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1 Chapter 2 Simple Linear Regression Ray-Bing Chen Institute of Statistics National University of Kaohsiung
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2 2.1 Simple Linear Regression Model y = 0 + 1 x + –x: regressor variable –y: response variable – 0 : the intercept, unknown – 1 : the slope, unknown – : error with E( ) = 0 and Var( ) = 2 (unknown) The errors are uncorrelated.
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3 Given x, E(y|x) = E( 0 + 1 x + ) = 0 + 1 x Var(y|x) = Var( 0 + 1 x + ) = 2 Responses are also uncorrelated. Regression coefficients: 0, 1 – 1 : the change of E(y|x) by a unit change in x – 0 : E(y|x=0)
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4 2.2 Least-squares Estimation of the Parameters 2.2.1 Estimation of 0 and 1 n pairs: (y i, x i ), i = 1, …, n Method of least squares: Minimize
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5 Least-squares normal equations:
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6 The least-squares estimator:
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7 The fitted simple regression model: –A point estimate of the mean of y for a particular x Residual: –An important role in investigating the adequacy of the fitted regression model and in detecting departures from the underlying assumption!
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8 Example 2.1: The Rocket Propellant Data –Shear strength is related to the age in weeks of the batch of sustainer propellant. –20 observations –From scatter diagram, there is a strong relationship between shear strength (y) and propellant age (x). –Assumption y = 0 + 1 x +
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10 The least-square fit:
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11 How well does this equation fit the data? Is the model likely to be useful as a predictor? Are any of the basic assumption violated and if so how serious is this?
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12 2.2.2 Properties of the Least-Squares Estimators and the Fitted Regression Model are linear combinations of y i are unbiased estimators.
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14 The Gauss-Markov Theorem: are the best linear unbiased estimators (BLUE). –
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15 Some useful properties: –The sum of the residuals in any regression model that contains an intercept 0 is always 0, i.e. – – Regression line always passes through the centroid point of data, –
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16 2.2.3 Estimator of 2 Residual sum of squares:
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17 Since, the unbiased estimator of 2 is –MS E is called the residual mean square. –This estimate is model-dependent. Example 2.2
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18 2.2.4 An Alternate Form of the Model The new regression model: Normal equations: The least-squares estimators:
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19 Some advantages: –The normal equations are easier to solve – are uncorrelated. –
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20 2.3 Hypothesis Testing on the Slope and Intercept Assume ε i are normally distributed y i ~ N( 0 + 1 x i, 2 ) 2.3.1 Use of t-Tests Test on slope: –H 0 : 1 = 10 v.s. H 1 : 1 10 –
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21 If 2 is known, under null hypothesis, (n-2) MS E / 2 follows a 2 n-2 If 2 is unknown, Reject H 0 if |t 0 | > t /2, n-2
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22 Test on intercept: –H 0 : 0 = 00 v.s. H 1 : 0 00 –If 2 is unknown –Reject H 0 if |t 0 | > t /2, n-2
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23 2.3.2 Testing Significance of Regression H 0 : 1 = 0 v.s. H 1 : 1 0 Accept H 0 : there is no linear relationship between x and y.
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24 Reject H 0 : x is of value in explaining the variability in y. Reject H 0 if |t 0 | > t /2, n-2
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25 Example 2.3:The Rocket Propellant Data –Test significance of regression – –MS E = 9244.59 – – the test statistic is –t 0.0025,18 = 2.101 –Reject H 0
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27 2.3.3 The Analysis of Variance (ANOVA) Use an analysis of variance approach to test significance of regression –
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28 – – SS T : the corrected sum of squares of the observations. It measures the total variability in the observations. – SS Res : the residual or error sum of squares –The residual variation left unexplained by the regression line. –SS R : the regression or model sum of squares –The amount of variability in the observations accounted for by the regression line – SS T = SS R + SS Res
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29 – – The degree-of-freedom: df T = n-1 df R = 1 df Res = n-2 df T = df R + df Res –Test significance regression by ANOVA SS Res = (n-2) MS Res ~ n-2 SS R = MS R ~ 1 SS R and SS Res are independent
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30 E(MS Res ) = 2 E(MS R ) = 2 + 1 2 S xx Reject H 0 if F 0 > F /2,1, n-2 –If 1 0, F 0 follows a noncentral F with 1 and n-2 degree of freedom and a noncentrality parameter
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31 Example 2.4: The Rocket Propellant Data
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32 More About the t Test – –The square of a t random variable with f degree of freedom is a F random variable with 1 and f degree of freedom.
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33 2.4 Interval Estimation in Simple Linear Regression 2.4.1 Confidence Intervals on 0, 1 and 2 Assume that ε i are normally and independently distributed
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34 100(1- )% confidence intervals on 0, 1 are given: Interpretation of C.I. Confidence interval for 2 :
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35 Example 2.5 The Rocket Propellant Data
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37 2.4.2 Interval Estimation of the Mean Response Let x 0 be the level of the regressor variable for which we wish to estimate the mean response. x 0 is in the range of the original data on x. An unbiased estimator of E(y| x 0 ) is
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38 follows a normal distribution.
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39 A 100(1- )% confidence interval on the mean response at x 0 :
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40 Example 2.6 The Rocket Propellant Data
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42 The interval width is a minimum for and widens as increases. Extrapolation
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43 2.5 Prediction of New Observations is the point estimate of the new value of the response follows a normal distribution with mean 0 and variance
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44 The 100(1- )% confidence interval on a future observation at x 0 (a prediction interval for the future observation y 0 )
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45 Example 2.7:
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47 The 100(1- )% confidence interval on
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48 2.6 Coefficient of Determination The coefficient of determination: The proportion of variation explained by the regressor x 0 R 2 1
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49 In Example 2.1, R 2 = 0.9018. It means that 90.18% of the variability in strength is accounted for by the regression model. R 2 can be increased by adding terms to the model. For a simple regression model, E(R 2 ) increases (decreases) as S xx increases (decreases)
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50 R 2 does not measure the magnitude of the slope of the regression line. A large value of R 2 imply a steep slope. R 2 does not measure the appropriateness of the linear model.
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51 2.7 Some Considerations in the Use of Regression Only suitable for interpretation over the range of the regressors, not for extrapolation. Important: The disposition of the x values. Slope strongly influenced by the remote values of x. Outliers and bad values can seriously disturb the least-square fit. (intercept and the residual mean square) Don’t imply the cause and effect relationship
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54 The t statistic for testing H 0 : 1 = 0 for this model is t 0 = 27.312 and R 2 = 0.9842
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55 x may be unknown. For example: consider predicting maximum daily load on an electric power generation system from a regression model relating the load to the maximum daily temperature.
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56 2.8 Regression Through the Origin A no-intercept model is Given (y i, x i ), i = 1 2,…, n,
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57 The 100(1- )% confidence interval on 1 The 100(1- )% confidence interval on E(y| x 0 ) The 100(1- )% confidence interval on y 0
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58 Misuse: data lie in a region of x-space remote from the origin.
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59 The residual mean square, MS Res Generally R 2 is not a good comparative statistic for two models. –For the intercept model, –For the no-intercept model, –Occasionally R 0 2 > R 2, but MS 0,Res < MS Res
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60 Example 2.8 The Shelf-Stocking Data
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64 2.9 Estimation by Maximum Likelihood Assume that the errors are NID(0, 2 ). Then y i ~N( 0 + 1 x i, 2 ) The likelihood function:
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65 MLE v.s. LSE – In general MLE have better statistical properties than LSE. –MLE are unbiased (asymptotically unbiased) and have minimum variance when compare to all the other unbiased estimators. –They are also consistent estimators. –They are a set of sufficient statistics.
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66 –MLE requires more stringent statistical assumptions than LSE. –LSE only need to have the second moment assumptions. –MLE require a full distributional assumption.
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67 2.10 Case Where the Regressor x Is Random 2.10.1 x and y Jointly Distributed x and y are jointly distributed r.v. and this joint distribution is unknown. All of our previous results hold if –y|x ~ N( 0 + 1 x, 2 ) –The x’s are independent r.v.’s whose probability distribution does not involve 0, 1, 2
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68 2.10.2 x and y Jointly Normally Distributed: the Correlation Model
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70 The estimator of
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71 Test on 100(1- )% C.I. for
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72 Example 2.9 The Delivery Time Data
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