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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 1 Bruce Mayer, PE Chabot College Mathematics Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Chabot Mathematics §1.3 Lines, Linear Fcns
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 2 Bruce Mayer, PE Chabot College Mathematics Review § Any QUESTIONS About §1.2 → Functions Graphs Any QUESTIONS About HomeWork §1.2 → HW-02 1.2
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 3 Bruce Mayer, PE Chabot College Mathematics §1.3 Learning Goals Review properties of lines: slope, horizontal & vertical lines, and forms for the equation of a line Solve applied problems involving linear functions Recognize parallel ( ‖ ) and perpendicular (┴) lines Explore a Least-Squares linear approximation of Line-Like data
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 4 Bruce Mayer, PE Chabot College Mathematics 3 Flavors of Line Equations The SAME Straight Line Can be Described by 3 Different, but Equivalent Equations Slope-Intercept (Most Common) –m & b are the slope and y-intercept Constants Point-Slope: –m is slope constant –(x 1,y 1 ) is a KNOWN-Point; e.g., (7,11)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 5 Bruce Mayer, PE Chabot College Mathematics 3 Flavors of Line Equations 3.General Form: –A, B, C are all Constants Equation Equivalence → With a little bit of Algebra can show:
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 6 Bruce Mayer, PE Chabot College Mathematics Lines and Slope The slope, m, between two points (x 1,y 1 ) and (x 2,y 2 ) is defined to be: A line is a graph for which the slope is constant given any two points on the line An equation that can be written as y = mx + b for constants m (the slope) and b (the y-intercept) has a line as its graph.
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 7 Bruce Mayer, PE Chabot College Mathematics SLOPE Defined SLOPE The SLOPE, m, of the line containing points (x 1, y 1 ) and (x 2, y 2 ) is given by
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 8 Bruce Mayer, PE Chabot College Mathematics Example Slope City Graph the line containing the points (−4, 5) and (4, −1) & find the slope, m SOLUTION Thus Slope m = −3/4 Change in y = − 6 Change in x = 8
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 9 Bruce Mayer, PE Chabot College Mathematics Example ZERO Slope Find the slope of the line y = 3 ( 3, 3) (2, 3) SOLUTION: Find Two Pts on the Line Then the Slope, m A Horizontal Line has ZERO Slope
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 10 Bruce Mayer, PE Chabot College Mathematics Example UNdefined Slope Find the slope of the line x = 2 SOLUTION: Find Two Pts on the Line Then the Slope, m A Vertical Line has an UNDEFINED Slope (2, 4) (2, 2)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 11 Bruce Mayer, PE Chabot College Mathematics Slope Symmetry We can Call EITHER Point No.1 or No.2 and Get the Same Slope Example, LET (x 1,y 1 ) = (−4,5) Moving L→R (−4,5) Pt1 (4,−1)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 12 Bruce Mayer, PE Chabot College Mathematics Slope Symmetry cont Now LET (x 1,y 1 ) = (4,−1) (−4,5) (4,−1) Pt1 Moving R→L Thus
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 13 Bruce Mayer, PE Chabot College Mathematics Example Application The cost c, in dollars, of shipping a FedEx Priority Overnight package weighing 1 lb or more a distance of 1001 to 1400 mi is given by c = 2.8w + 21.05 where w is the package’s weight in lbs Graph the equation and then use the graph to estimate the cost of shipping a 10½ pound package
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 14 Bruce Mayer, PE Chabot College Mathematics FedEx Soln: c = 2.8w + 21.05 Select values for w and then calculate c. c = 2.8w + 21.05 If w = 2, then c = 2.8(2) + 21.05 = 26.65 If w = 4, then c = 2.8(4) + 21.05 = 32.25 If w = 8, then c = 2.8(8) + 21.05 = 43.45 Tabulating the Results: wc 226.65 432.25 843.45
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 15 Bruce Mayer, PE Chabot College Mathematics FedEx Soln: Graph Eqn Plot the points. Weight (in pounds) Mail cost (in dollars) To estimate costs for a 10½ pound package, we locate the point on the line that is above 10½ lbs and then find the value on the c-axis that corresponds to that point 10 ½ pounds The cost of shipping an 10½ pound package is about $51.00 $51
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 16 Bruce Mayer, PE Chabot College Mathematics The Slope-Intercept Equation y = mx + b slope-intercept The equation y = mx + b is called the slope-intercept equation. slope m(0, b) The equation represents a line of slope m with y-intercept (0, b)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 17 Bruce Mayer, PE Chabot College Mathematics Example Find m & b Find the slope and the y-intercept of each line whose equation is given by a)b)c) Solution-a) Slope is 3/8 InterCept is (0,−2)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 18 Bruce Mayer, PE Chabot College Mathematics Example Find m & b cont.1 Find the slope and the y-intercept of each line whose equation is given by a)b)c) Solution-b) We first solve for y to find an equivalent form of y = mx + b. Slope m = −3 Intercept b = 7 Or (0,7)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 19 Bruce Mayer, PE Chabot College Mathematics Example Find m & b cont.2 Find the slope and the y-intercept of each line whose equation is given by a)b)c) Solution c) rewrite the equation in the form y = mx + b. Slope, m = 4/5 (80%) Intercept b = −2 Or (0,−2)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 20 Bruce Mayer, PE Chabot College Mathematics Example Find Line from m & b A line has slope −3/7 and y-intercept (0, 8). Find an equation for the line. We use the slope-intercept equation, substituting −3/7 for m and 8 for b: Then in y = mx + b Form
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 21 Bruce Mayer, PE Chabot College Mathematics Example Graph y = (4/3)x – 2 SOLUTION: The slope is 4/3 and the y-intercept is (0, −2) We plot (0, −2) then move up 4 units and to the right 3 units. Then Draw Line up 4 units right 3 down 4 left 3 ( 3, 6) (3, 2) (0, 2) We could also move down 4 units and to the left 3 units. Then draw the line.
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 22 Bruce Mayer, PE Chabot College Mathematics Parallel and Perpendicular Lines Two lines are parallel (||) if they lie in the same plane and do not intersect no matter how far they are extended. Two lines are perpendicular (┴) if they intersect at a right angle (i.e., 90°). E.g., if one line is vertical and another is horizontal, then they are perpendicular.
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 23 Bruce Mayer, PE Chabot College Mathematics Para & Perp Lines Described Let L 1 and L 2 be two distinct lines with slopes m 1 and m 2, respectively. Then L 1 is parallel to L 2 if and only if m 1 = m 2 and b 1 ≠ b 2 –If m 1 = m 2. and b 1 = b 2 then the Lines are CoIncident L 1 is perpendicular L 2 to if and only if m 1m 2 = −1. Any two Vertical or Horizontal lines are parallel ANY horizontal line is perpendicular to ANY vertical line
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 24 Bruce Mayer, PE Chabot College Mathematics Parallel Lines by Slope-Intercept Slope-intercept form allows us to quickly determine the slope of a line by simply inspecting, or looking at, its equation. This can be especially helpful when attempting to decide whether two lines are parallel These Lines All Have the SAME Slope
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 25 Bruce Mayer, PE Chabot College Mathematics Example Parallel Lines Determine whether the graphs of the lines y = −2x − 3 and 8x + 4y = −6 are parallel. SOLUTION Solve General Equation for y Thus the Eqns are – y = −2x − 3 – y = −2x − 3/2
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 26 Bruce Mayer, PE Chabot College Mathematics Example Parallel Lines The Eqns y = −2x − 3 & y = −2x − 3/2 show that m 1 = m 2 = −2 −3 = b 1 ≠ b 2 = −3/2 Thus the Lines ARE Parallel The Graph confirms the Parallelism
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 27 Bruce Mayer, PE Chabot College Mathematics Example ║& ┴ Lines Find equations in general form for the lines that pass through the point (4, 5) and are (a) parallel to & (b) perpendicular to the line 2x − 3y + 4 = 0 SOLUTION Find the Slope by ReStating the Line Eqn in Slope-Intercept Form
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 28 Bruce Mayer, PE Chabot College Mathematics Example ║& ┴ Lines SOLUTION cont. Thus Any line parallel to the given line must have a slope of 2/3 Now use the Given Point, (4,5) in the Pt-Slope Line Eqn Thus ║- Line Eqn
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 29 Bruce Mayer, PE Chabot College Mathematics Example ║& ┴ Lines SOLUTION cont. Any line perpendicular to the given line must have a slope of −3/2 Now use the Given Point, (4,5) in the Pt-Slope Line Eqn Thus ┴ Line Eqn
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 30 Bruce Mayer, PE Chabot College Mathematics Example ║& ┴ Lines SOLUTION Graphically
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 31 Bruce Mayer, PE Chabot College Mathematics Scatter on plots on XY-Plane A scatter plot usually shows how an EXPLANATORY, or independent, variable affects a RESPONSE, or Dependent Variable Sometimes the SHAPE of the scatter reveals a relationship Shown Below is a Conceptual Scatter plot that could Relate the RESPONSE to some EXCITITATION
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 32 Bruce Mayer, PE Chabot College Mathematics Linear Fit by Guessing The previous plot looks sort of Linear We could use a Ruler to draw a y = mx+b line thru the data But which Line is BETTER? and WHY?
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 33 Bruce Mayer, PE Chabot College Mathematics Least Squares Curve Fitting Numerical Software such as Scientific Calculators, MSExcel, and MATLAB calc the “best” m&b How are these Calculations Made? Almost All “Linear Regression” methods use the “Least Squares” Criterion
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 34 Bruce Mayer, PE Chabot College Mathematics Least Squares To make a Good Fit, MINIMIZE the |GUESS − data| distance by one of data Best Guess-y Best Guess-x
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 35 Bruce Mayer, PE Chabot College Mathematics Least Squares cont. Almost All Regression Methods minimize theSum of the Vertical Distances, J: §7.4 shows that for Minimum “J” What a Mess!!! –For more info, please take ENGR/MTH-25
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 36 Bruce Mayer, PE Chabot College Mathematics DropOut Rates Scatter Plot Given Column Chart Read Chart to Construct T-table Use T-table to Make Scatter Plot on the next Slide
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 37 Bruce Mayer, PE Chabot College Mathematics Zoom-in to more accurately calc the Slope
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 38 Bruce Mayer, PE Chabot College Mathematics “Best” Line (EyeBalled) Intercept 15.2% (x 1,y 1 ) = (8yr, 14%)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 39 Bruce Mayer, PE Chabot College Mathematics DropOut Rates Scatter Plot Calc Slope from Scatter Plot Measurements Read Intercept from Measurement Thus the Linear Model for the Data in SLOPE-INTER Form To Find Pt-Slp Form use Known-Pt from Scatter Plot (x 1,y 1 ) = (8yr, 14%)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 40 Bruce Mayer, PE Chabot College Mathematics DropOut Rates Scatter Plot Thus the Linear Model for the Data in PT-SLOPE Form Now use Slp-Inter Eqn to Extrapolate to DropOut-% in 2010 X for 2010 → x = 2010 − 1970 = 40 In Equation The model Predicts a DropOut Rate of 9.2% in 2010
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 41 Bruce Mayer, PE Chabot College Mathematics 9.2% (Actually 7.4%)
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 42 Bruce Mayer, PE Chabot College Mathematics Replace EyeBall by Lin Regress Use MSExcel commands for LinReg WorkSheet → SLOPE & INTERCEPT Comands Plot → Linear TRENDLINE By MSExcel M15_Drop_Out_Linear_Regression_1306.xlsx
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 43 Bruce Mayer, PE Chabot College Mathematics Official Stats on DropOuts Status dropout rates of 16- through 24-year-olds in the civilian, noninstitutionalized population, by race/ethnicity: Selected years, 1990-2010 YearTotal 1 Race/ethnicity WhiteBlackHispanicAsian Native Americans 199012.19.013.232.44.9!16.4! 199512.08.612.130.03.913.4! 199811.87.713.829.54.111.8 199911.27.312.628.64.3‡ 200010.96.913.127.83.814.0 200110.77.310.927.03.613.1 200210.56.511.325.73.916.8 20039.96.310.923.53.915.0 200410.36.811.823.83.617.0 20059.46.010.422.42.914.0 20069.35.810.722.13.614.7 20078.75.38.421.46.119.3 20088.04.89.918.34.414.6 20098.15.29.317.63.413.2 20107.45.18.015.14.212.4 http://nces.ed.gov/fastfacts/display.asp?id=16 SOURCE: U.S. Department of Education, National Center for Education Statistics. (2012). The Condition of Education 2012 (NCES 2012-045. ! Interpret data with caution. The coefficient of variation (CV) for this estimate is 30 percent or greater. ‡ Reporting standards not met (too few cases). 1 Total includes other race/ethnicity categories not separately shown.
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 44 Bruce Mayer, PE Chabot College Mathematics WhiteBoard Work Problem §1.3-56 For the “Foodies” in the Class Mix x ounces of Food-I and y ounces of Food-II to make a Lump of Food-Mix that contains exactly: 73 grams of Carbohydrates 46 grams of Protein
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 45 Bruce Mayer, PE Chabot College Mathematics All Done for Today USA HiSchl DropOuts
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 46 Bruce Mayer, PE Chabot College Mathematics Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Chabot Mathematics Appendix –
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 47 Bruce Mayer, PE Chabot College Mathematics
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 48 Bruce Mayer, PE Chabot College Mathematics
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 49 Bruce Mayer, PE Chabot College Mathematics
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 50 Bruce Mayer, PE Chabot College Mathematics
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 51 Bruce Mayer, PE Chabot College Mathematics
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BMayer@ChabotCollege.edu MTH15_Lec-03_sec_1-3_Lines_LinearFcns_.pptx 52 Bruce Mayer, PE Chabot College Mathematics
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