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Published bySydney Beasley Modified over 9 years ago
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They are boring! They have no use in life. STEREOTYPES ABOUT PARALLEL AND PERPENDICULAR LINES
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PARALLEL AND PERPENDICULAR LINES ARE EVERYWHERE
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y = mx + b m is the slope of the line b is the y-intercept REVIEW: SLOPE INTERCEPT FORM Life is easy when you’re in slope intercept form
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y = mx + b The y-intercept is the y value when x = 0. Visually, the y-intercept is y value when the line crosses the y axis http://www.mathsisfun.com/data/function- grapher.php Y -INTERCEPT
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m y = mx + b Slope Slider Slope of vertical lines? SLOPE
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3y = 6x + 9 5y = 10x y = -1 x = 3 IDENTIFYING THE SLOPE AND THE Y-INTERCEPT
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y = mx + b Given the slope, m, and a point, (x, y), then we can find b, the y-intercept. b = y – mx Once we find b, we can find the equation of the line. REVIEW: FINDING THE EQUATION OF THE LINE GIVEN A SLOPE AND A POINT ON THE LINE
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p = (-2, 2) m = 4 p = (-3, 4) m = -2 p = (-2, 2/3) m = -4/3 PRACTICE: FINDING THE EQUATION OF THE LINE GIVEN THE SLOPE AND A POINT ON THE LINE
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1. Graph line segments. Be sure that each endpoint is an integer coordinate, such as (1,3) or (-3,0) Compute and record their slope. 2. Then graph a parallel line to each of the three line segments. Compute and record the slopes of the parallel lines. Then delete the parallel lines. 3. Then graph a perpendicular line to each of the three line segments. Compute and record the slopes of the perpendicular lines. GRAPHING ACTIVITY
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PARALLEL LINES Two lines are parallel The lines never intersec t Slopes are equal
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y = (1/3)x + 2 y – 1 = 6x 2y = 5x + 3 4y = 8x y = 6 x = -3 FIND THE SLOPE OF A PARALLEL LINE
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PERPENDICULAR LINES Two lines are perpendicular The lines intersect at right angle Slopes are negative reciprocals
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y = -3x – 2 y = (1/3)x + 2 y – 1 = 6x 2y = 5x + 3 y = 6 x = -3 FIND THE SLOPE OF A PERPENDICULAR LINE
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y = (1/3)x + 2, p = (2, -3) 2y = 5x + 3, p = (1/2, 2/3) y = 6, p = (6, 0) x = -3, p = (1, 2) FIND THE EQUATION OF THE PARALLEL LINE THAT PASSES THROUGH THE GIVEN POINT.
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y = -3x – 2, p = (-1, 4) 4y = 8x, p = (1, 1/3) y = 6, p = (6, 0) x = -3, p = (1, 2) FIND THE EQUATION OF THE PERPENDICULAR LINE THAT PASSES THROUGH THE GIVEN POINT.
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