1. IB Physics 11 Mr. Jean December 4 th, 2013

2. The plan:

3. –If object 1 loses 75 units of momentum, then object 2 gains 75 units of momentum. Yet, the total momentum of the two objects (object 1 plus object 2) is the same before the collision as it is after the collision. The total momentum of the system (the collection of two objects) is conserved

4. Law of Conservation of Momentum:

5. Collisions commonly occur in contact sports (such as football) and racket and bat sports (such as baseball, golf, tennis, etc.). Consider a collision in football between a fullback and a linebacker during a goal-line stand. The fullback plunges across the goal line and collides in midair with the linebacker. The linebacker and fullback hold each other and travel together after the collision. The fullback possesses a momentum of 100 kg*m/s, East before the collision and the linebacker possesses a momentum of 120 kg*m/s, West before the collision. The total momentum of the system before the collision is 20 kg*m/s, West (review the section on adding vectors if necessary). Therefore, the total momentum of the system after the collision must also be 20 kg*m/s, West. The fullback and the linebacker move together as a single unit after the collision with a combined momentum of 20 kg*m/s. Momentum is conserved in the collision.

6. Now suppose that a medicine ball is thrown to a clown who is at rest upon the ice; the clown catches the medicine ball and glides together with the ball across the ice. The momentum of the medicine ball is 80 kg*m/s before the collision. The momentum of the clown is 0 m/s before the collision. The total momentum of the system before the collision is 80 kg*m/s. Therefore, the total momentum of the system after the collision must also be 80 kg*m/s. The clown and the medicine ball move together as a single unit after the collision with a combined momentum of 80 kg*m/s. Momentum is conserved in the collision.

7. One Dimensional Collisions: In a one dimensional collision both the magnitude and the direction of the momentum must be conserved. For complex momentum situations break all momentums into components and then sum the components. This too will conserve momentum.

8. Collisions: Collisions can be classified according to the energy interaction that takes place: Elastic collision  kinetic energy is conserved Inelastic collision  kinetic energy is not conserved Perfectly inelastic collision  objects stick together and have the same velocity.

9. Example: An old lady driving a 2.5x10 3 kg H2 Hummer drives into the back of your 1.0x10 3 kg Lotus Elan. The two cars stick together. What is their velocity after the collision if the old lady was originally travelling at 8.0m/s?

11. Example #2: The cue ball collides with the ‘8’ ball. The cue ball has twice as much mass as the ‘8’ ball. The objects do not stay attached. –What is the velocity of the ‘8’ ball? –Is this collision realistic? (Why or why not?)

13. Cannon Recoil: A 2000kg cannon contains a 100kg armour piercing shell. The cannon fires the projectile horizontally with a velocity of 1000m/s. –What is the velocity of the cannon after the shot?

14. Before:After:

16. “Loose Cannon”: An unpredictable person or thing, liable to cause damage if not kept in check by others. Also a place to eat in Halifax on Argyle Street.

17. Rifle Recoil:.50 Cal Rifle “Surprising Recoil”

18. The momentum before firing is zero. After firing, the net momentum is still zero because the momentum of the cannon is equal and opposite to the momentum of the cannonball. Conservation of Momentum

19. The force on the cannonball inside the cannon barrel is equal and opposite to the force causing the cannon to recoil. The action and reaction forces are internal to the system so they don’t change the momentum of the cannon-cannonball system. Before the firing, the momentum is zero. After the firing, the net momentum is still zero. Net momentum is neither gained nor lost. Conservation of Momentum

20. Momentum has both direction and magnitude. It is a vector quantity. The cannonball gains momentum and the recoiling cannon gains momentum in the opposite direction. The cannon-cannonball system gains none. The momenta of the cannonball and the cannon are equal in magnitude and opposite in direction. No net force acts on the system so there is no net impulse on the system and there is no net change in the momentum. Conservation of Momentum

21. In every case, the momentum of a system cannot change unless it is acted on by external forces. When any quantity in physics does not change, we say it is conserved. Conservation of Momentum

22. The law of conservation of momentum describes the momentum of a system: If a system undergoes changes wherein all forces are internal, the net momentum of the system before and after the event is the same. Examples are: atomic nuclei undergoing radioactive decay, cars colliding, and stars exploding. Conservation of Momentum

23. a.A moving ball strikes a ball at rest. 8.5 Collisions

24. a.A moving ball strikes a ball at rest. b.Two moving balls collide head-on. 8.5 Collisions

25. a.A moving ball strikes a ball at rest. b.Two moving balls collide head-on. c.Two balls moving in the same direction collide. 8.5 Collisions

26. Inelastic Collisions A collision in which the colliding objects become distorted and generate heat during the collision is an inelastic collision. Momentum conservation holds true even in inelastic collisions. Whenever colliding objects become tangled or couple together, a totally inelastic collision occurs. 8.5 Collisions

27. In an inelastic collision between two freight cars, the momentum of the freight car on the left is shared with the freight car on the right. 8.5 Collisions

28. The freight cars are of equal mass m, and one car moves at 4 m/s toward the other car that is at rest. net momentum before collision = net momentum after collision (net mv) before = (net mv) after (m)(4 m/s) + (m)(0 m/s) = (2m)(v after ) 8.5 Collisions

29. Twice as much mass is moving after the collision, so the velocity, v after, must be one half of 4 m/s. v after = 2 m/s in the same direction as the velocity before the collision, v before. 8.5 Collisions

30. do the math! Consider a 6-kg fish that swims toward and swallows a 2-kg fish that is at rest. If the larger fish swims at 1 m/s, what is its velocity immediately after lunch? Momentum is conserved from the instant before lunch until the instant after (in so brief an interval, water resistance does not have time to change the momentum). 8.5 Collisions

32. do the math! 8.5 Collisions

33. do the math! Suppose the small fish is not at rest but is swimming toward the large fish at 2 m/s. 8.5 Collisions

34. do the math! Suppose the small fish is not at rest but is swimming toward the large fish at 2 m/s. If we consider the direction of the large fish as positive, then the velocity of the small fish is –2 m/s. 8.5 Collisions

35. do the math! The negative momentum of the small fish slows the large fish. 8.5 Collisions

36. do the math! If the small fish were swimming at –3 m/s, then both fish would have equal and opposite momenta. Zero momentum before lunch would equal zero momentum after lunch, and both fish would come to a halt. 8.5 Collisions

37. do the math! Suppose the small fish swims at –4 m/s. The minus sign tells us that after lunch the two-fish system moves in a direction opposite to the large fish’s direction before lunch. 8.5 Collisions

38. Example of a perfectly Inelastic collision:

42. Questions to do:

52. Challenge Question: