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finding optimal #of stages N531 f2.3464 D16.51565
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1 inverter
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3 inverters
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5 inverters
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all together
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Problems with logical effort It’s only an approximation –But a good one It does not guarantee optimal solution –but gets quite close Chicken and egg problem –chicken Built for speed –Does not account for power consumption and physical size
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So What Have We Learned? Logical Effort… –Provides method to quickly determine speed of design topologies for comparison –Displays changes to parameter tweaking
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I agree with stupid It’s so… logical! now that makes sense!
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