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RESISTANCE AND OHM’S LAW. A closer look at insulators and conductors Conductors: electrons loosely bound to nuclei –Electrons flow easily when voltage.

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Presentation on theme: "RESISTANCE AND OHM’S LAW. A closer look at insulators and conductors Conductors: electrons loosely bound to nuclei –Electrons flow easily when voltage."— Presentation transcript:

1 RESISTANCE AND OHM’S LAW

2 A closer look at insulators and conductors Conductors: electrons loosely bound to nuclei –Electrons flow easily when voltage is applied –Eg: most metals Insulators: electrons tightly bound to nucleus –Electrons do not flow easily –Eg: glass and rubber

3 Resistance A measure of how difficult it is for current to flow through a material (Resists or slows down charges, which reduces current) Depends on material, thickness, length and temperature The lower the resistance, the better the conductor

4 Examples of Resistors Light bulb filament (thin wire that glows) Heating elements on stove or in oven Heating wires inside a toaster Resistors convert electrical energy to heat or light

5 Rheostats Variable resistors Used to adjust the amount of current flowing Examples: temperature control on stove dimmer switch volume control knob

6 Calculating Resistance Resistance can be calculated from voltage and current Mathematical relationship is called Ohm’s Law (after Georg Simon Ohm)

7 OHM’S LAW Resistance is measured in Ohms (  NOTE: Must use these base units, not milliAmps, kiloVolts etc.

8 3 Forms of Ohm’s Law

9 Memory Aids for Ohm’s Law V

10 Finding Resistance - cover up R (V over I) - divide If V = 12 Volts And I = 2 Amps V

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12 - cover the I (V over R) divide If V = 24 V and R = 8  V Finding Current

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14 Finding Voltage - cover the V (I beside R) multiply If I = 500 mA = 0.5 A and R = 20 

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17 Examples A small portable stove operates from a 120V outlet. When it is in use, 6A flow through it. What is the resistance of the heating element on the stove? R= V/I = 120V/6A = 20 Ω

18 The filament of a certain light bulb has a resistance of 96 Ω. To operate at its proper brightness, it needs a current of 1.25A to pass through it. What voltage must be applied to this light bulb to make it work? V = I R = 1.25 A x 96 Ω = 120V

19 If a kettle is operated from a 120V outlet and its heating element has a resistance of 10 Ω, what current is in the heating element? I = V / R = 120V / 10 Ω = 12 A

20 Ohm’s Law Worksheet For each question: (example) Show formula V = I x R Show work = 2 A x 6  Include correct units = 12 V


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