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Momentum and its Conservation Chapter 9
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Momentum Objects in motion are said to have a momentum.Objects in motion are said to have a momentum. Momentum depends on:Momentum depends on: VelocityVelocity MassMass
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Momentum Momentum is a vector. MagnitudeMagnitude DirectionDirection
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Momentum Momentum ( p unit:kgm/s ) A property a moving object has because of mass and velocity.
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Momentum p=mv
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Momentum of Systems Momentum of the ball changes!!!
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Momentum of Systems Momentum of the pins change!!
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Momentum of Systems Momentum of the ball and pins do not change!!
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Impulse
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Impulse Impulse Force applied on an object in a given amount of time
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Impulse FΔt
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Acceleration Δv Δt a=
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Newton’s 2 nd Law F=ma Δv Δt F=m
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Impulse / Momentum FΔt = m Δv Change in Momentum Impulse
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ρ = m Δv ρ = m (v 1 -v 2 ) ρ = m v 1 -mv 2
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Example A 100kg running back is moving at a speed of 12m/s is stopped by a linebacker in 0.5s. How much force did the linebacker apply to the running back?
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Example Given: v 1 = 12 m/s v 2 = 0 m/s v 2 = 0 m/s m = 100kg m = 100kg Δt = 0.5s Find:F = ?
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Equation: FΔt = m Δv F = m Δv F = m Δv Δt Δt F = m v 1 –v 2 F = m v 1 –v 2 Δt Δt F = (100kg)(12m/s – 0m/s) 0.5s 0.5s F = 2400N
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Homework Practice Problems 2,3,4,13,14 & 15 Pages: 217 Due: 1/9/07
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Conservation of Momentum The total momentum of a group of objects does not change unless outside forces act on the objects. The momentum before a collision is equal to the momentum after the collision.
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Total Momentum Before = Total Momentum After
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Example A 2000kg car going 25m/s rear ends an 500kg car going 15m/s on ice moving in the same direction. The two cars lock bumpers at collision. How fast does the wreckage move immediately after collision?
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Example
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Example Given: m 1 = 2000kg v 1 = 25m/s m 2 = 500kg v 2 =15m/s m 1,2 =2500kg Find: v 1,2 = ? Total Momentum Before = Total Momentum After
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Example ρ before = ρ after ρ 1 + ρ 2 = ρ 1,2 m 1 v 1 + m 2 v 2 = m 1,2 v 1,2
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Example (2000kg)(25m/s)+(500kg)(15m/s)= v 1,2 (2500kg ) m 1 v 1 +m 2 v 2 = v 12 m 12 V 12 = 23m/s
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Homework Practice Problems 7-12 Page: 210 Due: 1/7/02
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Explosion
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Explosion ρ before = ρ after ρ before = ρ cannon + ρ ball ρ before = 0
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Explosion 0 = ρ cannon + ρ ball ρ cannon = ρ ball mv cannon = mv ball
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Explosion - Example A student, with a mass of 50kg, is standing in a boat, throws a 10kg medicine ball. The ball has a velocity of 10m/s. What is the speed of the student after the throw?
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Explosion - Example Given: m s = 50kg m b = 10kg v b = 10m/s Find: v s = ?
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Explosion - Example ρ before = ρ after ρ before = ρ student + ρ ball ρ before = 0 ρ student = ρ ball
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Explosion - Example m s v s = v b m b v s = m b v b m s
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Explosion - Example v s =(10kg)(10m/s) (50kg) v s = 2m/s
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Homework Page: 217 Problems: 34, 35, 36 & 38 Due: 1/3/07
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Homework Practice Problems 13-16 Page: 214 Due: 1/7/02
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