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Algebraic Fractions with monomial Denominators
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A monomial is a number, a variable, or a product of a number and variables. The degree of a monomial is the sum of the exponents of the variables
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Objective: Simplify fractions using the highest common factor.
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5-Minute Check Find the HCF of each set of numbers or monomials. 1.22, 55
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5-Minute Check Find the HCF of each set of numbers or monomials. 1.22, 5511
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318106 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 3.15, 18, 30 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 3.15, 18, 303 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 3.15, 18, 30 4.12ab 3, 16a 4 b 2 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 3.15, 18, 30 4.12ab 3, 16a 4 b 2 4ab 2 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 3.15, 18, 30 4.12ab 3, 16a 4 b 2 5.15mnp, 45mp 3, 90m 3 n 4 5-Minute Check
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Find the HCF of each set of numbers or monomials. 1.22, 55 2.106, 318 3.15, 18, 30 4.12ab 3, 16a 4 b 2 5.15mnp, 45mp 3, 90m 3 n 4 15m 5-Minute Check
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Simplifying Fractions Example a.Write 63/105 in simplest form. 63 = 7*3*3 The HCF of 63 and 105 is 3*7 or 21. 105 7*5*3
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4-6 Simplifying Fractions Example a.Write 63/105 in simplest form. 63 = 7*3*3 The HCF of 63 and 105 is 3*7 or 21. 105 7*5*3 Divide the numerator and the denominator by 21.
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Simplifying Fractions Example a.Write 63/105 in simplest form. 63 = 7*3*3 The HCF of 63 and 105 is 3*7 or 21. 105 7*5*3 Divide the numerator and the denominator by 21. Since the HCF of 3 and 5 is 1, the fraction is in simplest form.
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Example b.Simplify. Assume that x and y are not equal to zero. 15x 2 y 2 35xy 2 Simplifying Fractions
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4-6 Simplifying Fractions The HCF of 15x 2 y 2 and 35xy 2 is 5*x*y*y. Example b.Simplify. Assume that x and y are not equal to zero. 15x 2 y 2 35xy 2 15x 2 y 2 35xy 2
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Divide the numerator and denominator by 5xy2. 4-6 Simplifying Fractions The HCF of 15x 2 y 2 and 35xy 2 is 5*x*y*y. Example b.Simplify. Assume that x and y are not equal to zero. 15x 2 y 2 35xy 2 15x 2 y 2 35xy 2
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Since the HCF of 3x and 7 is 1, the fraction 3x / 7 is in simplest form. Divide the numerator and denominator by 5xy2. 4-6 Simplifying Fractions The HCF of 15x 2 y 2 and 35xy 2 is 5*x*y*y. Example b.Simplify. Assume that x and y are not equal to zero. 15x 2 y 2 35xy 2 15x 2 y 2 35xy 2
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4-6 Simplifying Fractions I need two volunteers to rewrite the fraction below in simplest form. 24 60 40 100
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Simplifying Fractions Rewrite the fraction below in simplest form. 24 60 40 100 Each individual now needs to find other fractions that when reduced equals 2/5.
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