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Joint Linkage and Linkage Disequilibrium Mapping
Key Reference Li, Q., and R. L. Wu, 2009 A multilocus model for constructing a linkage disequilibrium map in human populations. Statistical Applications in Genetics and Molecular Biology 8 (1): Article 18.
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Genetic Designs for Mapping
Controlled crosses – Backcross, F2, full-sib family, … (linkage) Unrelated (random) individuals from a natural population (linkage disequilibrium) Cases and controls from a natural population Unrelated (random) families from a natural population (linkage and LD) Related (non-random) families from a natural population (linkage, LD and identical-by-descent) Family designs are increasingly used for genetic studies because of much information contained.
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Natural Population Consider two SNPs 1 (with two allele A and a) and 2 (with two alleles B and b) The two SNPs are linked with recom. frac. r The two SNPs form four haplotypes, AB, Ab, aB, and ab Prob(A) = p, Prob(B) = q, linkage disequilibrium = D. We have haplotype frequencies as
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Diagrammatic Presentation
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Family Design: family number and size
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Mating frequencies of families and offspring genotype frequencies per family
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HWE assumed Can you figure out where this assumption is needed?
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Segregation of double heterozygote
Overall haplotype frequencies produced by this parent are calculated as 1/2ω1 for AB or ab and 1/2ω2 for Ab or aB
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A Joint Probability Mother genotypes (Mm) Father genotypes (Mf )
Offspring genotypes (Mo) P(Mm,Mf,Mo) = P(Mm,Mf)P(Mo|Mm.Mf) = P(Mm)P(Mf)P(Mo|Mm,Mf)
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A joint two-stage log-likelihood
Let unknown parameters
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Upper-stage Likelihood
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EM algorithm for Θ E step M step
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Lower-stage Likelihood
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EM algorithm for r E step - calculate the probability with which a considered haplotype produced by a double heterozygote parent is the recombinant type using
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E step (cont’d) Calculate the probability with which a double heterozygote offspring carries recombinant haplotypes by
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M step where m equals the sum of the following terms:
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Hypothesis tests Linkage and Linkage disequilibrium H0: r = 0 and D = 0 H1: At least one equality does not hold LR = -2(log L0 – log L1) Critical threshold x2 (df=2)
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Hypothesis tests Sex-specific difference in population structure
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Hypothesis test Sex-specific difference in the recombination fraction
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Simulation
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Power
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Power
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Conclusions The model can jointly estimate the linkage and linkage disequilibrium between two markers - LD from parents - Linkage from offspring The model can draw a LD map to study the evolution of populations and high-resolution mapping of traits
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