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L14 Physics of dry air and moist air
Potential temperature Pseudo-adiabatic charts Skew T – ln p charts Moist air Saturated adiabatic lapse rate Normand’s Rule: Cloud base
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Potential Temperature (θ)
The potential temperature of an air parcel is its temperature when compressed (or expanded) adiabatically to surface pressure (p0) (defined as a standard pressure of 1000 hPa). Again, start from the 1st Law of Thermodynamics, and make dq=0:
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Ideal Gas Law (see Lecture 8)
so: R is the specific gas constant for air R = 287 J kg-1 K-1 substitute in α:
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Divide by RT: Integrate both sides, from the starting (p,T) to the surface (p0,T0), noting cp/R is a constant: Remember integral of 1/x is the natural log of x:
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Rearrange to give potential temperature, θ:
Integrating: Remember: Hence: or: Rearrange to give potential temperature, θ: R = 287 J kg-1 K-1 cp = 1004 J kg-1 K-1 Hence R/cp = 0.286
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Happily, we can look at this graphically: e. g
Happily, we can look at this graphically: e.g., the ‘Pseudo-adiabatic’ chart Re-arrange: So if you plot: p0.286 on y-axis,T on x-axis For a constant θ, (p00.286/θ) is also a constant, so the graph yields a straight line with gradient given by (p00.286/θ), and passing through T=0 and p=0
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Pseudo-adiabatic chart
Earth’s atmosphere y-axis is linear for p0.286 also linear for ln(p) Useful as now we can follow each line and determine graphically temperature at any pressure, assuming adiabatic expansion/compression
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Pseudo-adiabatic chart
Earth’s atmosphere Solves Poisson’s equation graphically! Disadvantage: Everything happens in small region of the chart… This can be overcome by skewing the temperature lines rather than plotting them straight up → The Skew T-ln p chart Earth’s atmosphere is never here Potential Temperature: temperature at 1000HPa
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Examples: Kuching in Malaysia Valentia in Ireland.
Vertical T Skew T-ln p chart difference to pseudo-adiabatic: ln(p) rather than p0.286 T skewed Skew T
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What are all the lines on the skew T-ln p chart?
isobar isotherm dry adiabat saturated adiabat saturation mixing ratio
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Example: airplane air If an airplane at 250hPa takes air in at
-51oC and adjusts it to cabin pressure (850 hPa), does the air have to be Heated Cooled to be comfortable?
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Follow the dry adiabat to 850 hPa
Cabin pressure 850 hPa Temperature ~43°C
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Moist air See: L6 Humidity
Air contains some H2O molecules (water vapour) Vapour pressure (e): partial pressure exerted by the gaseous water (hPa) Mixing ratio (w): mass of water vapour / mass of dry air Warmer air can accommodate more water molecules; the maximum for a given temperature is when the air is ‘saturated’ For a given temperature, there is a: saturation vapour pressure (es) saturation mixing ratio (ws) An air parcel can become saturated, e.g. by ascent and cooling Once saturated, further cooling will result in condensation of liquid water: i.e. cloud droplets
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evaporation condensation Mixing ratio w = mvapour/mdry [normally given units g/kg] At saturation: evaporation balances condensation Saturation mixing ratio ws = es / p Relative Humidity = w/ws x 100% = e/es x 100%
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Thermodynamics of saturated air
As long as air remains unsaturated, it will behave like ‘dry’ air However, once saturated, the condensation of liquid water releases latent heat This means that an ascending air parcel that becomes saturated will cool less than one that remains unsaturated We can theoretically derive how much the cooling is modified (not done here, see Wallace & Hobbs p79-87 if interested), and define the ‘Saturated Adiabatic Lapse Rate’ (SALR) The difference between the DALR and a SALR is largest for warmer air, as the water vapour content, and hence latent heat release are larger Saturated adiabats are solid green lines on the skew T-ln p chart
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Saturation mixing ratio
Derived Using ideal gas law, and def. of saturation water vapour pressure (Clausius Clapeyron, Dr Essery) Constant p: w increases with T Constant T: w increases with decreasing p
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Relative humidity: RH = 100*e/es ≈ 100*w/ws
Dewpoint (Td): Temperature to which air must cool at constant pressure to be saturated Q: Air at 1000 hPa and 18oC has a mixing ratio of 6 g/kg. What is its relative humidity and dewpoint? w = 6 g/kg ws RH=6/13*100=46% Dewpoint ~6.5oC 13g/kg saturation mixing ratio. => relative humidity 46% Notice: if we know one moisture variable (mixing ratio) we know them all!
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As unsaturated air lifts dry adiabatically, it will eventually saturate: Normand’s Rule
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This level is the lifting condensation level
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LCL = Cloud base
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Let’s look at some real data
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Albemarle, 00z Monday 17 Oct
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Albemarle, 00z Tuesday 18 Oct
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Summary Potential temperature – the temperature of air compressed/expanded to 1000 hPa along a dry adiabat Pseudo-adiabatic charts – graphically solve equations Skew T – ln p charts – will use in labs Moist air – releases latent heat at saturation point Saturated adiabatic lapse rate – less than DALR – typically 6 K/km Normand’s Rule: Can estimate cloud base height using surface temperature and moisture
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