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Torsion  Introduction -- Analyzing the stresses and strains in machine parts which are subjected to torque T Circular -- Cross-section Non-circular.

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Presentation on theme: "Torsion  Introduction -- Analyzing the stresses and strains in machine parts which are subjected to torque T Circular -- Cross-section Non-circular."— Presentation transcript:

1 Torsion  Introduction -- Analyzing the stresses and strains in machine parts which are subjected to torque T Circular -- Cross-section Non-circular Irregular shapes -- Material (1) Elastic (2) Elasto-plastic -- Shaft (1) Solid (2) Hollow

2 3.1 Introduction T is a vector  Two ways of expression
-- Applications: a. Transmission of torque in shafts, e.g. in automobiles

3 Assumptions in Torque Analysis:
a. Every cross section remains plane and undistorted. b. Shearing strain varies linearly along the axis of the shaft.

4 3.2 Preliminary Discussion of the Stresses in a Shaft
Where  = distance (torque arm) Since dF =  dA The stress distribution is Statically Indeterminate. Free-body Diagram

5 -- Must rely on “deformation” to solve the problem.
Analyzing a small element:

6 3.3 Deformations in a Circular Shaft
 =  (T, L) -- the angle of twist (deformation) Rectangular cross section warps under torsion

7 A circular plane remains circular plane

8 Determination of Shear Strain 
(in radians) The shear strain   

9  = c = radius of the shaft
Since

10 3.4 Stresses in the Elastic Range
Hooke’s Law Therefore, (3.6)

11

12 (3.1) (3.6) But (3.9) Therefore, Or,

13 Substituting Eq. (3.9) into Eq. (3.6)
(3.10) (3.9) These are elastic torsion formulas. For a solid cylinder: For a hollow cylinder:

14 (3-13) Since

15 3.5 Angle of Twist in the Elastic Range
(3.3) (3.15) Therefore, Eq. (3.3) = Eq. (3.15)  Hence,

16 For Multiple-Section Shafts:

17 Shafts with a Variable Circular Cross Section

18 3.6 Statically Indeterminate Shafts
-- Must rely on both Torque equations and (2) Deformation equation, i.e. Example 3.05

19 3.7 Design of Transmission Shafts
-- Two Parameters in Transmission Shafts: a. Power P b. Speed of rotation where  = angular velocity (radians/s) = 2  = frequency (Hz) [N.m/s = watts (W)] (3.21)

20 (3.21) (3.9) Therefore, For a Solid Circular Shaft:


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