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Test Tubes General Chemistry A CH4701
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This lecture: General information Course syllabus Recommended texts Relevance of this module to you
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This lecture: General information Course syllabus Recommended texts Relevance of this module to you Topic 1:- Fundamental principles Topic 2:- Classification of matter
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Lecturer Edmond Magner MS1016 Andrew McCormack MS10 Course duration1 semester
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Lecturer Edmond Magner MS1016 Teresa Curtin MSG015 Course duration1 semester Class contact2 x 50 min lectures/week 1 x 2 hour lab/fortnight Assessment60% exam, 40% labs
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Lecturer Edmond Magner MS1016 Teresa Curtin MSG015 Course duration1 semester Class contact2 x 50 min lectures/week 1 x 2 hour lab/fortnight Assessment60% exam, 40% labs LabsIn B3-053 MUST have white lab coat and safety specs Your first lab session will be on week 3 (B3053)
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CH 4701 COURSE SYLLABUS 1. Basics Simple characterisation of atoms + molecules Chemical accounting: the mole Early chemical ideas & their present day uses Modern theories of atomic structure Introduction to chemical bonding The Periodic Table
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CH 4701 COURSE SYLLABUS 1. Basics Simple characterisation of atoms + molecules Chemical accounting: the mole Early chemical ideas & their present day uses Modern theories of atomic structure Introduction to chemical bonding The Periodic Table 2. Applied chemistry Gas laws Electrochemistry Chemical equilibria (solutions and acids/bases)
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TEXTS & COURSE MATERIALS Essential for all: Good set of lecture notes!
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TEXTS & COURSE MATERIALS Essential for all: Good set of lecture notes! CH4701 Course Materials Pack: - available from UL Print Room (E1-006) reference number 3485, price €4.50
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TEXTS & COURSE MATERIALS Essential for all: Good set of lecture notes! CH4701 Course Materials Pack: - available from UL Print Room (E1-006) reference number 3485, price €5.00 Recommended for students without Leaving Cert chem: Chemistry: The Central Science 8th edn., by Brown, LeMay and Bursten - available UL Bookshop, price ca. €38.00 (includes multimedia CD-ROM) Some copies of other gen. chem. texts available in UL library under classification 540.
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COURSE AIMS + RELEVANCE 1. "Educate"
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COURSE AIMS + RELEVANCE 1. "Educate" 2. Give a basic understanding of the theory, practice and everyday applications of chemistry to non- chemists
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COURSE AIMS + RELEVANCE 1. "Educate" 2. Give a basic understanding of the theory, practice and everyday applications of chemistry to non- chemists 3. Review of fundamentals for chemists
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COURSE AIMS + RELEVANCE 1. "Educate" 2. Give a basic understanding of the theory, practice and everyday applications of chemistry to non- chemists 3. Review of fundamentals for chemists CHEMISTRY
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COURSE AIMS + RELEVANCE 1. "Educate" 2. Give a basic understanding of the theory, practice and everyday applications of chemistry to non- chemists 3. Review of fundamentals for chemists CHEMISTRY Describes: structure & composition of matter
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COURSE AIMS + RELEVANCE 1. "Educate" 2. Give a basic understanding of the theory, practice and everyday applications of chemistry to non- chemists 3. Review of fundamentals for chemists CHEMISTRY Describes: structure & composition of matter changes in structure & composition
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COURSE AIMS + RELEVANCE 1. "Educate" 2. Give a basic understanding of the theory, practice and everyday applications of chemistry to non- chemists 3. Review of fundamentals for chemists CHEMISTRY Describes: structure & composition of matter changes in structure & composition energy involved in these changes
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FUNDAMENTAL PRINCIPLES Law of conservation of energy: "Energy can be neither created nor destroyed, but may be transformed from one form to another"
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FUNDAMENTAL PRINCIPLES Law of conservation of energy: "Energy can be neither created nor destroyed, but may be transformed from one form to another" Law of conservation of mass: "Mass cannot be created or destroyed. The total mass of substances involved in a physical or chemical change remains constant"
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FUNDAMENTAL PRINCIPLES Law of conservation of energy: "Energy can be neither created nor destroyed, but may be transformed from one form to another" Law of conservation of mass: "Mass cannot be created or destroyed. The total mass of substances involved in a physical or chemical change remains constant" Special theory of relativity: E = mc 2, where c = velocity of light)
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CLASSIFICATION OF MATTER Properties of Matter
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CLASSIFICATION OF MATTER Properties of Matter Bulk (Substantive)Particulate
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CLASSIFICATION OF MATTER Properties of Matter Bulk (Substantive)Particulate Physical state
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CLASSIFICATION OF MATTER Properties of Matter Bulk (Substantive)Particulate Physical state Metallic character
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CLASSIFICATION OF MATTER Properties of Matter Bulk (Substantive)Particulate Physical state Metallic character Physical appearance
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CLASSIFICATION OF MATTER Properties of Matter Bulk (Substantive)Particulate Physical state Metallic character Physical appearance Chemical integrity
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Classification by physical state: Solid (Plutonium) Liquid(Mercury) (Chlorine)Gas
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Classification by metallic character: metal or non-metal?
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Classification by metallic character: metal or non-metal? Classification by physical appearance: Homogeneous Heterogeneous (Ruby) (Moon rock)
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Classification by chemical integrity: Matter Mixtures
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Classification by chemical integrity: Matter Mixtures (Bronze) (Agate)
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Classification by chemical integrity: Matter Pure substancesMixtures (Bronze) (Agate)
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Classification by chemical integrity: Matter Pure substancesMixtures Elements (Bronze) (Agate) (Carbon)
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Classification by chemical integrity: Matter Pure substancesMixtures Compounds Elements (Bronze) (Agate) (Carbon) (Ice)
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Definitions. Mixture: contains 2 or more pure substances, which can be separated out by physical means.
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Definitions. Mixture: contains 2 or more pure substances, which can be separated out by physical means. Pure substances: have a definite chemical composition and properties. They cannot be separated into simpler substances by physical means.
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Definitions. Mixture: contains 2 or more pure substances, which can be separated out by physical means. Pure substances: have a definite chemical composition and properties. They cannot be separated into simpler substances by physical means. Compound: pure substance which can be further broken down by chemical means.
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Definitions. Mixture: contains 2 or more pure substances, which can be separated out by physical means. Pure substances: have a definite chemical composition and properties. They cannot be separated into simpler substances by physical means. Compound: pure substance which can be further broken down by chemical means. Element: pure substance which cannot be further broken down by ordinary chemical means.
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Some examples of matter classification Steam? Gas, non-metallic, homogeneous, compound.
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Some examples of matter classification Steam? Gas, non-metallic, homogeneous, compound. Sugar? Solid, non-metallic, homogeneous, compound.
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Some examples of matter classification Steam? Gas, non-metallic, homogeneous, compound. Sugar? Solid, non-metallic, homogeneous, compound. Air? Gas, non-metallic, homogeneous, mixture.
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Some examples of matter classification Steam? Gas, non-metallic, homogeneous, compound. Sugar? Solid, non-metallic, homogeneous, compound. Air? Gas, non-metallic, homogeneous, mixture. Brass? Solid, metallic, homogeneous, mixture.
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Some examples of matter classification Steam? Gas, non-metallic, homogeneous, compound. Sugar? Solid, non-metallic, homogeneous, compound. Air? Gas, non-metallic, homogeneous, mixture. Brass? Solid, metallic, homogeneous, mixture. Mars Bar? Solid, non-metallic, heterogeneous, mixture
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Differences between mixtures and compounds Mixture Compound Components can be Components can not be separated by using physical techniques
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Differences between mixtures and compounds Mixture Compound Components can be Components can not be separated by using physical techniques Composition is variable Composition is fixed
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Differences between mixtures and compounds Mixture Compound Components can be Components can not be separated by using physical techniques Composition is variable Composition is fixed Properties are related to Properties are unlike those of its components
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Table of some of the more common elements ElementSymbol HydrogenH HeliumHe CarbonC AluminiumAl
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Table of some of the more common elements ElementSymbol HydrogenH HeliumHe CarbonC AluminiumAl NitrogenN OxygenO PhosphorousP IronFe
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Table of some of the more common elements ElementSymbol HydrogenH HeliumHe CarbonC AluminiumAl NitrogenN OxygenO PhosphorousP IronFe CopperCu NickelNi SulphurS IodineI
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http://www.ul.ie/~ces/Resources.html
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The correct classifications for sea water, distilled water, brass, and helium respectively are (a)compound, element, mixture and compound (b)mixture, element, mixture and compound
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The correct classifications for sea water, distilled water, brass, and helium respectively are (a)compound, element, mixture and compound (b)mixture, element, mixture and compound (c) mixture, compound, mixture and element (d) compound, element, compound and mixture (e) mixture, compound, compound and element
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The correct classifications for sea water, distilled water, brass, and helium respectively are (a)compound, element, mixture and compound (b)mixture, element, mixture and compound (c) mixture, compound, mixture and element (d) compound, element, compound and mixture (e) mixture, compound, compound and element
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The correct classifications for sea water, distilled water, brass, and helium respectively are (a)compound, element, mixture and compound (b)mixture, element, mixture and compound (c) mixture, compound, mixture and element (d) compound, element, compound and mixture (e) mixture, compound, compound and element All mixtures (indicate correct statement) (a) are heterogeneous in appearance (b) contain different types of molecules
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The correct classifications for sea water, distilled water, brass, and helium respectively are (a)compound, element, mixture and compound (b)mixture, element, mixture and compound (c) mixture, compound, mixture and element (d) compound, element, compound and mixture (e) mixture, compound, compound and element All mixtures (indicate correct statement) (a) are heterogeneous in appearance (b) contain different types of molecules (c) contain two or more pure substances (d) can be separated only by chemical means (e) contain more than one physical state
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The correct classifications for sea water, distilled water, brass, and helium respectively are (a)compound, element, mixture and compound (b)mixture, element, mixture and compound (c) mixture, compound, mixture and element (d) compound, element, compound and mixture (e) mixture, compound, compound and element All mixtures (indicate correct statement) (a) are heterogeneous in appearance (b) contain different types of molecules (c) contain two or more pure substances (d) can be separated only by chemical means (e) contain more than one physical state
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DIMENSIONS AND UNITS Need to provide a quantitative means of describing the universe.
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DIMENSIONS AND UNITS Need to provide a quantitative means of describing the universe. 7 independent dimensions (physical quantities):
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DIMENSIONS AND UNITS Need to provide a quantitative means of describing the universe. 7 independent dimensions (physical quantities): 1. Mass (m) quantity of matter in a body
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DIMENSIONS AND UNITS Need to provide a quantitative means of describing the universe. 7 independent dimensions (physical quantities): 1. Mass (m) quantity of matter in a body 2. Length (l) measurement of distance
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DIMENSIONS AND UNITS Need to provide a quantitative means of describing the universe. 7 independent dimensions (physical quantities): 1. Mass (m) quantity of matter in a body 2. Length (l) measurement of distance 3. Time (t) measurement of progress of an event
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DIMENSIONS AND UNITS Need to provide a quantitative means of describing the universe. 7 independent dimensions (physical quantities): 1. Mass (m) quantity of matter in a body 2. Length (l) measurement of distance 3. Time (t) measurement of progress of an event 4. Thermodynamic temperature (T). “The condition of a body which determines the transfer of heat to or from that body”
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance”
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance” 6. Electric current (I): “Rate of transfer of electricity”
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance” 6. Electric current (I): “Rate of transfer of electricity” 7. Luminous intensity (I v ): “Rate of transfer of light energy”
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance” 6. Electric current (I): “Rate of transfer of electricity” 7. Luminous intensity (I v ): “Rate of transfer of light energy” Fundamental Property of Dimensions: Two physical quantities having different dimensions cannot be added, subtracted or equated.
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance” 6. Electric current (I): “Rate of transfer of electricity” 7. Luminous intensity (I v ): “Rate of transfer of light energy” Fundamental Property of Dimensions: Two physical quantities having different dimensions cannot be added, subtracted or equated. All other physical quantities can be expressed in terms of these fundamental dimensions
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance” 6. Electric current (I): “Rate of transfer of electricity” 7. Luminous intensity (I v ): “Rate of transfer of light energy” Fundamental Property of Dimensions: Two physical quantities having different dimensions cannot be added, subtracted or equated. All other physical quantities can be expressed in terms of these fundamental dimensions e.g. volume of a cube = l x l x l = l 3
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DIMENSIONS AND UNITS 5. Amount of substance (n). “The number of specified entities of a pure substance” 6. Electric current (I): “Rate of transfer of electricity” 7. Luminous intensity (I v ): “Rate of transfer of light energy” Fundamental Property of Dimensions: Two physical quantities having different dimensions cannot be added, subtracted or equated. All other physical quantities can be expressed in terms of these fundamental dimensions e.g. volume of a cube = l x l x l = l 3 velocity = distance/ time = l/t
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Units: Defined value of a given dimension for reference purposes
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I.
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg Length m
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg Length m Time s
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg Length m Time s Temperature K (kelvin)
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg Length m Time s Temperature K (kelvin) Amount of substance mol (mole)
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg Length m Time s Temperature K (kelvin) Amount of substance mol (mole) Current A (ampere)
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Units: Defined value of a given dimension for reference purposes Preferred system (in chemistry) is S.I. DimensionS.I. Unit Mass kg Length m Time s Temperature K (kelvin) Amount of substance mol (mole) Current A (ampere) Luminous intensity cd (candela)
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Common S.I. prefixes PrefixNameMeaning Ggiga10 9 Mmega10 6 kkilo10 3
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Common S.I. prefixes PrefixNameMeaning Ggiga10 9 Mmega10 6 kkilo10 3 ddeci10 -1 ccenti10 -2 mmilli10 -3
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Common S.I. prefixes PrefixNameMeaning Ggiga10 9 Mmega10 6 kkilo10 3 ddeci10 -1 ccenti10 -2 mmilli10 -3 micro10 -6 nnano10 -9 ppico10 -12
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Derived Units Quantity Definition Derived Unit Area Length x length m 2
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3 Density Mass/ unit volume kg m -3
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3 Density Mass/ unit volume kg m -3 Speed Distance/ unit time m s -1
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3 Density Mass/ unit volume kg m -3 Speed Distance/ unit time m s -1 Acceleration Change in speed/ m s -2 unit time
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3 Density Mass/ unit volume kg m -3 Speed Distance/ unit time m s -1 Acceleration Change in speed/ m s -2 unit time Force Mass x acceleration kg m s -2 (newton, N)
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3 Density Mass/ unit volume kg m -3 Speed Distance/ unit time m s -1 Acceleration Change in speed/ m s -2 unit time Force Mass x acceleration kg m s -2 (newton, N) Pressure Force/ unit area kg m -1 s -2 (pascal, Pa)
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Derived Units Quantity Definition Derived Unit Area Length x length m 2 Volume Area x length m 3 Density Mass/ unit volume kg m -3 Speed Distance/ unit time m s -1 Acceleration Change in speed/ m s -2 unit time Force Mass x acceleration kg m s -2 (newton, N) Pressure Force/ unit area kg m -1 s -2 (pascal, Pa) Energy Force x distance kg m 2 s -2 (joule, J )
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Difference between mass and amount of substance: amount of substance is the number of specified entities (e.g. atoms, molecules, etc.)
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Difference between mass and amount of substance: amount of substance is the number of specified entities (e.g. atoms, molecules, etc.) EntityNumber of entitiesMass (g) Hg6.02 x 10 23 atoms200.59 (= 1 mol)
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Difference between mass and amount of substance: amount of substance is the number of specified entities (e.g. atoms, molecules, etc.) EntityNumber of entitiesMass (g) Hg6.02 x 10 23 atoms200.59 (= 1 mol) KCl6.02 x 10 23 molecules74.56 (= 1 mol)
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Difference between mass and amount of substance: amount of substance is the number of specified entities (e.g. atoms, molecules, etc.) EntityNumber of entitiesMass (g) Hg6.02 x 10 23 atoms200.59 (= 1 mol) KCl6.02 x 10 23 molecules74.56 (= 1 mol) SO 4 2- 6.02 x 10 23 ions96.06 (=1 mol)
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Accuracy: measure of how close measurement is to its real value
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Precision: measure of how close successive measurements are to each other
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Accuracy: measure of how close measurement is to its real value Precision: measure of how close successive measurements are to each other X X X Precise & accurate
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Accuracy: measure of how close measurement is to its real value Precision: measure of how close successive measurements are to each other X X X X X X Precise & accurate & inaccurate
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Accuracy: measure of how close measurement is to its real value Precision: measure of how close successive measurements are to each other X X X X X X X X X Precise Precise Imprecise & accurate & inaccurate & inaccurate
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Dimensional analysis: a method of reducing physical quantities to combinations of the 7 basic dimensions
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Dimensional analysis: a method of reducing physical quantities to combinations of the 7 basic dimensions Q1. Dimensions of pressure?
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Dimensional analysis: a method of reducing physical quantities to combinations of the 7 basic dimensions Q1. Dimensions of pressure? A. Pressure = Force/Area and we already know the dimensions of force are MLt -2. Thus the dimensions of pressure are MLt -2 /L 2 = ML -1 t -2.
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Dimensional analysis: a method of reducing physical quantities to combinations of the 7 basic dimensions Q1. Dimensions of pressure? A. Pressure = Force/Area and we already know the dimensions of force are MLt -2. Thus the dimensions of pressure are MLt -2 /L 2 = ML -1 t -2. Q2. Check the validity of the following equation: PV = nR/T, given units of R to be ML 2 t -2 n -1 T -1.
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Dimensional analysis: a method of reducing physical quantities to combinations of the 7 basic dimensions Q1. Dimensions of pressure? A. Pressure = Force/Area and we already know the dimensions of force are MLt -2. Thus the dimensions of pressure are MLt -2 /L 2 = ML -1 t -2. Q2. Check the validity of the following equation: PV = nR/T, given units of R to be ML 2 t -2 n -1 T -1. A. Dimensions of L.H.S.: ML -1 t -2. L 3 = ML 2 t -2 Dimensions of R.H.S.: n. ML 2 t -2 n -1 T -1 = ML 2 t -2 T -2
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Dimensional analysis: a method of reducing physical quantities to combinations of the 7 basic dimensions Q1. Dimensions of pressure? A. Pressure = Force/Area and we already know the dimensions of force are MLt -2. Thus the dimensions of pressure are MLt -2 /L 2 = ML -1 t -2. Q2. Check the validity of the following equation: PV = nR/T, given units of R to be ML 2 t -2 n -1 T -1. A. Dimensions of L.H.S.: ML -1 t -2. L 3 = ML 2 t -2 Dimensions of R.H.S.: n. ML 2 t -2 n -1 T -1 = ML 2 t -2 T -2 Equating both sides does not cancel all terms, thus equation is invalid.
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ATOMS AND MOLECULES
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Atom:smallest particle of an element which can undergo chemical changes in a reaction
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ATOMS AND MOLECULES Atom:smallest particle of an element which can undergo chemical changes in a reaction Molecule: smallest particle of a compound which can exist and still retain the chemical properties of the compound.
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Structure of the Atom
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Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m)
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.)
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.) C atom = 2x10 -23 g = 12.000 a.m.u.
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.) C atom = 2x10 -23 g = 12.000 a.m.u. Electrical charge: neutral
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.) C atom = 2x10 -23 g = 12.000 a.m.u. Electrical charge: neutral Composition: contains electrons, protons, and, with the exception of hydrogen, neutrons.
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.) C atom = 2x10 -23 g = 12.000 a.m.u. Electrical charge: neutral Composition: contains electrons, protons, and, with the exception of hydrogen, neutrons. ParticleMass (a.m.u.)Charge e- 0.0005 -1
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.) C atom = 2x10 -23 g = 12.000 a.m.u. Electrical charge: neutral Composition: contains electrons, protons, and, with the exception of hydrogen, neutrons. ParticleMass (a.m.u.)Charge e- 0.0005 -1 p+ 1.007 +1
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Structure of the Atom Size:0.1 to 0.5 nanometers (1nm = 1x10 -9 m) Mass:H atom = 1.67x10 -24 g = 1.008 atomic mass units (a.m.u.) C atom = 2x10 -23 g = 12.000 a.m.u. Electrical charge: neutral Composition: contains electrons, protons, and, with the exception of hydrogen, neutrons. ParticleMass (a.m.u.)Charge e- 0.0005 -1 p+ 1.007 +1 n 1.009 0
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Structure of the Atom
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Size:0.1 to 0.5 nanometers (1 nm = 1 x 10 -9 m)
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Structure of the Atom Size:0.1 to 0.5 nanometers (1 nm = 1 x 10 -9 m) Electron clouds ~ 2 x 10 -10 m
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Structure of the Atom Size:0.1 to 0.5 nanometers (1 nm = 1 x 10 -9 m) Nucleus Electron clouds ~ 2 x 10 -10 m
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Structure of the Atom Size:0.1 to 0.5 nanometers (1 nm = 1 x 10 -9 m) Nucleus Electron clouds ~ 5 x 10 -15 m ~ 2 x 10 -10 m
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Structure of the Atom Size:0.1 to 0.5 nanometers (1 nm = 1 x 10 -9 m) Nucleus Electron clouds ~ 5 x 10 -15 m ~ 2 x 10 -10 m Nucleus- consists of protons and neutrons
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“Life-sized” model of the atom
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“Scaled up” electron mass Electron = 0.0005 a.m.u.Proton = 1.0070 a.m.u.
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“Life-sized” model of the atom “Scaled up” electron mass Electron = 0.0005 a.m.u.Proton = 1.0070 a.m.u. “Model proton” = 65 kg“Model electron” = 32 g
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“Life-sized” model of the atom “Scaled up” electron mass Electron = 0.0005 a.m.u.Proton = 1.0070 a.m.u. “Model proton” = 65 kg“Model electron” = 32 g “Scaled up” atomic radius Nuclear diameter = 5 x 10 -15 m Atomic diameter = 2 x 10 -10 m
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“Life-sized” model of the atom “Scaled up” electron mass Electron = 0.0005 a.m.u.Proton = 1.0070 a.m.u. “Model proton” = 65 kg“Model electron” = 32 g “Scaled up” atomic radius Nuclear diameter = 5 x 10 -15 m Atomic diameter = 2 x 10 -10 m “Model nucleus” radius = 1 m “Model atomic” radius = 40 km
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“Life-sized” model of the atom “Scaled up” electron mass Electron = 0.0005 a.m.u.Proton = 1.0070 a.m.u. “Model proton” = 65 kg“Model electron” = 32 g “Scaled up” atomic radius Nuclear diameter = 5 x 10 -15 m Atomic diameter = 2 x 10 -10 m “Model nucleus” radius = 1 m “Model atomic” radius = 40 km Q. A speck of carbon contains ca. 10 19 atoms and the diameter of a carbon atom is 1.5 x 10 -10 m. If the circumference of the earth is 40,075 km, how many times around the earth would a line of single carbon atoms extend?
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“Life-sized” model of the atom “Scaled up” electron mass Electron = 0.0005 a.m.u.Proton = 1.0070 a.m.u. “Model proton” = 65 kg“Model electron” = 32 g “Scaled up” atomic radius Nuclear diameter = 5 x 10 -15 m Atomic diameter = 2 x 10 -10 m “Model nucleus” radius = 1 m “Model atomic” radius = 40 km Q. A speck of carbon contains ca. 10 19 atoms and the diameter of a carbon atom is 1.5 x 10 -10 m. If the circumference of the earth is 40,075 km, how many times around the earth would a line of single carbon atoms extend? A. Length = 10 19 x 1.5 x 10 -10 m = 1.5 x 10 9 m. # times = 1.5 x 10 9 /40075 x 10 3 = 37.4
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Iron atoms on a copper crystal
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Iron atoms on a copper crystal Carbon monoxide molecules on platinum crystal
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Iron atoms on a copper crystal Xenon atoms on nickel Carbon monoxide molecules on platinum crystal
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Atomic number:number of protons in an atom. Symbol: Z Atomic mass: mass of an atom in a.m.u. ( number of protons + neutrons in an atom). Symbol: A
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Atomic number:number of protons in an atom. Symbol: Z Atomic mass: mass of an atom in a.m.u. ( number of protons + neutrons in an atom). Symbol: A Atome-p+nZA (a.m.u.) H11011.008 Li33437.016 C666612.000 U929214692238.05
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Conventional Notation for Chemical Symbols Cl
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Conventional Notation for Chemical Symbols Cl 35 17 - 2 Mass numberNumber and sign of charge
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Conventional Notation for Chemical Symbols Cl 35 17 - 2 Mass numberNumber and sign of charge Atomic number Number of atoms in entity
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Conventional Notation for Chemical Symbols Cl 35 17 - 2 Mass numberNumber and sign of charge Atomic number Number of atoms in entity Examples: He 4 2 OH - CO 3 2-
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Ions:atoms or molecules which have gained or lost one or more electrons Isotopes: atoms of the same element which have different masses, i.e. different numbers of neutrons
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Ions:atoms or molecules which have gained or lost one or more electrons Isotopes: atoms of the same element which have different masses, i.e. different numbers of neutrons Examples of ions:H + H - NO 3 -
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Ions:atoms or molecules which have gained or lost one or more electrons Isotopes: atoms of the same element which have different masses, i.e. different numbers of neutrons Examples of ions:H + H - NO 3 - Examples of isotopes:H 1 1 H 1 2 H 3 1 Hydrogen Deuterium Tritium
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ElementsCompounds AtomsMolecules Identical atoms
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ElementsCompounds AtomsMolecules IonsIsotopes Identical atoms ± e - ± n
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ElementsCompounds AtomsMolecules IonsIsotopes Identical atoms ± e - ± n ± e - ± n
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