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Published byGregory Dominick West Modified over 9 years ago
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Section 3.1 The Determinant of a Matrix
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Determinants are computed only on square matrices. Notation: det(A) or |A| For 1 x 1 matrices: det( [k] ) = k
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Determinants are computed only on square matrices. Notation: det(A) or |A| For 1 x 1 matrices: det( [k] ) = k For 2 x 2 matrices: For larger matrices, we define a determinant in terms of cofactors.
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Def. If A is a square matrix, then the ij minor, denoted M ij, is the determinant of the matrix obtained by deleting the i th row and the j th column of A. The ij cofactor, denoted C ij, is given by C ij = (-1) i+j M ij
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Ex. Find C 23 and C 13 for the matrix
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Computing determinants by the cofactor expansion. The determinant of an n x n matrix A can be computed by expanding along the i th row: The determinant of an n x n matrix A can be computed by expanding along the j th column:
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Ex. Compute the determinant of
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Triangular matrices: If A is a triangular matrix then det(A) = a 11 a 22 a 33 · · · a nn
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Triangular matrices: A = det(A) =
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Section 3.2 Evaluation of a Determinant Using Elementary Operations
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We computed determinants by the “cofactor expansion method” in the previous section. We shall introduce a new method which involves placing a given matrix into triangular form via elementary row operations. Why even bother with a second method for computing determinants if we already have one that works?
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There are some problems in math that are theoretically simple but practically impossible. Think, for example, of a determinant of a 50 x 50 matrix. When computed by expanding by cofactors, this involves : 50 different 49 x 49 determinants. Each one of these 49 x 49 determinants requires 49 different 48 x 48 determinants. Each one of these 48 x 48 determinants requires 48 different 47 x 47 determinants. Each one of these.... We end up with a total of 50∙49∙48∙47∙ ∙ ∙6∙5∙4∙3 different 2 x 2 determinants (this is about 10 64 2 x 2 determinants that must be calculated). Even if a computer could calculate one million 2 x 2 determinants per second, it would take about 10 58 seconds (about 10 50 years) to finish calculating our 50 x 50 determinant. (According to the big bang theory, the universe is only about 10 10 years old.)
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Order nCofactor Expansion Row Reduction Additions Multiplications Additions Multiplications 3 5 9 5 10 5119205 30 45 10 3,628,799 6,235,300285 339
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Suppose that B is the triangular matrix obtained from A through row operations. We need to exploit the relationship between det(B) and det(A). To do so, we must first see how each row operation affects the value of a determinant.
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Theorem: Suppose that A* was obtained from A through a single elementary row operation. i. If that operation was R i ↔ R j then we have: det(A*) = –det(A). ii. If that operation was R i + cR j → R i then we have: det(A*) = det(A). iii. If that operation was cR i → R i then we have: det(A*) = c det(A).
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Ex. Verify iii. above is true on the following matrices:
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Ex. Suppose. Compute the determinants of the following matrices. (a)
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Ex. Suppose. Compute the determinants of the following matrices. (b)
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Ex. Suppose. Compute the determinants of the following matrices. (c)
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Ex. Use elementary row operations to compute the determinant of
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If det(A) = 0, what do we know about the triangular matrix obtained by applying row operations on A?
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If det(A) ≠ 0, then there is only one solution to a system represented by AX = B.
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Section 3.3 Properties of Determinants
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Let and. Then AB is. Compute: det(A) det(B) det(AB)
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Theorem: Suppose A and B are n x n matrices and c is a scalar. 1. det(AB) = _________________ 2. det(cA) = _________________ 3. det(A T ) = _________________ det(A) det(B) c n det(A) det(A)
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Theorem: det(A -1 ) = ___________
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Theorem: If A is invertible then det(A) ≠ 0.
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Theorem: Let A be an nxn matrix. The following are equivalent: 1. A is invertible. 2. AX = B has a unique solution. 3. AX = O has only the trivial solution. 4. rref(A) = I. 5. det(A) ≠ 0.
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Section 3.5 Applications of Determinants
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Cramer’s Rule:
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Consider the following system of linear equations represented by the matrix equation AX = B: a 11 x 1 + a 12 x 2 + · · · + a 1n x n = b 1 a 21 x 1 + a 22 x 2 + · · · + a 2n x n = b 2 a 31 x 1 + a 32 x 2 + · · · + a 3n x n = b 3 : :: a n1 x 1 + a n2 x 2 + · · · + a nn x n = b n Now, think of A in terms of its column vectors: A = [ a 1 a 2 a 3 · · · a n ] Define A 1 = [ b a 2 a 3 · · · a n ] A 2 = [ a 1 b a 3 · · · a n ] A 3 = [ a 1 a 2 b · · · a n ] : :: A n = [ a 1 a 2 a 3 · · · b ]
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If det(A) ≠ 0 then there is a unique solution to AX = B which can be computed by:
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Ex. Use Cramer’s rule to solve the following: x – y + 3z = 2 2x + y – z = 5 –x + y – 4z = –4
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