Presentation is loading. Please wait.

Presentation is loading. Please wait.

Motion on an Inclined Plane Lesson #6. Example Problem A skier weighing 562 N is resting on an incline of 30 degrees above the horizontal, with her poles.

Similar presentations


Presentation on theme: "Motion on an Inclined Plane Lesson #6. Example Problem A skier weighing 562 N is resting on an incline of 30 degrees above the horizontal, with her poles."— Presentation transcript:

1 Motion on an Inclined Plane Lesson #6

2 Example Problem A skier weighing 562 N is resting on an incline of 30 degrees above the horizontal, with her poles planted. Find the component of her weight that is parallel to the incline and the component that is perpendicular to the incline. FgFg F gy F gx y x 30 ̊ F gy y-component 562 N cos 30 = F gy = - 487 N F gx x-component 562 N sin 30 = F gx = 281 N F gx

3 Practice Problem A 100 kg crate is sitting on a ramp that is tipped 50 ̊ to the horizontal. If the crate is at rest on the ramp, what are the x and y components of the force of gravity? FgFg F gy F gx y x 50 ̊ F gx x-component 980 N sin 50 = F gx = 751 N F gx FfFf F gy y-component 980 N cos 50 = F gy = -630 N

4 Assessment Read p. 132-135 Read p. 132-135 p. 133 #34 p. 133 #34 p. 143 #99 p. 143 #99


Download ppt "Motion on an Inclined Plane Lesson #6. Example Problem A skier weighing 562 N is resting on an incline of 30 degrees above the horizontal, with her poles."

Similar presentations


Ads by Google