1. o Aim of the lecture  More detail on Capacitance Ohms Law  Capacitance Energy storage Dielectrics Ohms Law resistance Power dissipation o Main learning outcomes  familiarity with  Dielectrics  Resistance  Addition of  Capacitors  Resistors  Power dissipation in resistors Lecture 5

2. Dielectrics - + Material between plates oA dielectric is o an insulator o either polar o or non-polar No dielectric between plates C =  0 A/d With a dielectric, then C =  r  0 A/d

3. Electrons leave one plate The same number arrive on the other Polar Dielectric o In a polar material  molecules are polarised  act like small dipoles  orientate to align with E field -ve +ve E [pure water is like this]

4. Polar Dielectric -ve +ve E Consider Gauss’ Law surface as shown net charge inside surface reduced charge =  0 E.dA ∫ But charge is now q-q’ where q is the charge without dielectric q’ is the charge due to polar molecules q-q’ =  0 E.dA ∫

5. Polar Dielectric -ve +ve E q-q’ =  0 E.dA ∫ which gives that the electric field is E = (q-q’)/  0 A compared with E 0 = q/  0 A with no field The electric field is weaker when a dielectric is present for the same applied voltage The quantity of charge q’ depends on E 0, (often) which depends on q so q’ is proportional to q

6. Polar Dielectric -ve +ve E The quantity of charge q’ depends on E 0, (often) which depends on q so q’ is proportional to q so q’ = const q and E = const E 0 define that 1/const is  r with the result that C =  r  0 A/d

7. Other geometries are possible cylindrical

8. Sphere above a plane

9. A non-polar dielectric is one where the molecules are non-polar o In this case the molecules are CAUSED to be polar by the electric field, they are  Induced dipoles In practice the only difference is that the values of  r are (usually) smaller than for a polar dielectric

10. Adding Capacitance Add a second capacitor in series The net charge on these two plates is zero, it is just an equipotential line

11. Adding Capacitance Overall effect is to double distance between plates but C =  r  0 A/d so capacitance is halved

12. C C Total capacitance = C/2 Adding capacitors in series REDUCES the total capacitance

13. More generally When adding capacitors in series 1 1 1 = + C T C 1 C 2

14. Example: capacitance with partial dielectric

15. Capacitors Connected in Parallel but C =  r  0 A/d so capacitance is doubled o Adding a second identical capacitor in parallel  doubles the area of the plates  doubles charge stored for same voltage applied

16. More generally When adding capacitors in parallel = + C T C 1 C 2

17. = + C T C 1 C 2 1 1 1 = + C T C 1 C 2 PARALEL SERIES

18. Energy Stored The energy stored is equal to the energy in the electric field between the plates. Q = CV Work done to move a small charge, dq from one plate to the other is dW = VdQ = VCdV So total energy, E is E = ∫dW = C∫VdV = ½CV 2

19. = + C T C 1 C 2 1 1 1 = + C T C 1 C 2 E = ½CV 2 Q = CV Summary for Capacitors C =  r  0 A/d for parallel plate capacitor For series addition For parallel addition  0 is 8.854×10 −12 F m –1  r is typically between 1 and 10

20. Practical Information: Capacitors are labelled in a ‘funny’ way The units are always  F or pF This means 100k pF ie 100 x 10 3 x 10 -12 F = 100nF (it cant be  F because it would be too big – you just have to know this!) And this means the maximum voltage you can put across it is 100V More than you wanted to know! not examinable but useful

21. Final Warning: some capacitors are ‘polarised’ you MUST put the voltage across them the correct direction. Tantalum bead capacitors can explode if connected the wrong way round!! This little + means that this terminal must be +ve compared with the other 22u 35 means 22  F max volts = 35V

22. More on Ohms Law and Resistance Recall that V = IR Where V is the voltage applied across a resistance, R and I is the current that flows. The resistance is analogous to the resistance of a pipe to the flow of water through it.

23. o Electrons are made to drift in an electric field caused by an external voltage. o They loose energy in collisions with the fixed atoms o They therefore do not accelerate o They drift at constant speed

24. Consider a resistance with a voltage across it. V Suppose the current that flows is I a If we apply the same voltage across two such resistances connected in parallel, then the current doubles, so the resistance is inversely proportional to the area, A, of conductor Current = 2I a

25. If we put two in series, then we need a voltage V across each to drive the same current, I a, so resistance is proportional to length, L Resistance =  L/A for many materials  is a constant called the ‘resistivity’ of the material and is very different for different conductors.

26. o Any real circuit has resistance o Usually wires are a small resistance  we ignore it, assume it is zero  Represent the resistance with a RESISTOR o The wires that we draw joining parts of a circuit are  Taken to have zero resistance  Resistance is represented by o An ampmeter has zero resistance o A voltmeter has a very high resistance (infinite if perfect) V = I R

27. These resistors are 100  with 5% accuracy More practical details! Here is how you can tell what a resistor value is:

28. Resistors in series. Recall that for identical resistors, the resistance is proportional to the length. This generalises for resistors in series Rtotal = R1 + R2 + R3 + …..

29. For resistors in parallel, it is like increasing the area, so two in parallel gives half the resistance, and in general: Rtotal

30. The energy transferred to the atoms when the electrons collide with them in a resistor is converted to heat Power = current x voltage P = IR but remember ohms law V=IR So P = I 2 R P = V 2 /R