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Modeling with Polynomial Functions

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1 Modeling with Polynomial Functions
Section 6.9 Modeling with Polynomial Functions

2 Using Finite Differences
You know that two points determine a line, three points determine a parabola and four points determine the graph of a cubic function. To decide whether y-values for equally-spaced x-values can be modeled by a polynomial function, you can use finite differences.

3 Finding Finite Differences
We find differences the same way we found them in algebra 1. Remember, we are only trying to see if there is a pattern with the sequence of numbers. We must find a constant difference in order to use a polynomial model.

4 Using Differences If the first difference is constant, the function is a linear model. If the second difference is constant, the function is a quadratic model. If the third difference is constant, the function is a cubic model.

5 Ex 1a 1.1 Using Differences to Identify Patterns Find the next three terms in the sequence by using constant differences: 1, 3, 5, 7, 9, ... 11 13 15 2 2 2 2 First differences 2 2 2 Add 2 to each term to find the next term: 9 + 2 = 11 = 13 = 15

6 Ex 1b 1.1 Using Differences to Identify Patterns Find the next three terms in the sequence by using constant differences: 80, 73, 66, 59, 52, ... 45 38 31 -7 -7 -7 -7 First differences -7 -7 -7 Subtract 7 from each term to find the next term: = 45 = 38 = 31

7 Ex 2a: Find the next three terms: 1, 4, 9, 16, 25
1.1 Using Differences to Identify Patterns Find the next three terms: 1, 4, 9, 16, 25 Find the first differences. 36 49 64 3 5 7 9 11 13 15 1st differences 2 2 2 2 2 2 2nd differences

8 Ex 2b: Find the next three terms: 37, 41, 48, 58, 71, …
1.1 Using Differences to Identify Patterns Find the next three terms: 37, 41, 48, 58, 71, … Find the first differences. 87 106 128 4 7 10 13 16 19 22 1st differences 3 3 3 3 3 3 2nd differences

9 Writing a Cubic Function
Write the cubic function whose zeros are -3, 2 and 5, and passes through (0, -15) First, write the function in intercept form: f(x) = a(x + 3)(x – 2)(x – 5) Solve for a by substituting the point in for (x,y) -15 = a(0 +3)(0-2)(0-5) -15 = 30a a = - ½ f(x) = - ½ (x + 3)(x – 2)(x – 5)

10 Example: Find a polynomial function that gives the nth triangular pyramidal number:
F(1) = 1, F(2) = 4, F(3)=10, F(4)=20, F(5)=35, F(6)= 56, F(7) = 84 First, start by finding the constant difference: V V V V V V

11 V V V V V V V V V V V V V V V Since the third differences are constant, we know it can be model by a cubic function.

12 Cubics are of the form: f(x) = ax3 + bx2 + cx + d Now, substitute the first four terms into the equation to produce a system of four equations in four variables.

13 Simplify the system: Use matrices on the calculator to solve the system for a, b, c, and d.

14 Write the equation: a = 1/6, b = ½, c = 1/3, d = 0 So,

15 You try an example: Write the equation for the following:
1 2 3 4 5 6 F(x) 20 58 122 218 352

16 You try an example: Write the equation for the following:
1 2 3 4 5 6 F(x) 20 58 122 218 352

17 Cubic Regressions on Calculator
You can also use the graphing calculator to find the equation of a cubic. Put in the data into L1 and L2 (just like linear regressions). Select CubicReg function to find the equation.

18 Find the polynomial model for the data:
X 9 11 13 15 17 19 21.5 Y 6.43 7.61 8.82 9.86 10.88 12.36 15.24

19 Assignment Section 6.9: page 383 – 385 # 14, 17, 23 – 31 odd, 33, 47


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