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Published byKevin Hopkins Modified over 9 years ago
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A Projectile from a Cliff
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Practice Quiz 3 # 10 A cannon is at the top of a cliff, 150 meters high. The cannon fires a shell at an angle of 20° above the horizontal. The speed of the shell is 300 m/s as it leaves the muzzle of the cannon. How far from the base of the cliff does the shell land? v 1 = 300 m/s v 1x = 300 cos 20° = 282 m/s v 1y = 300 sin 20° = 103 m/s
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Time to Top of Trajectory HorizVert v 1 282 103 a 0 −10 v 2 282 0 t = (v 2 − v 1 )/ a = 10.3 v̄ 282 51.5 s v̄∙t=2890 v̄∙t=676
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To the Top Doubling
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Two Students Time from top to ground ? s = v 1 t + ½at 2 − 876 = 0 + ½ (−10) t 2 t 2 = −876 / (−5) = 175.2 t = √175.2 = 13.3
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The Whole Trip Horizontal Calculation s x = v̄ ∙ t = 282 ∙ 23.6 = 6653 meters
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