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Free Radical Chlorination. Experimental Evidence Helps to Determine Mechanism Chlorination does not occur at room temperature in the dark. The most effective.

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Presentation on theme: "Free Radical Chlorination. Experimental Evidence Helps to Determine Mechanism Chlorination does not occur at room temperature in the dark. The most effective."— Presentation transcript:

1 Free Radical Chlorination

2 Experimental Evidence Helps to Determine Mechanism Chlorination does not occur at room temperature in the dark. The most effective wavelength of light is blue that is strongly absorbed by Cl 2 gas. The light-initiated reaction has a high quantum yield (many molecules of product are formed from each photon of light).

3 Free Radical Species are Constantly Generated Throughout the Reaction Propagation

4 Termination: Reaction of any 2 Radicals

5 Chlorination of Propane

6 H’s are not abstracted at the same rate. For secondary: 70%/4H = 17.5 For primary: 30%/6H = 5.0 Therefore… Relative rate of H abstraction for 1 o : 2 o is 1 : 3.5

7 Chlorination of Methylpropane

8 3 o Radicals are Easiest to Form

9 Tertiary H’s removed five times more readily than primary H’s in chlorination reactions Relative reactivity of 1 o H abstraction: 65% / 9H = 7.2 Relative reactivity of 3o H abstraction: 35% / 1H = 35 Therefore… Relative rate of H abstraction for 1 o : 3 o 1:5

10 Stability of Free Radicals

11

12 Bromination is Very Selective

13 RDS in Bromination is highly endothermic

14 Consider the free radical monochlorination of 2,2,5-trimethylhexane. Draw all of the unique products (ignore stereoisomers; use zig-zag structures please) and predict the ratio or percent composition of the products. The relative reactivity of H abstraction in a chlorination reaction: 1 o : 2 o : 3 o = 1: 3.5: 5

15 2.(12) Consider the free radical monochlorination of 1,4-dimethylcyclohexane. The reaction affords three different products (all C 8 H 15 Cl). In this reaction, the rates of hydrogen abstraction of primary : secondary : tertiary are 1 : 3.5 : 5. Draw the three products and predict the percent composition (or ratio) of the product mixture. (Disregard cis / trans isomers for this problem.)


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