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New Toads and Frogs Results By Jeff Erickson Presented by Nate Swanson
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Overview Notation and Game Rules Basic Simplification Techniques Ways of Calculating Knot Values
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Notation and Game Rules One-dimensional board Left = Toads Right = Frogs Toads move to the right, Frogs move to the left A toad may either push to an empty square, or jump a single frog and land on an empty square
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Notation and Game Rules
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Basic Simplification Techniques Dead Pieces: –Any piece in a contiguous sequence starting with 2 toads (or the left edge of the board), and ending with 2 frogs (or the right edge of the board) Any other piece is alive We may remove any dead pieces
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Basic Simplification Techniques
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Death Leap Principle Isolated- –None of its neighboring squares is empty Any position in which the only legal moves are jumps into isolated spaces has value zero
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Death Leap Principle Proof – suppose it’s Left’s turn: –If she has no move, she loses –Otherwise, she must jump into an isolated space –Right responds by pushing the jumped frog –This leaves the board in the same situation
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Death Leap Principle Any board that has none of the following positions has value zero:
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Terminal Toads Theorem and Finished Frogs Formula Proof: Show 2 nd wins on
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Terminal Toads Theorem and Finished Frogs Formula Mirror strategy: –X is responded in (-X) –Last toad in 1 st compartment is marked with * –Any move in the third component is answered by moving the marked T, and visa versa –Enough to show Left loses going 1 st ; 2 special cases for Right –Similar argument for Fin. Frogs Form.
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Terminal Toads Theorem and Finished Frogs Formula
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Ways to Calculate Knot Values Knot – when all toads and frogs form a contiguous sequence Need only to consider positions that start with a single toad and end with a single frog Lemma 1 (all superscripts positive)
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Ways to Calculate Knot Values Lemma 2 Proof: By case analysis of Lemma 1 and TTT
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Lemma 2 Case Analysis
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Ways to Calculate Knot Values Lemma 3 Proof: By case analysis of Lemma 1 and TTT (every position 3 moves away is an integer).
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Ways to Calculate Knot Values Lemma 4 Proof: Show 2 nd wins on Base Case: b=2, Lemma 3 Similar argument for reverse game
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Ways to Calculate Knot Values Lemma 5 If neither player can move from the position Then:
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Lemma 5 Proof: induct on a –Left moving 1 st Left must jump; Right responds by pushing jumped frog By TTT, this equals (b-1) By induction, this game equals 0
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Lemma 5 Right moving 1 st : counting argument –Left’s toads will move at least b times, for a total of ab moves –Right’s frog will move at most a moves, which is if Right never jumps, leaving a(b-1) + a= ab Therefore, Right will lose
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Ways to Calculate Knot Values Lemma 6 –If neither player can move from the position Then TF
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Ways to Calculate Knot Values Lemma 7 Proof: It suffices to prove that, We then induct on c (like before), and symmetrically do the same for the other side.
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Lemma 7 Both players mark their respective single piece, and makes sure that that piece never jumps (best strategy) Left gets cd + b + d + 1 in the 1 st component and ab + a + c in the 2 nd. Right gets ab + a + c + 1 in the 1 st component, cd – d +b + 1 in the 2 nd, and d – 1 in the 3 rd Base Case: Lemma 1
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Conclusion Lemmas cover each case for knotted games –Each knotted game has an integer value –Each knotted game’s value can be computed directly without evaluating any of the followers
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